The escape velocity for a body projected vertically upwards from the surface of earth is $11\;{\rm{km}}{{\rm{s}}^{ - 1}}$. If the body is projected at an angle of ${45^0}$ with the vertical, the escape velocity will be

$11\;{\rm{km}}{{\rm{s}}^{ - 1}}$

$11\;\sqrt 2 {\rm{km}}{{\rm{s}}^{ - 1}}$

$22\;{\rm{km}}{{\rm{s}}^{ - 1}}$

$11/\sqrt 2 \;{\rm{m}}{{\rm{s}}^{ - 1}}$

NEET UG PHYSICS MCQ: GRAVITATION

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Understanding +4 | -1

The escape velocity for a body projected vertically upwards from the surface of earth is

11\;\mathrm{km}{\mathrm{s}^{ - 1}}

. If the body is projected at an angle of

{45^0}

with the vertical, the escape velocity will be

View answer and explanation

Correct option: C

11\;\mathrm{km}{\mathrm{s}^{ - 1}}

Option C (

11\;\mathrm{km}{\mathrm{s}^{ - 1}}

) is correct because escape velocity is independent of the angle of projection.

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