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NEET • PHYSICS • DUAL NATURE OF RADIATION AND MATTER

Dual nature of radiation and matter practice · Mixed difficulty

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121 Medium
121 of 130
Analyzing +4 | -1
Assertion: In process of photoelectric emission, all emitted electrons do not have same kinetic energy.

Reason: If radiation falling on photosensitive surface of a metal consists of different wavelength then energy acquired by electrons absorbing photons of different wavelengths shall be different.
View answer and explanation
Correct option: B
Assertion is correct, reason is correct; reason is not a correct explanation for assertion
Option B (Assertion is correct, reason is correct; reason is not a correct explanation for assertion) is correct because both statements are true, but the reason doesn't directly explain the assertion.
122 Easy
122 of 130
Application +4 | -1
A particle at rest disintegrates into two fragments of masses in the ratio of 1: 2 having non-zero velocities. The ratio of the de-Broglie wavelength of the lighter particle to that of the heavier particle is
View answer and explanation
Correct option: A
1
Option A (1) is correct because, due to conservation of momentum, the magnitudes of the momenta of the two fragments are equal, resulting in equal de Broglie wavelengths.
123 Easy
123 of 130
Understanding +4 | -1
Statement-1: Photoelectric effect establishes quantum nature of light.
Statement-2: There is negligible time lag between photon collisions with the material and photoelectron emission irrespective of intensity of incident light. (Assume incident light is of frequency greater than threshold frequency of the material).
View answer and explanation
Correct option: A
Statement-1 is true, Statement-2 is true, Statement-2 is the correct explanation for Statement-1
Option A (Statement-1 is true, Statement-2 is true, Statement-2 is the correct explanation for Statement-1) is correct because the instantaneous emission of photoelectrons, regardless of intensity, demonstrates the particle nature of light.
124 Medium
124 of 130
Understanding +4 | -1
The work function of a metal is W0{W_0} and λ\lambda is wavelength of incident radiation. There is no emission of photoelectron when
View answer and explanation
Correct option: D
λ>hcW0\lambda > \frac{{hc}}{{{W_0}}}
Option D (λ>hcW0\lambda > \frac{{hc}}{{{W_0}}}) is correct because for no photoemission to occur, the wavelength of the incident radiation must be greater than the threshold wavelength.
125 Medium
125 of 130
Analyzing +4 | -1
While doing his experiment, Millikan one day observed the following charges on a single drop
(i)6.563×10−19C6.563 \times {10^{ - 19}}C (ii) 8.204×10−19C8.204 \times {10^{ - 19}}C
(iii)11.50  ×10−19C  11.50\; \times {10^{ - 19}}C\; (iv)13.13×10−19C13.13 \times {10^{ - 19}}C
(v)16.48×10−19C    16.48 \times {10^{ - 19}}C\;\; (vi)18.09×10−19C18.09 \times {10^{ - 19}}C
From this data the value of the elementary charge (e)\left( e \right) was found to be
View answer and explanation
Correct option: A
1.641×10−19C1.641 \times {10^{ - 19}}C
Option A (1.641×10−19C1.641 \times {10^{ - 19}}C) is correct because it is the approximate elementary charge found by calculating the greatest common divisor of the observed charges.
126 Medium
126 of 130
Application +4 | -1
The temperature at which protons in proton gas would have enough energy to overcome Coulomb barrier of 4.14×10−144.14 \times {10^{ - 14}} J is (Boltzmann constant
=1.38×10−23  JK−1)  \times {10^{ - 23}}\;\mathrm{J}{\mathrm{K}^{ - 1}})\mathrm{\;}
View answer and explanation
Correct option: A
2×1092 \times {10^9} K
Option A (2×1092 \times {10^9} K) is correct because it is calculated using the formula E=32kTE = \frac{3}{2}kT.
127 Medium
127 of 130
Remembering +4 | -1
Which of the following is not the property of a cathode ray
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Correct option: D
It does not deflect in electric field
Option D (It does not deflect in electric field) is correct because cathode rays are streams of electrons, which are negatively charged particles, and thus deflect in an electric field.
128 Medium
128 of 130
Remembering +4 | -1
Positive rays were discovered by
View answer and explanation
Correct option: B
Goldstein
Option B (Goldstein) is correct because Eugen Goldstein is credited with the discovery of positive rays (also known as canal rays).
129 Medium
129 of 130
Understanding +4 | -1
When ultraviolet radiation is incident on a surface, no photoelectrons are emitted. If a second beam causes photoelectrons to be ejected, it may consist of
View answer and explanation
Correct option: B
X-rays
Option B (X-rays) is correct because X-rays have higher energy and frequency than ultraviolet radiation, allowing them to eject photoelectrons when UV radiation fails.
130 Medium
130 of 130
Application +4 | -1
Two identical metal plates shown photoelectric effect by a light of wavelength λA∘\lambda \mathop A\limits^ \circ falls on plate A and λB{\lambda _B} on plate B(λA=2λB).B\left( {{\lambda _A} = 2{\lambda _B}} \right). The maximum kinetic energy is
View answer and explanation
Correct option: B
KA<KB/2{K_A} < {K_B}/2
Option B (KA<KB/2{K_A} < {K_B}/2) is correct because the kinetic energy is inversely proportional to the wavelength, and the wavelength of A is twice that of B.
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