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NEET • CHEMISTRY • SOME BASIC CONCEPTS OF CHEMISTRY

Some basic concepts of chemistry practice · Mixed difficulty

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91 Medium
91 of 313
Remembering +4 | -1
Law of constant composition is same as the law of
View answer and explanation
Correct option: D
Definite proportion
Option D (Definite proportion) is correct because the law of constant composition is another name for the law of definite proportions, stating that a chemical compound always contains the same elements in the same proportions by mass.
92 Easy
92 of 313
Analyzing +4 | -1
Which one of the following is not a redox reaction
View answer and explanation
Correct option: A
CaCO3→CaO+CO2CaC{O_3} \to CaO + C{O_2}
Option A (CaCO3→CaO+CO2CaC{O_3} \to CaO + C{O_2}) is correct because there is no change in oxidation state of any element in this reaction.
93 Easy
93 of 313
Application +4 | -1
The Largest number of molecules is in
View answer and explanation
Correct option: A
36 g of water
Option A (36 g of water) is correct because it contains the largest number of moles, and therefore the largest number of molecules.
94 Hard
94 of 313
Understanding +4 | -1
Any quantitative observation or measurement is represented by AA followed by BB in which it is measured. AA and BB respectively are
View answer and explanation
Correct option: C
A→A \rightarrow number, B→B \rightarrow units
Option C (A→A \rightarrow number, B→B \rightarrow units) is correct because any quantitative measurement consists of a numerical value followed by the unit of measurement.
95 Easy
95 of 313
Understanding +4 | -1
The number of significant figures in 10.3106 g is
View answer and explanation
Correct option: D
6
Option D is correct because all non-zero digits are significant, and zeros between non-zero digits are also significant, resulting in 6 significant figures.
96 Hard
96 of 313
Analyzing +4 | -1
One mole of mixture of N2,NO2\mathrm{N}_2, \mathrm{NO}_2 and N2O4\mathrm{N}_2 \mathrm{O}_4 has a mean molar mass of 55.4 g.55.4 \mathrm{~g}. On heating to a temperature, at which all the N2O4\mathrm{N}_2 \mathrm{O}_4 is dissociated into NO2,\mathrm{NO}_2, the mean molar mass tends to a lower value of 39.6 g.39.6 \mathrm{~g}. What is the mole ratio of N2,NO2\mathrm{N}_2, \mathrm{NO}_2 and N2O4\mathrm{N}_2 \mathrm{O}_4 in the original mixture?
View answer and explanation
Correct option: A
5:1:45: 1: 4
Option A is correct because the mole ratio of N2, NO2, and N2O4 in the original mixture is 5:1:4.
97 Medium
97 of 313
Understanding +4 | -1
The oxidation number and covalency of sulphur in the sulphur molecule (S8)\left( {{S_8}} \right) are respectively :
View answer and explanation
Correct option: A
0 and 2
Option A (0 and 2) is correct because in S8, each sulfur atom is covalently bonded to two other sulfur atoms, and the oxidation number of an element in its elemental form is zero.
98 Medium
98 of 313
Analyzing +4 | -1
Assertion: Components of a homogeneous mixture cannot be separated by using physical methods.

Reason: Composition of homogeneous mixture is uniform throughout as the components react to form a single compound.
View answer and explanation
Correct option: D
If both assertion and reason is false
Option D (If both assertion and reason is false) is correct because homogeneous mixtures can be separated by physical methods, and their composition is uniform without chemical reaction.
99 Easy
99 of 313
Understanding +4 | -1
Choose correct option based on following statements. Here T stands for true statement and F for false statement.
(i) Homogeneous mixture has uniform composition throughout.
(ii) All components of a heterogeneous mixture are observable to naked eyes.
(iii) All solutions are homogeneous in nature.
(iv) Air is an example of heterogeneous mixture.
View answer and explanation
Correct option: B
TFTF
Option B is correct because (i) is true, (ii) is false, (iii) is true, and (iv) is false based on the definitions of homogeneous and heterogeneous mixtures.
100 Medium
100 of 313
Analyzing +4 | -1
Statement-I: 12 parts by mass of carbon in CO\mathrm{CO} and CO2\mathrm{CO}_2 molecules combine with 16 and 32 parts by mass of oxygen.

Statement-II: A given compound always contains exactly the same proportion of elements by weight.
View answer and explanation
Correct option: B
Both statement I and II are incorrect
Option B is correct because both statements are incorrect. Statement I violates the law of multiple proportions, and Statement II describes the law of definite proportions, but it's misstated.
101 Medium
101 of 313
Analyzing +4 | -1
Which is not a redox reaction?
View answer and explanation
Correct option: B
CaCO3(s)→CaO(s)+CO2(g)CaC{O_{3(s)}} \to Ca{O_{(s)}} + C{O_{2(g)}}
Option B (CaCO3(s)→CaO(s)+CO2(g)CaC{O_{3(s)}} \to Ca{O_{(s)}} + C{O_{2(g)}}) is not a redox reaction because the oxidation states of all elements remain unchanged during the reaction.
102 Easy
102 of 313
Understanding +4 | -1
One mole electron means:
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because 1 mole of electrons contains Avogadro's number of electrons, which has a mass of approximately 0.55 mg.
103 Easy
103 of 313
Application +4 | -1
The number of Na atoms in 46 g ‘Na”
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Correct option: D
12.046  ×  102312.046{\mkern 1mu} {\mkern 1mu} \times {\mkern 1mu} {\mkern 1mu} {10^{23}}
Option D (12.046  ×  102312.046{\mkern 1mu} {\mkern 1mu} \times {\mkern 1mu} {\mkern 1mu} {10^{23}}) is correct because 46g of Na is 2 moles of Na, and therefore contains 2 times Avogadro's number of atoms.
104 Medium
104 of 313
Understanding +4 | -1
If Avogadro number NA{\mathrm{N}_\mathrm{A}} , is changed from 6.022×1023 mol−1 to 6.022×1020 mol−16.022 \times {10^{23}}\,mo{l^{ - 1}}\,to\,6.022 \times {10^{20}}\,mo{l^{ - 1}} , this would change:
View answer and explanation
Correct option: D
The mass of one mole of carbon
Option D (The mass of one mole of carbon) is correct because changing Avogadro's number directly affects the mass of one mole of a substance, as the molar mass is defined based on Avogadro's number.
105 Easy
105 of 313
Application +4 | -1
To neutralise 20 mL of M/ 10 NaOH, the volume of M/20 HCl needed is:
View answer and explanation
Correct option: C
40 mL
Option C (40 mL) is correct because it is calculated by using the neutralization equation N1V1=N2V2N_1V_1 = N_2V_2.
106 Hard
106 of 313
Application +4 | -1
74.5 g of a metallic chloride contains 35.5 g of chlorine, the equivalent weight of the metal is
View answer and explanation
Correct option: C
39
Option C (39) is correct because the equivalent weight of the metal is calculated by using the formula relating the masses and equivalent weights of the metal and chlorine.
107 Hard
107 of 313
Analyzing +4 | -1
Assertion: Sulphate is estimated as BaSO4\mathrm{BaSO}_4 and not as MgSO4\mathrm{MgSO}_4.
Reason: Ionic radius of Mg2+\mathrm{Mg}^{2+} is smaller than Ba2+\mathrm{Ba}^{2+}.
View answer and explanation
Correct option: D
Both Assertion and Reason are correct but Reason is not correct explanation of Assertion
Option D is correct because both the assertion and the reason are correct, but the reason is not the correct explanation for the assertion.
108 Medium
108 of 313
Application +4 | -1
0.1 mole of a carbohydrate with empirical formula CH2O\mathrm{C}{\mathrm{H}_2}\mathrm{O} contains 1 g of hydrogen. What is its molecular formula?
View answer and explanation
Correct option: A
C5H10O5{\mathrm{C}_5}{\mathrm{H}_{10}}{\mathrm{O}_5}
Option A (C5H10O5{\mathrm{C}_5}{\mathrm{H}_{10}}{\mathrm{O}_5}) is correct. By calculating the moles of hydrogen from the given mass and comparing it to the moles of the carbohydrate, we can determine the molecular formula.
109 Medium
109 of 313
Understanding +4 | -1
Irrespective of the source, pure sample, of water always yields 88.89% mass of oxygen and 11.11% mass of hydrogen. This is explained by the law of
View answer and explanation
Correct option: C
constant composition
Option C (constant composition) is correct because the law of constant composition states that a pure compound always contains the same elements combined in the same proportion by mass.
110 Easy
110 of 313
Understanding +4 | -1
Oxygen and the oxide ion have the
View answer and explanation
Correct option: A
Same proton number
Option A (Same proton number) is correct because oxygen and its oxide ion are the same element, and the number of protons defines the element.
111 Hard
111 of 313
Application +4 | -1
The equivalent weight of a metal is 9 and vapour density of its chloride is 59.25. The atomic weight of metal is
View answer and explanation
Correct option: A
23.9
Option A (23.9) is correct because it's calculated using the relationship between equivalent weight, atomic weight, and the valence derived from the vapor density of the chloride.
112 Easy
112 of 313
Remembering +4 | -1
The value of gram molar volume of gas is:
View answer and explanation
Correct option: D
22.4 litre at STP
Option D (22.4 litre at STP) is correct because the gram molar volume of any gas at Standard Temperature and Pressure (STP) is 22.4 litres.
113 Easy
113 of 313
Understanding +4 | -1
The least count of an instrument is 0.01 cm. Taking all precautions, the most possible error in the measurement can be
View answer and explanation
Correct option: B
0.01 cm
Option B is correct because the most possible error is equal to the least count of the instrument.
114 Medium
114 of 313
Remembering +4 | -1
One gram mole of a gas at NTP occupies 22.4 L. This fact was derived from
View answer and explanation
Correct option: B
Avogadro’s hypothesis
Option B (Avogadro’s hypothesis) is correct because Avogadro's hypothesis states that equal volumes of all gases, at the same temperature and pressure, have the same number of molecules, leading to the molar volume concept.
115 Medium
115 of 313
Remembering +4 | -1
Equivalent weight of oxygen is:
View answer and explanation
Correct option: B
8
Option B (8) is correct because the equivalent weight of oxygen is its atomic weight (16) divided by its valence (2), resulting in 8.
116 Hard
116 of 313
Analyzing +4 | -1
Iron forms two oxides. If for the same mass of iron, the mass of oxygen combined in the first oxide is two-third of the mass of oxygen combined in the second oxide, then the ratio of valency of iron in first and second oxide is
View answer and explanation
Correct option: B
2:32: 3
Option B (2:32: 3) is correct because the ratio of valencies is inversely proportional to the ratio of oxygen masses combined with the same mass of iron.
117 Easy
117 of 313
Remembering +4 | -1
Ratio in hydrogen and oxygen in water molecule by volume is
View answer and explanation
Correct option: A
2:12:1
Option A (2:12:1) is correct because water (H₂O) has two hydrogen atoms for every one oxygen atom by volume.
118 Easy
118 of 313
Application +4 | -1
MM is the molecular weight of KMnO4.\mathrm{KMn}{\mathrm{O}_4}. The equivalent weight of KMnO4\mathrm{KMn}{\mathrm{O}_4} when it is converted into K2MnO4{\mathrm{K}_2}\mathrm{Mn}{\mathrm{O}_4} is :
View answer and explanation
Correct option: A
MM
Option A (MM) is correct because when KMnO4KMnO_4 is converted to K2MnO4K_2MnO_4, the oxidation state of Mn changes from +7 to +6, a change of 1. Therefore, the equivalent weight is M/1 = M.
119 Medium
119 of 313
Understanding +4 | -1
Camphor is often used in molecular mass determination because
View answer and explanation
Correct option: C
It is volatile
Option C (It is volatile) is correct because camphor's volatility allows for easy purification and determination of colligative properties.
120 Easy
120 of 313
Application +4 | -1
5 molar solution of H2SO4{H_2}S{O_4} is diluted from 1 litre to a volume of 10 litre, the normality of the solution will be
View answer and explanation
Correct option: A
1N
Option A (1N) is correct because the normality is calculated using the dilution formula and considering the n-factor of H2SO4.
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