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NEET • CHEMISTRY • SOME BASIC CONCEPTS OF CHEMISTRY

Some basic concepts of chemistry practice · Mixed difficulty

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121 Medium
121 of 313
Remembering +4 | -1
The equivalent weight of an element can be calculated from:
View answer and explanation
Correct option: A
6.4 divided by specific heat and valence
Option A is correct because the equivalent weight is related to the Dulong-Petit law (6.4/specific heat) and valence.
122 Hard
122 of 313
Application +4 | -1
What weight of HNO3\mathrm{HN}{\mathrm{O}_3} is required to make 1 litre of 2 N solution to be used as an oxidising agent in the reaction? 3Cu+8HNO3→3Cu(NO3)2+2NO+4H2O3\mathrm{Cu} + 8\mathrm{HN}{\mathrm{O}_3} \to 3\mathrm{Cu}{\left( {\mathrm{N}{\mathrm{O}_3}} \right)_2} + 2\mathrm{NO} + 4{\mathrm{H}_2}\mathrm{O}
View answer and explanation
Correct option: C
42 g
Option C (42 g) is correct because it is the mass of HNO3 needed to prepare 1 litre of 2N solution, considering its role as an oxidizing agent.
123 Easy
123 of 313
Application +4 | -1
Equivalent weight of a bivalent metal is 37.2. The molecular weight of its chloride is
View answer and explanation
Correct option: C
145.4145.4
Option C (145.4) is correct because it is calculated by finding the atomic weight of the metal and then adding the weight of two chlorine atoms.
124 Hard
124 of 313
Analyzing +4 | -1
A crystalline hydrated salt on being heated loses 45.6%45.6 \% of its weight. Percentage composition of anhydrous salt is AlAl - 10.5%,K−15.1%10.5 \%, {K}-15.1 \%, S−24.8%, O−49.6%S-24.8 \%,\, {O}-49.6 \%. Find molecular formula of salt (hydrated) (M=948 g/mol({M}=948 \mathrm{~g} / \mathrm{mol} for hydrated salt).
View answer and explanation
Correct option: A
K2SO4⋅Al2(SO4)3⋅24H2O{K}_2 {SO}_4 \cdot {Al}_2\left({SO}_4\right)_3 \cdot 24 {H}_2 {O}
Option A (K2SO4⋅Al2(SO4)3⋅24H2O{K}_2 {SO}_4 \cdot {Al}_2\left({SO}_4\right)_3 \cdot 24 {H}_2 {O}) is correct because the calculated mole ratio of K2SO4:Al2(SO4)3:H2O is approximately 1:1:24, matching the formula.
125 Easy
125 of 313
Application +4 | -1
The number of equivalent per mole of H2S{\mathrm{H}_2}\mathrm{S} used in its oxidation to SO2\mathrm{S}{\mathrm{O}_2} is :
View answer and explanation
Correct option: B
6
Option B (6) is correct because in the oxidation of H2SH_2S to SO2SO_2, sulfur changes its oxidation state from -2 to +4, which is a change of 6.
126 Hard
126 of 313
Analyzing +4 | -1
If average molecular wt. of air is 29 , then assuming N2\mathrm{N}_2 and O2\mathrm{O}_2 gases are there which options are correct regarding composition of air:

(i) 75%75 \% by mass of N2\mathrm{N}_2

(ii) 75%75 \% by moles N2\mathrm{N}_2

(iii) 72.41%72.41 \% by mass of N2\mathrm{N}_2
View answer and explanation
Correct option: C
both (ii) and (iii) are correct
Option C is correct because the mole percentage of N2 is approximately 75%, and the mass percentage is approximately 72.41%.
127 Easy
127 of 313
Remembering +4 | -1
When a solid vaporizes directly without melting, it is known as:
View answer and explanation
Correct option: B
Sublimation
Option B (Sublimation) is correct because sublimation is the process where a solid transitions directly into a gas phase without passing through the liquid phase.
128 Easy
128 of 313
Application +4 | -1
100 mL of 0.1 M solution of a reductant is diluted to 1 litre, which of the following changes?
View answer and explanation
Correct option: A
Molarity
Option A (Molarity) is correct because dilution changes the concentration (molarity) of the solution, while the number of millimoles and milliequivalents of the solute remain constant.
129 Medium
129 of 313
Application +4 | -1
6.90 grams of metal carbonate was completely decomposed by 50 ml of 2N HCl. The equivalent weight of metal is
View answer and explanation
Correct option: A
39
Option A (39) is correct because the equivalent weight of the metal is calculated using the formula: Equivalent weight of metal carbonate = Equivalent weight of metal + Equivalent weight of carbonate. From the reaction with HCl, we can find the equivalent weight of the metal carbonate, and then solve for the equivalent weight of the metal.
130 Hard
130 of 313
Understanding +4 | -1
Assertion: The atomic mass of an element is given by Dulong-Petit's law: atomic mass ×\times sp. heat (cal/mol)≃6.4(\mathrm{cal} / \mathrm{mol}) \simeq 6.4.
Reason: The formula is valid for metals only and not for all elements.
View answer and explanation
Correct option: B
Assertion is wrong but Reason is correct
Option B (Assertion is wrong but Reason is correct) is correct because Dulong-Petit's law provides an approximate atomic mass and is primarily applicable to metals.
131 Medium
131 of 313
Analyzing +4 | -1
Which of the following pairs contains equal number of atoms?
View answer and explanation
Correct option: A
11.2 cc (STP) of nitrogen and 0.015 g of nitric oxide
Option A (11.2 cc (STP) of nitrogen and 0.015 g of nitric oxide) is correct because both contain approximately the same number of atoms.
132 Easy
132 of 313
Analyzing +4 | -1
Assertion : A certain element XX, forms three binary compounds with chlorine containing 59.68%,68.95%59.68 \%, 68.95 \% and 74.75%74.75 \% chlorine respectively. These data illustrate the law of multiple proportions.

Reason : According to law of multiple proportions, the relative amounts of an element combining with some fixed amount of a second element in a series of compounds are the ratios of small whole numbers.
View answer and explanation
Correct option: A
If both assertion and reason are true and the reason is the correct explanation of the assertion.
Option A is correct. The assertion is true because the given data illustrates the law of multiple proportions. The reason is also true and provides the correct explanation of the assertion.
133 Medium
133 of 313
Understanding +4 | -1
Which mode of expressing concentration is independent of temperature?
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because molality, percent by weight, and mole fraction are all based on mass or moles, which are independent of temperature.
134 Medium
134 of 313
Remembering +4 | -1
Which of the following is an SI unit?
View answer and explanation
Correct option: B
Mole
Option B (Mole) is correct because the mole is the SI unit for the amount of substance.
135 Easy
135 of 313
Application +4 | -1
Cortisone is a molecular substance containing 21 atoms of carbon per molecule. The molecular weight of cortisone is 360.4. what is the percentage of carbon in cortisone?
View answer and explanation
Correct option: C
69.98%69.98\%
Option C (69.98%69.98\%) is correct because it represents the percentage of carbon in cortisone, calculated from the number of carbon atoms and the molecular weight.
136 Medium
136 of 313
Understanding +4 | -1
One mole of   CO2\;\mathrm{C}{\mathrm{O}_2} contains:
View answer and explanation
Correct option: A
6.02×1023atoms  of  C6.02 \times {10^{23}}\mathrm{atoms}\;\mathrm{of}\;\mathrm{C}
Option A (6.02×1023atoms  of  C6.02 \times {10^{23}}\mathrm{atoms}\;\mathrm{of}\;\mathrm{C}) is correct because one mole of any substance contains Avogadro's number of entities, and in one mole of CO2CO_2 there is one mole of C atoms.
137 Easy
137 of 313
Remembering +4 | -1
Molecular mass is defined as the
View answer and explanation
Correct option: C
Mass of one molecule of any substance compared with the mass of one atom of C-12
Option C (Mass of one molecule of any substance compared with the mass of one atom of C-12) is correct because molecular mass is defined relative to the mass of a C-12 atom.
138 Medium
138 of 313
Remembering +4 | -1
The prefix 1018{10^{18}} is
View answer and explanation
Correct option: C
exa
Option C is correct because the prefix 'exa' corresponds to the power of 1018.
139 Medium
139 of 313
Understanding +4 | -1
In alkaline medium, the reduction of permanganate anion involves a gain of_____electrons.
View answer and explanation
Correct option: A
3
Option A (3) is correct because in alkaline medium, permanganate (MnO4-) is reduced to MnO2, which involves a gain of 3 electrons (Mn+7 to Mn+4).
140 Easy
140 of 313
Remembering +4 | -1
Which represents per cent by weight?
View answer and explanation
Correct option: A
wt.  of  solutewt.  of  solution×100\frac{{\mathrm{wt}\mathrm{. }\;\mathrm{of}\;\mathrm{ solute}}}{{\mathrm{wt}\mathrm{. }\;\mathrm{of}\;\mathrm{ solution}}} \times 100
Option A (wt.  of  solutewt.  of  solution×100\frac{{\mathrm{wt}\mathrm{. }\;\mathrm{of}\;\mathrm{ solute}}}{{\mathrm{wt}\mathrm{. }\;\mathrm{of}\;\mathrm{ solution}}} \times 100) is correct because percent by weight is defined as the weight of solute divided by the weight of solution, multiplied by 100.
141 Easy
141 of 313
Remembering +4 | -1
The prefix zepto stands for (in m)
View answer and explanation
Correct option: D
10−21{10^{ - 21}}
Option D is correct because the prefix zepto represents 10-21.
142 Medium
142 of 313
Remembering +4 | -1
Among the following statements, that which was not proposed by Dalton was
View answer and explanation
Correct option: B
when gases combine or reproduced in a chemical reaction they do so in a simple ratio by volume provided all gases are at the same T and P.
Option B (when gases combine or reproduced in a chemical reaction they do so in a simple ratio by volume provided all gases are at the same T and P) is correct because this statement describes Gay-Lussac's Law of Gaseous Volumes, which was not proposed by Dalton.
143 Medium
143 of 313
Analyzing +4 | -1
Which of the following reactions is not correct according to the law of conservation of mass.
View answer and explanation
Correct option: B
C3H8(g)+O2(g)→CO2(g)+H2O(g){C_3}{H_8}\left( g \right) + {O_2}\left( g \right) \to C{O_2}\left( g \right) + {H_2}O\left( g \right)
Option A is the correct answer because the reaction is not balanced, violating the law of conservation of mass. The number of Mg and O atoms are not equal on both sides.
144 Medium
144 of 313
Application +4 | -1
A 10g sample of CaCO3CaC{O_3} with 80% purity was heated to a constant weight volume of CO2C{O_2} gas liberated under STP conditions is approximately
View answer and explanation
Correct option: D
1.8 L
Option D (1.8 L) is correct because it is calculated based on the stoichiometry of the decomposition reaction and the purity of the sample.
145 Easy
145 of 313
Understanding +4 | -1
With increase of temperature, which of these changes?
View answer and explanation
Correct option: C
Molarity
Option C (Molarity) is correct because molarity is defined as moles of solute per liter of solution, and the volume of a solution changes with temperature.
146 Medium
146 of 313
Understanding +4 | -1
How many mole of atoms are in a mole of CH3COOH\mathrm{C}{\mathrm{H}_3}\mathrm{COOH} molecule?
View answer and explanation
Correct option: A
2 moles of C atoms, 4 moles of H atoms, 2 moles of O atoms
Option A is correct because one mole of CH3COOH contains 2 moles of C atoms, 4 moles of H atoms, and 2 moles of O atoms.
147 Easy
147 of 313
Remembering +4 | -1
Dulong and Petit’s law is valid only for
View answer and explanation
Correct option: D
Solid elements
Option D is correct because Dulong and Petit's law is valid only for solid elements at sufficiently high temperatures.
148 Hard
148 of 313
Analyzing +4 | -1
Assertion:- Law of conservation of mass hold good for nuclear reaction.

Reason:- Law states that mass can be neither created nor destroyed in a chemical reaction.
View answer and explanation
Correct option: D
If both Assertion & Reason are False
Option D (If both Assertion & Reason are False) is correct because the law of conservation of mass does not strictly hold for nuclear reactions due to mass-energy equivalence, and the reason is only applicable to chemical reactions.
149 Medium
149 of 313
Application +4 | -1
What weight of HNO3\mathrm{HN}{\mathrm{O}_3} is needed to convert 5 g of iodine into iodic acid according to the reaction, I2+HNO3→HIO3+NO2+H2O?{\mathrm{I}_2} + \mathrm{HN}{\mathrm{O}_3} \to \mathrm{HI}{\mathrm{O}_3} + \mathrm{N}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O}? ?
View answer and explanation
Correct option: A
12.4 g
Option A (12.4 g) is correct because it is the correct mass of HNO3 needed based on the balanced equation and stoichiometry.
150 Medium
150 of 313
Application +4 | -1
A gaseous mixture contains oxygen and nitrogen in the ratio of 1:41:4 by weight. Therefore, the ratio of their number of molecules is:
View answer and explanation
Correct option: C
7:87:8
Option C (7:87:8) is correct because the ratio of the number of molecules is calculated based on the molar masses and given weight ratio.
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