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NEET • CHEMISTRY • ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES
Organic chemistry-some basic principles and techniques practice · Medium
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31
Medium
31 of 173
Analyzing
+4 | -1
The correct order of stability of the given carbocation will be
View answer and explanation
Correct option: C
II > I > III
Option C (II > I > III) is correct because the stability of carbocations is influenced by electron-donating groups, with resonance being more stabilizing than inductive effects, and electron-withdrawing groups destabilizing them.
32
Medium
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Analyzing
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What is the correct order of decreasing stability of the following cations
I)
II)
III)
I)
II)
III)
View answer and explanation
Correct option: A
II > I > III
Option B (II > I > III) is correct because the carbocation is stabilized by the electron-donating effect of the methoxy group in II, and destabilized by the inductive effect in III.
33
Medium
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Analyzing
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Assertion: Pyridine is more basic than Pyrrole.
Reason: In Pyrrole, nitrogen has hybridisation
and the lone pair of nitrogen is not available for
donation.
Reason: In Pyrrole, nitrogen has hybridisation
and the lone pair of nitrogen is not available for
donation.
View answer and explanation
Correct option: A
If both Assertion and Reason are correct and
Reason is the correct explanation of
Assertion
Reason is the correct explanation of
Assertion
Option A is correct because Pyridine is indeed more basic than Pyrrole, and the reason provided correctly explains why: the lone pair in Pyrrole is involved in aromaticity and thus less available for donation.
34
Medium
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Analyzing
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Which one of the carbanions is the least stable?
View answer and explanation
Correct option: C
Option C () is the least stable carbanion because alkyl groups are electron-donating and destabilize the negative charge on the carbon.
35
Medium
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Remembering
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In Kjeldahl's method for the estimation of nitrogen, the formula used to
View answer and explanation
Correct option: B
Option B is correct because it represents the formula for calculating the percentage of nitrogen in Kjeldahl's method, relating volume, normality, and weight.
36
Medium
36 of 173
Analyzing
+4 | -1
Identify, which of the below does not possess any element of symmetry?
View answer and explanation
Correct option: A
(+)(-) tartaric acid
Option A ((+)(-) tartaric acid) is correct because a racemic mixture of tartaric acid does not possess any element of symmetry.
37
Medium
37 of 173
Understanding
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Di-chloroacetic acid is a stronger acid than acetic acid.
This due to occurrence of
This due to occurrence of
View answer and explanation
Correct option: C
Inductive effect
Option C is correct because the electron-withdrawing inductive effect of the chlorine atoms stabilizes the conjugate base of dichloroacetic acid, making it a stronger acid.
38
Medium
38 of 173
Analyzing
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Which of the following compounds is isomeric with , 4- tetramethylhexane?
View answer and explanation
Correct option: B
4-isopropylheptane
Option B is correct because 4-isopropylheptane has the same number of carbon atoms as 2,2,4,4-tetramethylhexane (10 carbons), making them isomers.
39
Medium
39 of 173
Analyzing
+4 | -1
An organic compound (molar mass = 60) is found to contain While rest is oxygen. On heating it gives along with a solid residue. The solid residue gives violet with alkaline The organic compound is:
View answer and explanation
Correct option: C
Option C () is correct because the compound contains C, H, N, and O in the given percentages, releases ammonia upon heating, and the residue gives a violet color with alkaline , indicating a peptide bond, which is consistent with urea.
40
Medium
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Understanding
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The compound which will not show geometrical isomerism is
View answer and explanation
Correct option: B
Option B () is correct because for geometrical isomerism to occur, each carbon of the double bond must have two different groups attached. In this case, one carbon has two identical phenyl groups.
41
Medium
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Application
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During hearing of a court case, the judge suspected that some changes in the documents had been carried out. He asked the forensic department to check the ink used at two different places. According to you which technique can give the best results?
View answer and explanation
Correct option: D
Thin layer chromatography
Option D (Thin layer chromatography) is correct because it is a suitable technique for comparing inks based on their different adsorption characteristics on a stationary phase.
42
Medium
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Remembering
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Dumas method involves the determination of nitrogen content in the organic compound in the form of
View answer and explanation
Correct option: B
The correct answer is because in Dumas method, the nitrogen in the organic compound is converted to nitrogen gas (), which is then measured to determine the nitrogen content.
43
Medium
43 of 173
Remembering
+4 | -1
Reimer-Tiemann reaction involves a:
View answer and explanation
Correct option: B
Carbene intermediate
Option B is correct because the Reimer-Tiemann reaction involves the formation of dichlorocarbene as an intermediate, which then reacts with the phenol.
44
Medium
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Understanding
+4 | -1
What is the hybridization shown by and carbons, respectively in the given compound?
View answer and explanation
Correct option: B
and
Option D ( and ) is correct because the first carbon (C1) is part of an aldehyde group and is hybridized, while the second carbon (C2) is bonded to four groups and is hybridized.
45
Medium
45 of 173
Remembering
+4 | -1
In organic compound phosphorus is estimated as:
View answer and explanation
Correct option: A
Magnesium pyrophosphate
Option A (Magnesium pyrophosphate ) is correct because phosphorus is estimated as magnesium pyrophosphate in quantitative analysis.
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46
Medium
46 of 173
Remembering
+4 | -1
Fuels from crude oil are separated from one another by:
View answer and explanation
Correct option: A
Fractional distillation
Option A (Fractional distillation) is correct because fuels from crude oil are separated based on their different boiling points using fractional distillation.
47
Medium
47 of 173
Application
+4 | -1
2 – methyl butane on reaction with bromine in the presence of sun light gives mainly
View answer and explanation
Correct option: B
2 – bromo – 2- methyl butane
Option B (2 – bromo – 2- methyl butane) is correct because the most stable carbocation is formed at the 2nd carbon, leading to the major product.
48
Medium
48 of 173
Understanding
+4 | -1
- tartaric acid and - tartaric acid are :
View answer and explanation
Correct option: D
Enantiomers
Option D (Enantiomers) is correct because d-tartaric acid and l-tartaric acid are non-superimposable mirror images of each other, which defines them as enantiomers.
49
Medium
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Understanding
+4 | -1
The IUPAC name of ethylidene chloride is:
View answer and explanation
Correct option: D
1, 1-Dichloroethane
Option D (1, 1-Dichloroethane) is correct because \"ethylidene\" implies both chlorine atoms are attached to the same carbon in ethane.
50
Medium
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Analyzing
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Assertion (A): All the carbon atoms in are hybridized
Reason (R): is a planar molecule
Reason (R): is a planar molecule
View answer and explanation
Correct option: D
Both A and R are false
Option D is correct because the central carbon in allene (H₂C=C=CH₂) is sp hybridized, not sp², and the molecule is non-planar due to the perpendicular arrangement of the CH₂ groups.
51
Medium
51 of 173
Analyzing
+4 | -1
Which of the following represents the correct IUPAC name for the compounds concerned?
View answer and explanation
Correct option: A
2, 2-dimethylpentane
Option A is correct because 2,2-dimethylpentane is the correct IUPAC name for the given structure. The longest chain is 5 carbons (pentane), and there are two methyl groups at position 2.
52
Medium
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Application
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IUPAC name of is :
View answer and explanation
Correct option: D
- dimethyl ethanamine
Option D (- dimethyl ethanamine) is correct because it follows IUPAC nomenclature rules, correctly identifying the longest carbon chain and the substituents attached to the nitrogen atom.
53
Medium
53 of 173
Analyzing
+4 | -1
The number of isomers in are
View answer and explanation
Correct option: A
7
Option A (7) is correct because there are 7 structural isomers of .
54
Medium
54 of 173
Analyzing
+4 | -1
Which resonating structure of vinyl. Chloride is least stable
View answer and explanation
Correct option: C
Option C () is correct because it has charge separation and an incomplete octet on the carbon, making it the least stable resonating structure.
55
Medium
55 of 173
Analyzing
+4 | -1
Which one of the following compounds is most polar?
View answer and explanation
Correct option: B
Option B () is correct because polarity depends on the electronegativity difference between atoms and the molecular geometry. Fluorine is the most electronegative halogen, leading to a larger dipole moment.
56
Medium
56 of 173
Understanding
+4 | -1
Thiophene is separated from benzene by:
View answer and explanation
Correct option: A
Chlorination of thiophene
Option B is correct because thiophene undergoes sulfonation more readily than benzene, leading to a product that can be easily separated.
57
Medium
57 of 173
Remembering
+4 | -1
Correct order of -I effect is:
(a)
(b)
(c) -CHO
(d) -COOH
(a)
(b)
(c) -CHO
(d) -COOH
View answer and explanation
Correct option: A
a b c d
Option A (a b c d) is correct because the order of -I effect depends on the electronegativity and positive charge, with positively charged nitrogen having a strong -I effect.
58
Medium
58 of 173
Understanding
+4 | -1
Consider thiol anion and alkoxy anion. Which of the following statement is correct?
View answer and explanation
Correct option: B
is less basic but more nucleophilic than
Option B () is correct because the stability of free radicals increases with increasing substitution due to hyperconjugation and inductive effects.
59
Medium
59 of 173
Application
+4 | -1
IUPAC name of is
View answer and explanation
Correct option: C
Triamminebromochloronitroplatinum (IV) chloride
Option C (Triamminebromochloronitroplatinum (IV) chloride) is correct because it follows the IUPAC naming conventions for coordination compounds, listing ligands alphabetically and indicating the oxidation state of the metal.
60
Medium
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Application
+4 | -1
An organic compound has carbon and hydrogen percentage in the ratio 6:1 and carbon and oxygen percentages in the ratio 3:4. The compound has the empirical formula
View answer and explanation
Correct option: D
Option D () is correct because the ratio of C:H:O is 1:2:1, which corresponds to the empirical formula .
Revision notes and key takeaways
Review ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES in your textbook or class notes, then use this set to check your understanding.
Showing 31-60 of 173 questions
