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NEET • PHYSICS • DUAL NATURE OF RADIATION AND MATTER

Dual nature of radiation and matter practice · Mixed difficulty

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61 Medium
61 of 130
Application +4 | -1
An electron is accelerated through a potential difference of VV volt. The speed of electrons will be
View answer and explanation
Correct option: B
2eVm\sqrt {\frac{{2eV}}{m}}
Option B (2eVm\sqrt {\frac{{2eV}}{m}}) is correct because it is derived from equating the kinetic energy gained by the electron to the work done by the potential difference.
62 Hard
62 of 130
Application +4 | -1
A beam of 10.6 eV10.6 \mathrm{~eV} photons of intensity 2.0 W/m22.0 \mathrm{~W} / \mathrm{m}^2 falls on a platinum surface of area 1.0×10−4 m21.0 \times 10^{-4} \mathrm{~m}^2 and work function 5.6 eV5.6 \mathrm{~eV}. If 0.53%0.53 \% of the incident photons eject photo electrons, then find the number of photoelectrons emitter per second and maximum energy of ejected electrons (in eV\mathrm{eV}) are
View answer and explanation
Correct option: A
6.25×1011,5 eV6.25 \times 10^{11}, 5 \mathrm{~eV}
Option A (6.25×1011,5 eV6.25 \times 10^{11}, 5 \text{ eV}) is correct because it accurately calculates the number of photoelectrons emitted per second and the maximum kinetic energy of the ejected electrons.
63 Hard
63 of 130
Understanding +4 | -1
Relation between the stopping potential V0{V_0} of a metal and the maximum velocity v of the photoelectron is
View answer and explanation
Correct option: A
V0∝V2{V_0} \propto {V^2}
Option A (V0∝V2{V_0} \propto {V^2}) is correct because the stopping potential is related to the maximum kinetic energy of the photoelectrons, which is proportional to the square of their velocity.
64 Hard
64 of 130
Application +4 | -1
Wave equation of light used in PEE at a given point is given by E=E0[sin⁡5ωt+cos⁡15ωt]\mathrm{E}=\mathrm{E}_0[\sin 5 \omega \mathrm{t}+\cos 15 \omega \mathrm{t}] here t\mathrm{t} is instant, If work function of electron emitter is ϕ\phi then value of stopping potential will be:-
View answer and explanation
Correct option: B
he(15ω2π)−ϕe\frac{\mathrm{h}}{\mathrm{e}}\left(\frac{15 \omega}{2 \pi}\right)-\frac{\phi}{\mathrm{e}}
Option B (he(15ω2π)−ϕe\frac{\mathrm{h}}{\mathrm{e}}\left(\frac{15 \omega}{2 \pi}\right)-\frac{\phi}{\mathrm{e}}) is correct because the stopping potential is determined by the highest frequency component of the incident light, which is 15ω15\omega.
65 Medium
65 of 130
Analyzing +4 | -1
Assertion: Two sources of equal intensity always emit equal number of photons in any time interval.

Reason: Two sources of equal intensity may emit equal number of photons in any time interval.
View answer and explanation
Correct option: D
Assertion is incorrect, reason is correct.
Option D is correct because the assertion is false, as intensity depends on both the number of photons and their energy, while the reason is true as equal intensity does not guarantee an equal number of photons due to frequency differences.
66 Easy
66 of 130
Application +4 | -1
In photoelectric experiment energy of 2.48 eV2.48 \mathrm{~eV} irradiates a photo sensitive material. The stopping potential was measured to be 0.5 V0.5 \mathrm{~V}. Work function of the photo sensitive material is :
View answer and explanation
Correct option: D
1.98 eV1.98 \mathrm{~eV}
Option D (1.98 eV1.98 \mathrm{~eV}) is correct because the work function can be calculated by subtracting the stopping potential energy from the incident photon energy.
67 Hard
67 of 130
Application +4 | -1
Find the typical de Broglie wavelength associated with a HeHe atom in helium gas at room temperature (27∘C)\left(27^{\circ} \mathrm{C}\right) and 1 atm1 \mathrm{~atm} pressure?
View answer and explanation
Correct option: A
0.73×10−10 m,3.4×10−9 m0.73 \times 10^{-10} \mathrm{~m}, 3.4 \times 10^{-9} \mathrm{~m}
Option A (0.73×10−10 m,3.4×10−9 m0.73 \times 10^{-10} \mathrm{~m}, 3.4 \times 10^{-9} \mathrm{~m}) is correct because it is calculated using the de Broglie wavelength formula with average kinetic energy at the given temperature.
68 Medium
68 of 130
Understanding +4 | -1
If nR{n_R} and nV{n_V} denote the number of photons emitted by a red bulb and violet bulb of equal power in a given time, then
View answer and explanation
Correct option: B
nR>nV{n_R} > {n_V}
Option B (nR>nV{n_R} > {n_V}) is correct because red light has a lower frequency (and thus lower energy per photon) than violet light, so more red photons are needed to achieve the same power.
69 Medium
69 of 130
Application +4 | -1
The threshold frequency for a certain photosensitive metal is υ0{\upsilon _0} When it is illuminated by light of frequency υ=2υ0\upsilon = 2{\upsilon _0},the maximum velocity of photoelectrons is v0{v_0}. What will be the maximum velocity of the photoelectrons when the same metal is illuminated by light of frequency υ=5υ0\upsilon = 5{\upsilon _0} ?
View answer and explanation
Correct option: B
2v02{v_0}
Option B (2v02{v_0}) is correct because the maximum velocity is proportional to the square root of the frequency difference from the threshold frequency.
70 Hard
70 of 130
Analyzing +4 | -1
Hydrogen gas in the atomic state is excited to an energy level such that the electrostatic potential energy of hydrogen atom becomes -1.7 eV. Now a photoelectric plate having work function 2.3 eV is exposed to the emission spectra of this gas. Assuming all the transitions to be possible, find the minimum de-Broglie wavelength of the ejected photoelectrons in A∘\mathop {\text{A}}\limits^ \circ to the nearest integer.
View answer and explanation
Correct option: A
4
Option A (4) is correct because the maximum energy of the emitted photon corresponds to the transition from n=2 to n=1, and this energy, minus the work function, gives the maximum kinetic energy of the photoelectron, from which the de Broglie wavelength can be calculated.
71 Medium
71 of 130
Application +4 | -1
An oil drop with charge qq is held stationary between two plates with an external potential difference of 400 V. If the size of the drop is doubled without any change of charge, the potential difference required to keep the drop stationary will be
View answer and explanation
Correct option: C
3200 V
Option C (3200 V) is correct. The electric field must remain constant to keep the drop stationary, and since the weight increases by a factor of 8, the electric force must also increase by a factor of 8, requiring an 8x increase in potential difference.
72 Easy
72 of 130
Application +4 | -1
de-Broglie wavelength of a proton and an electron is same. The ratio of kinetic energy of electron to that of proton is
View answer and explanation
Correct option: B
1835
Option B (1835) is correct because the ratio of kinetic energies is equal to the ratio of masses when de-Broglie wavelengths are the same.
73 Medium
73 of 130
Analyzing +4 | -1
Assertion (A): Work function of aluminium is 4.2 eV. Emission of electron will not be possible if two photons each of energy 2.5 eV strike an electron of a aluminium.
Reason (R): For photoelectron emission the energy of each photon should be greater than the work function of metal.
View answer and explanation
Correct option: A
Both A and R are true and R is the correct explanation of A
Option A (Both A and R are true and R is the correct explanation of A) is correct because the work function must be exceeded by the energy of a single photon for photoelectric emission.
74 Medium
74 of 130
Analyzing +4 | -1
A photon, an electron and a uranium nucleus all have the same wavelength. The one with the most energy
View answer and explanation
Correct option: A
Is the photon
Option D (None, all have same length) is correct because the de-Broglie wavelength is inversely proportional to momentum, and since all have the same momentum, their wavelengths are equal.
75 Medium
75 of 130
Analyzing +4 | -1
For a body moving with relativistic speed, if the velocity is doubled, then
View answer and explanation
Correct option: A
Its linear momentum is doubled
Option C (Its linear momentum will be more than double) is correct because relativistic momentum increases more rapidly than velocity at high speeds.
76 Medium
76 of 130
Application +4 | -1
An electron is accelerated by a potential difference of V volt to acquire kinetic energy equal to maximum kinetic energy of ejected photoelectron from a metal of work function 3.2 eV, using a light of wavelength 2000 A∘ 2000\,\mathop \mathrm{A}\limits^ \circ \, Value of V is
View answer and explanation
Correct option: C
3 volt
Option C (3 volt) is correct because the accelerating potential V equals the maximum kinetic energy of the ejected photoelectron, which is calculated using the photoelectric effect equation.
77 Medium
77 of 130
Application +4 | -1
A broken ligament is being ‘welded’ back in place using 20 ms pulses from a 0.5 W laser operating at a wavelength of 632 nm. The number of photons in 5 pulses of laser are
View answer and explanation
Correct option: C
1.59×10231.59 \times {10^{23}}
Option C (1.59×10231.59 \times {10^{23}}) is correct because it is the number of photons calculated from the total energy of the laser pulses.
78 Medium
78 of 130
Application +4 | -1
The ratio transmitter operates on a wavelength of 1500 m at a power of 400 kW. The energy of radio photon (in joule) is
View answer and explanation
Correct option: B
1.32×10−281.32 \times {10^{ - 28}}J
Option B (1.32×10−281.32 \times {10^{ - 28}}J) is correct because it is calculated using the formula E=hcλE = \frac{{hc}}{\lambda}.
79 Easy
79 of 130
Remembering +4 | -1
Kinetic mass of photon is
View answer and explanation
Correct option: B
hv/c2h v / c^2
Option B (hv/c2h v / c^2) is correct because it represents the kinetic mass of a photon derived from the energy-mass equivalence principle.
80 Medium
80 of 130
Understanding +4 | -1
The mean free path of the electrons in a discharge tube is 20 cm. The length of the tube is 15 cm only. Then length of Crooke’s dark space is
View answer and explanation
Correct option: C
15 cm
Option C (15 cm) is correct because the Crooke's dark space length cannot exceed the tube length.
81 Medium
81 of 130
Remembering +4 | -1
The special theory of relativity is based on the frame of reference which has constant?
View answer and explanation
Correct option: B
Speed
Option B (Speed) is correct because the special theory of relativity is based on inertial frames of reference, which move at a constant speed.
82 Medium
82 of 130
Remembering +4 | -1
Photo cell is a device to
View answer and explanation
Correct option: B
Measure light intensity
Option B (Measure light intensity) is correct because photocells are designed to generate a current proportional to the incident light intensity.
83 Medium
83 of 130
Understanding +4 | -1
The de-Broglie wavelength λ\lambda associated with an electron having kinetic energy EE is given by the expression
View answer and explanation
Correct option: A
h2mE\frac{h}{{\sqrt {2mE} }}
Option A is correct because the de Broglie wavelength is given by λ = h/sqrt(2mE), where E is the kinetic energy.
84 Medium
84 of 130
Understanding +4 | -1
When light falls on a metal surface, the maximum kinetic energy of the emitted photo-electrons depends upon
View answer and explanation
Correct option: B
Frequency of the incident light
Option B (Frequency of the incident light) is correct because the maximum kinetic energy of photoelectrons depends on the frequency of the incident light, as described by the photoelectric equation.
85 Medium
85 of 130
Analyzing +4 | -1
If alpha, beta and gamma rays carry same momentum, which has the longest wavelength?
View answer and explanation
Correct option: D
None, all have same length
Option A (Neutron, same, neutron) is correct because the neutron has a larger mass, resulting in a shorter wavelength for the same kinetic energy or speed.
86 Hard
86 of 130
Application +4 | -1
A proton is accelerated through a potential difference of 400 V400 \mathrm{~V} to have same de-Broglie wavelength what potential difference must be applied across doubly ionised 8O16{ }_8 {O}^{16} atom:
View answer and explanation
Correct option: B
12.5 volt
Option B (12.5 volt) is correct because the potential difference is inversely proportional to the charge and mass to maintain the same de-Broglie wavelength.
87 Medium
87 of 130
Remembering +4 | -1
The magnitude of saturation photoelectric current depends upon
View answer and explanation
Correct option: B
Intensity
Option B (Intensity) is correct because the saturation photoelectric current is directly proportional to the intensity of the incident light.
88 Medium
88 of 130
Remembering +4 | -1
The minimum energy required to eject an electron, from the metal surface is called
View answer and explanation
Correct option: D
Work function
Option D (Work function) is correct because the work function is the minimum energy required to eject an electron from a metal surface.
89 Medium
89 of 130
Application +4 | -1
In a photocell bichromatic light of wavelength 2475A∘2475\mathop A\limits^ \circ and 6000  A∘6000\;\mathop A\limits^ \circ are incident on cathode whose work function is 4.8  eV.4.8\;eV. If a uniform magnetic field of 3×10−5tesla3 \times {10^{ - 5}}tesla exists parallel to the plate, the radius of the path described by the photoelectron will be (mass of electron =9×10−31kg= 9 \times {10^{ - 31}}kg)
View answer and explanation
Correct option: B
5  cm5\;cm
Option B (5  cm5\;cm) is correct because it is the radius of the path described by the photoelectron, calculated using the maximum kinetic energy and the magnetic field.
90 Medium
90 of 130
Remembering +4 | -1
G. P. Thomson experimentally confirmed the existence of matter waves by the phenomenon
View answer and explanation
Correct option: B
Refraction
Option A is correct because G.P. Thomson experimentally confirmed the existence of matter waves through the phenomenon of diffraction.
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