JEE PHYSICS MCQ: GRAVITATION

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A body of mass

m

is moving in a circular orbit of radius

R

about a planet of mass

M

. At some instant, it splits into two equal masses. The first mass moves in a circular orbit of radius

\frac{R}{2}

. and the other mass, in a circular orbit of radius

\frac{3 R}{2}

. The difference between the final and initial total energies is :

View answer and explanation

Correct option: C

-\frac{G M m}{6 R}

Option C (-GMm/6R) is correct because the difference in total energies after the split is calculated by subtracting the initial energy from the sum of the final energies of the two masses.

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. If the body is projected in a direction making an angle of

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v_e

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