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NEET • CHEMISTRY • SOLID STATE

Solid state practice · Medium

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Showing 61-90 of 112 questions

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61 Medium
61 of 112
Remembering +4 | -1
In the calcium fluoride structure, the coordination number of the cation and anion are respectively
View answer and explanation
Correct option: D
8,48,\mathrm{ }4
Option D (8, 4) is correct because in the CaF2CaF_2 structure, each Ca2+Ca^{2+} ion is surrounded by 8 F−F^- ions, and each F−F^- ion is surrounded by 4 Ca2+Ca^{2+} ions.
62 Medium
62 of 112
Remembering +4 | -1
The unit cell with crystallographic dimensions a≠b≠c,   α=γ=90oa \ne b \ne c,\,\,\,\alpha = \gamma = {90^\mathrm{o}} and β≠90o\beta \ne {90^\mathrm{o}} is
View answer and explanation
Correct option: A
Monoclinic
Option A (Monoclinic) is correct because the given crystallographic dimensions match the definition of a monoclinic unit cell.
63 Medium
63 of 112
Remembering +4 | -1
p-type semiconductor is formed when germanium is doped with
View answer and explanation
Correct option: C
Aluminium
Option C (Aluminium) is correct because Aluminium is a trivalent impurity, and doping Germanium with a trivalent impurity creates a p-type semiconductor.
64 Medium
64 of 112
Analyzing +4 | -1
What is common in HCP and FCC unit cell?
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because there is no commonality among the given options for HCP and FCC unit cells.
65 Medium
65 of 112
Application +4 | -1
The number of atoms in 100 g of an fcc crystal with density d=10g/cm3d = 10\mathrm{g/c}{\mathrm{m}^\mathrm{3}} and cell edge equal to 100 pm, is equal to
View answer and explanation
Correct option: D
4×10254 \times {10^{25}}
Option D (4×10254 \times {10^{25}}) is correct because it's the calculated number of atoms based on the given parameters.
66 Medium
66 of 112
Application +4 | -1
A,B\mathrm{A}, \mathrm{B} and C\mathrm{C} have the oxidation numbers of +6,−2+6,-2 and −1-1 respectively, the possible molecular formula when these atoms combine will be:
View answer and explanation
Correct option: B
AB2C2\mathrm{AB}_2 \mathrm{C}_2
Option B is correct because the charges must balance in a neutral molecule. With A having +6, B having -2, and C having -1, the formula AB2C2AB_2C_2 gives a net charge of +6 + 2(-2) + 2(-1) = +6 - 4 - 2 = 0.
67 Medium
67 of 112
Understanding +4 | -1
Given below are two statements.
Statement I Frenkel defects are vacancy as well as interstitial defects.
Statement II Frenkel defects leads to colour in ionic solids due to presence of F - centres.
Choose the most appropriate answer from the options given below.
View answer and explanation
Correct option: C
Statement I is true but statement II is false.
Option C (Statement I is true but statement II is false) is correct because Frenkel defects are both vacancy and interstitial defects, but they don't directly lead to color due to F-centers.
68 Medium
68 of 112
Remembering +4 | -1
Close packing is maximum in the crystal lattice of :
View answer and explanation
Correct option: B
Face centred
Option B (Face centred) is correct because face-centered cubic (FCC) structures have the highest packing efficiency (74%).
69 Medium
69 of 112
Understanding +4 | -1
The example of orthosilicate is :
View answer and explanation
Correct option: B
Mg2SiO4\mathrm{M}{\mathrm{g}_2}\mathrm{Si}{\mathrm{O}_4}
Option B (Mg2SiO4\mathrm{M}{\mathrm{g}_2}\mathrm{Si}{\mathrm{O}_4}) is correct because orthosilicates are characterized by isolated SiO44−SiO_4^{4-} tetrahedra, which is represented by the formula Mg2SiO4\mathrm{M}{\mathrm{g}_2}\mathrm{Si}{\mathrm{O}_4}.
70 Medium
70 of 112
Remembering +4 | -1
The correct option for the number of body centred unit cells in all 14 types of Bravais lattice unit cells is:
View answer and explanation
Correct option: B
3
Option B (3) is correct because there are three Bravais lattices that have body-centered unit cells: body-centered cubic, body-centered tetragonal, and body-centered orthorhombic.
71 Medium
71 of 112
Application +4 | -1
An element has bcc structure having unit cells 12.08×102312.08 \times {10^{23}}. The number of atoms in these cells is :
View answer and explanation
Correct option: B
24.16×102324.16 \times {10^{23}}
Option B (24.16×102324.16 \times {10^{23}}) is correct because in a bcc structure, there are 2 atoms per unit cell. Therefore, the total number of atoms is twice the number of unit cells.
72 Medium
72 of 112
Understanding +4 | -1
Which among the following will show anisotropy?
View answer and explanation
Correct option: C
Barium chloride
Option C (Barium chloride) is correct because crystalline solids like barium chloride exhibit anisotropy, meaning their properties vary with direction.
73 Medium
73 of 112
Application +4 | -1
If a crystal lattice of a compound, each corner of a cube is enjoyed by sodium, each edge of a cube has oxygen and centre of a cube is enjoyed by tungsten (W)(W), then give its formula
View answer and explanation
Correct option: B
NaWO3\mathrm{NaW}{\mathrm{O}_3}
Option B is correct because the formula is derived by calculating the contribution of each atom type based on its position in the unit cell: Na at corners (1/8 contribution), O at edges (1/4 contribution), and W at the center (1 contribution).
74 Medium
74 of 112
Application +4 | -1
The fraction of the total volume occupied by the atoms present in bcc unit cell is
View answer and explanation
Correct option: B
3π8\frac{{\sqrt 3 \pi }}{8}
Option B (3π8\frac{{\sqrt 3 \pi }}{8}) is correct because it represents the packing fraction of a BCC unit cell.
75 Medium
75 of 112
Understanding +4 | -1
At zero kelvin, most of the ionic crystals possess.
View answer and explanation
Correct option: C
No defect
Option C (No defect) is correct because at zero Kelvin, the thermal energy is minimal, and the ions or atoms tend to occupy their ideal lattice positions, minimizing defects.
76 Medium
76 of 112
Understanding +4 | -1
The ratio of closed packed atoms to tetrahedral holes in cubic close packing is:
View answer and explanation
Correct option: B
1:21\mathrm{ }:\mathrm{ }2
Option B (1:21\mathrm{ }:\mathrm{ }2) is correct because in cubic close packing (CCP), for every N closed packed atoms, there are 2N tetrahedral holes.
77 Medium
77 of 112
Analyzing +4 | -1
Which of the following statements is/are not true?
View answer and explanation
Correct option: D
Non – stoichiometric defects do not alter the density of the solid
Option D is correct because non-stoichiometric defects *do* alter the density of the solid by creating vacancies or interstitial ions.
78 Medium
78 of 112
Remembering +4 | -1
An example of a substance possessing giant covalent structure is
View answer and explanation
Correct option: B
Silica
Option B (Silica) is correct because silica (SiO2SiO_2) forms a giant covalent network structure.
79 Medium
79 of 112
Analyzing +4 | -1
A substance AB crystallizes in cubic
closest packing (C.C.P.) with B occupying
half the tetrahedral voids. One litre of
the crystal is doped with 1 mole atoms of
C some of which replace the B atoms
and remaining occupy few interstitial
voids without affecting the dimensions of
cubic crystal lattice. If density of crystal
before doping is 4.8 gm/millilitre and
density after doping is 4.795 gm /ml then
calculate % of C added with replace B
atoms.
(Given : Atomic weight : A, B
and C : 40, 30, 15)
View answer and explanation
Correct option: B
66.67
Option B (66.67) is correct because it is the percentage of C atoms that replace B atoms calculated based on the change in density after doping.
80 Medium
80 of 112
Understanding +4 | -1
The ratio of number of atoms present in a simple cubic, body centered cubic and face centered cubic structure are, respectively.
View answer and explanation
Correct option: B
0.043101852
Option A (0.334097222) is incorrect. The correct answer should be the ratio of the number of atoms per unit cell in simple cubic, body-centered cubic, and face-centered cubic structures, which is 1:2:4, thus the ratio is 1/7 : 2/7 : 4/7, which is approximately 0.143:0.286:0.571. None of the options are correct.
81 Medium
81 of 112
Understanding +4 | -1
Which kind of defect is shown by the given crystal?
K+Cl−K+Cl−K+Cl−{K^ + }C{l^ - }{K^ + }C{l^ - }{K^ + }C{l^ - }
Cl−□ Cl−K+□ K+C{l^ - }{ \Box }\,C{l^ - }{K^ + }{ \Box }\,{K^ + }
K+Cl− □ Cl−K+Cl−{K^ + }C{l^ - }\,{ \Box }\,C{l^ - }{K^ + }C{l^ - }
Cl−K+Cl−K+□K+C{l^ - }{K^ + }C{l^ - }{K^ + }{ \Box }{K^ + }
View answer and explanation
Correct option: A
Schottky defect
Option A (Schottky defect) is correct because the crystal shows missing K+ and Cl- ions, which is characteristic of a Schottky defect.
82 Medium
82 of 112
Application +4 | -1
Of the elements Sr,Zr,Mo,Cd and  Sb,\mathrm{Sr},\mathrm{Zr},\mathrm{Mo},\mathrm{Cd}\,\mathrm{ and}\;\mathrm{ Sb}, all of which are in VV period, the paramagnetics are:
View answer and explanation
Correct option: D
Zr,Mo  and  Sb\mathrm{Zr},\mathrm{Mo}\;and\;Sb
Option D is correct because paramagnetic elements have unpaired electrons. In the V period, Zr, Mo, and Sb can exhibit paramagnetism due to their electronic configurations.
83 Medium
83 of 112
Remembering +4 | -1
Liquid crystals are best used in:
View answer and explanation
Correct option: A
Colour TV
Option A (Colour TV) is correct because liquid crystals are widely used in display technologies like colour TVs due to their ability to manipulate light.
84 Medium
84 of 112
Understanding +4 | -1
Which of the following statements is not correct?
View answer and explanation
Correct option: D
The coordination number of S2−  in  ZnS{\mathrm{S}^{2 - }}\;in\;\mathrm{ZnS} is 6
Option D (The coordination number of S2−  in  ZnS{\mathrm{S}^{2 - }}\;in\;\mathrm{ZnS} is 6) is correct because in ZnS, the coordination number of S2−S^{2-} is 4, not 6. Each S2−S^{2-} ion is tetrahedrally surrounded by Zn2+Zn^{2+} ions.
85 Medium
85 of 112
Analyzing +4 | -1
Assertion (A) Both Frenkel and Schottky defects are stoichiometric defects.

Reason (R) Both defects change the density of the crystalline solid.
View answer and explanation
Correct option: C
If Assertion is true but Reason is false.
Option C is correct because while Frenkel and Schottky defects are stoichiometric, only Schottky defects change the density of the solid.
86 Medium
86 of 112
Understanding +4 | -1
Which of the following point defects are shown by Ag Br (s) crystals

i) Schottky defect ii) Frenkel defect

iii) Metal excess defect iv) Metal deficiency defect
View answer and explanation
Correct option: A
i and ii
Option A (i and ii) is correct because AgBr(s) crystals show both Schottky and Frenkel defects.
87 Medium
87 of 112
Remembering +4 | -1
Which type of solid crystals will conduct heat and electricity?
View answer and explanation
Correct option: D
Metallic
Option D (Metallic) is correct because metallic solids have delocalized electrons that can conduct heat and electricity.
88 Medium
88 of 112
Understanding +4 | -1
The correct statement regarding F-centre is
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because F-centers involve electrons trapped in voids, which cause color and increase conductivity.
89 Medium
89 of 112
Understanding +4 | -1
Which defect may be present in NaClNaCl crystal?
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because NaCl crystals can exhibit Schottky defects, non-stoichiometric defects, and impurity defects.
90 Medium
90 of 112
Application +4 | -1
The edge of unit cell of fcc Xe crystal is 620 pm. The radius of Xe atom is
View answer and explanation
Correct option: C
219.25pm219.25\mathrm{ }pm
Option C (219.25pm219.25\mathrm{ }pm) is correct because in an FCC lattice, the radius is related to the edge length by r=24ar = \frac{{\sqrt{2}}}{{4}}a.
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