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NEET • CHEMISTRY • ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

Organic chemistry-some basic principles and techniques practice · Mixed difficulty

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Showing 181-210 of 392 questions

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181 Hard
181 of 392
Understanding +4 | -1
Identify the substitute group, that acts as ortho-para director, during electrophilic substitution in aromatic compounds.
View answer and explanation
Correct option: A
−NH2- \mathrm{N}{\mathrm{H}_2}
Option A (-NH2) is correct because amino groups are strong activating groups that donate electron density into the aromatic ring through resonance, directing electrophilic substitution to the ortho and para positions.
182 Easy
182 of 392
Application +4 | -1
A hydrocarbon contains 10.5 g carbon and 1 g hydrogen. Its 2.4 g has 1 L volume at 1 atm and 127∘^ \circC. Hydrocarbon is
View answer and explanation
Correct option: A
C6H7{\mathrm{C}_6}{\mathrm{H}_7}
Option A (C6H7{\mathrm{C}_6}{\mathrm{H}_7}) is correct because the empirical formula is C6H7, and the molar mass calculated from the ideal gas law matches this formula.
183 Easy
183 of 392
Remembering +4 | -1
A secondary(2∘{2^ \circ }) carbon is one that is joined to :
View answer and explanation
Correct option: B
2-alkyl groups
Option B is correct because a secondary carbon is bonded to two other carbon atoms (alkyl groups).
184 Hard
184 of 392
Understanding +4 | -1
An organic compound contains, C, H and S. When C and H are to be estimated the combustion tube at the exit should contain a:
View answer and explanation
Correct option: D
Lead chromate
Option D (Lead chromate) is correct because lead chromate is used to oxidize sulfur to sulfur dioxide, which can then be absorbed and quantified to estimate the sulfur content.
185 Easy
185 of 392
Remembering +4 | -1
The prefix name of —SH group in IUPAC system is :
View answer and explanation
Correct option: A
Mercapto
Option A (Mercapto) is correct because 'mercapto' is the prefix used to name the -SH group in the IUPAC system when it is a substituent.
186 Easy
186 of 392
Understanding +4 | -1
Which of the following species is not electrophile in nature
View answer and explanation
Correct option: C
H3+O{H_3}^ + O
Option C is correct because H3O+ is a hydronium ion, which is a protonated water molecule and acts as an acid (proton donor), not an electrophile (electron acceptor).
187 Medium
187 of 392
Analyzing +4 | -1
Arrange in decreasing order of +R+\mathrm{R} power in the given groups

I) −NH2-\mathrm{NH}_2

II) −OΘ-O^{\Theta}

III) −OH-\mathrm{OH}

IV) −NHCOCH3-\mathrm{NHCOCH}_3
View answer and explanation
Correct option: A
II >> I >> III >> IV
Option A (II > I > III > IV) is correct because the +R effect depends on the availability of electrons, which is highest for O-, followed by NH2, OH, and NHCOCH3.
188 Medium
188 of 392
Remembering +4 | -1
In Kjeldahl’s method of estimation of nitrogen, K2SO4{\mathrm{K}_2}\mathrm{S}{\mathrm{O}_4} acts as:
View answer and explanation
Correct option: D
Boiling point elevator
Option D (Boiling point elevator) is correct because K2SO4{\mathrm{K}_2}\mathrm{S}{\mathrm{O}_4} is added to increase the boiling point of sulfuric acid, facilitating the digestion process.
189 Medium
189 of 392
Understanding +4 | -1
Which conformation of butane will have the minimum energy
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Correct option: B
Anti/staggered
Option B (Anti/staggered) is correct because the anti or staggered conformation of butane has the lowest energy due to minimal steric hindrance between the methyl groups.
190 Easy
190 of 392
Remembering +4 | -1
Cyclohexane is :
View answer and explanation
Correct option: B
Alicyclic compound
Option B is correct because cyclohexane is a cyclic aliphatic compound, hence alicyclic.
191 Medium
191 of 392
Understanding +4 | -1
The compound formed in the positive test for nitrogen with the Lassaigne solution of an organic compound is
View answer and explanation
Correct option: A
Fe4[Fe(CN)6]3\mathrm{F}{\mathrm{e}_4}{\left[ {\mathrm{Fe}{{\left( {\mathrm{CN}} \right)}_6}} \right]_3}
Option A (Fe4[Fe(CN)6]3\mathrm{F}{\mathrm{e}_4}{\left[ {\mathrm{Fe}{{\left( {\mathrm{CN}} \right)}_6}} \right]_3}) is correct because the Prussian blue color in the Lassaigne's test for nitrogen is due to the formation of ferric ferrocyanide, Fe4[Fe(CN)6]3Fe_4[Fe(CN)_6]_3.
192 Medium
192 of 392
Analyzing +4 | -1
Which of the following statement(s) is/are correct ?

(i) A carbon atom having an sps p hybrid orbital is less electronegative than carbon atoms possessing sp2s p^2 or sp3s p^3 hybridised orbitals.

(ii) π\pi-bonds provide the most reactive centres in the molecules containing multiple bonds

(iii) The number of σ\sigma and π\pi bonds in compound CH2=C=CHCH3{CH}_2={C}={CHCH}_3 are 7 and 2 respectively.
View answer and explanation
Correct option: C
(ii) only
Option C ((ii) only) is correct because only statement (ii) is correct. Pi-bonds are indeed reactive centers, while (i) is incorrect as sp hybridized carbon is more electronegative, and (iii) has incorrect bond counts.
193 Medium
193 of 392
Understanding +4 | -1
Increasing order of stability of radicals is
View answer and explanation
Correct option: B
CH3−C.H2<CH3−C.H−CH3<(CH3)2C.−CH2−CH3<(CH3)3C.C{H_3} - \mathop C\limits^. {H_2} < C{H_3} - \mathop C\limits^. H - C{H_3} < {\left( {C{H_3}} \right)_2}\mathop C\limits^. - C{H_2} - C{H_3} < {\left( {C{H_3}} \right)_3}\mathop C\limits^.
Option C (4-methyl hex-2-yne) is correct because it follows the IUPAC naming rules by identifying the longest chain containing the triple bond and numbering it to give the triple bond the lowest possible number.
194 Medium
194 of 392
Application +4 | -1
Correct IUPAC structure for the given organic compound is 2,2-Dibromo-1-phenylpentane
View answer and explanation
Correct option: B
Ph−CH2−C∣BrBr∣−CH2−CH2−CH3Ph - C{H_2} - \mathop C\limits_{\begin{array}{cccccccccccccccccccc} | \\ {Br} \end{array}}^{\begin{array}{cccccccccccccccccccc} {Br} \\ | \end{array}} - C{H_2} - C{H_2} - C{H_3}
Option B is correct because it accurately represents the 2,2-Dibromo-1-phenylpentane structure with the correct placement of the phenyl group and bromine atoms.
195 Medium
195 of 392
Application +4 | -1
In Carius method of 0.099 g orgainc compound gave 0.287 g AgCl\mathrm{AgCl}. The percentage of chlorine in the compound will be
View answer and explanation
Correct option: B
71.7
Option B (71.7) is correct because the percentage of chlorine is calculated using the formula: % Chlorine = (Mass of AgCl / Molecular weight of AgCl) * (Atomic weight of Cl / Mass of organic compound) * 100.
196 Hard
196 of 392
Understanding +4 | -1
An organic compound is fused with fusion mixture and extracted with HNO3\mathrm{HN}{\mathrm{O}_3}. The extract gives yellow precipitate with ammonium molybdate. It show the presence of which element?
View answer and explanation
Correct option: D
May be P or As or both
Option D (May be P or As or both) is correct because both phosphorus and arsenic form yellow precipitates with ammonium molybdate in the presence of nitric acid.
197 Medium
197 of 392
Analyzing +4 | -1
Most stable carbocation among the following is
View answer and explanation
Correct option: C
CH3−CH2+C{H_3} - \mathop {C{H_2}}\limits^ +
Option C (CH3−CH2+C{H_3} - \mathop {C{H_2}}\limits^ +) is correct because alkyl groups stabilize carbocations through inductive effect and hyperconjugation.
198 Medium
198 of 392
Remembering +4 | -1
Formulae of phenyl carbinol and chloral are respectively :
View answer and explanation
Correct option: B
C6H5CH2OH  and  CCl3CHO{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{C}{\mathrm{H}_2}\mathrm{OH\;}{\kern 1pt} {\kern 1pt} \mathrm{and}{\kern 1pt} \mathrm{\;CC}{\mathrm{l}_3}\mathrm{CHO}
Option B is correct because phenyl carbinol is benzyl alcohol (C₆H₅CH₂OH), and chloral is trichloroacetaldehyde (CCl₃CHO).
199 Easy
199 of 392
Remembering +4 | -1
Detection of phosphorus in the compound can be done by its conversion into phosphate. Reagent to identify phosphate ion is
View answer and explanation
Correct option: B
Ammonium molybdate
Option B (Ammonium molybdate) is correct because it is the reagent used to identify phosphate ions in the detection of phosphorus.
200 Medium
200 of 392
Analyzing +4 | -1
Which of the following species is most stable?
View answer and explanation
Correct option: D
p−CH3O−C6H4−C+H2p - \mathrm{C}{\mathrm{H}_3}\mathrm{O} - {\mathrm{C}_\mathrm{6}}{\mathrm{H}_4} - \mathop \mathrm{C}\limits^ + {\mathrm{H}_2}
Option D (p−CH3O−C6H4−C+H2p - \mathrm{C}{\mathrm{H}_3}\mathrm{O} - {\mathrm{C}_\mathrm{6}}{\mathrm{H}_4} - \mathop \mathrm{C}\limits^ + {\mathrm{H}_2}) is correct because the methoxy group (OCH3OCH_3) is an electron-donating group that stabilizes the carbocation through resonance.
201 Easy
201 of 392
Analyzing +4 | -1
Which of the following have incorrect molecular formula?

A. Icosane −C10H22- {C}_{10} {H}_{22}

B. Triacontane −C30H62-{C}_{30} {H}_{62}

C. Nonane - C9H20{C}_9 {H}_{20}

D. Heptane −C7H14- {C}_7 {H}_{14}
View answer and explanation
Correct option: A
(A) and (D)
Option A is correct because Icosane and Heptane have incorrect molecular formulas. The correct formula for Icosane is C20H42 and for Heptane is C7H16.
202 Medium
202 of 392
Remembering +4 | -1
3-phenylpropenoic acid is IUPAC name of :
View answer and explanation
Correct option: D
Cinnamic acid
Option D (Cinnamic acid) is correct because 3-phenylpropenoic acid is the IUPAC name for cinnamic acid.
203 Easy
203 of 392
Remembering +4 | -1
Shifting of electrons of a multiple bond under the influence of a reagent is called :
View answer and explanation
Correct option: B
EE -effect
Option B (EE -effect) is correct because the shifting of electrons of a multiple bond under the influence of a reagent is called the electromeric effect, which is also known as the E-effect.
204 Easy
204 of 392
Remembering +4 | -1
Select the organic compound which was prepared for the first time in laboratory from its elements :
View answer and explanation
Correct option: B
CH3COOH\mathrm{C}{\mathrm{H}_3}\mathrm{COOH}
Option A (Acetic Acid) is incorrect. Option A (Urea) is incorrect. Option C (Ethanol) is incorrect. Option B (CH₃COOH) is correct because acetic acid was the first organic compound synthesized from its elements in the laboratory.
205 Easy
205 of 392
Understanding +4 | -1
Which of the following has +R+ R effect
View answer and explanation
Correct option: C
−NH2- N{H_2}
Option C (-NH2) is correct because the amino group has a lone pair of electrons that it can donate into a pi system, exhibiting a +R (resonance) effect.
206 Medium
206 of 392
Understanding +4 | -1
Which of the following statements is not characteristic of free radical chain reaction?
View answer and explanation
Correct option: B
It is usually sensitive to change in solvent polarity
Option B (Ph−CH2−C∣BrBr∣−CH2−CH2−CH3Ph - C{H_2} - \mathop C\limits_{\begin{array}{cccccccccccccccccccc} | \\ {Br} \\ \end{array}}^{\begin{array}{cccccccccccccccccccc} {Br} \\ | \\ \end{array}} - C{H_2} - C{H_2} - C{H_3}) is correct because it correctly represents a pentane chain with a phenyl group at position 1 and two bromine atoms at position 2.
207 Medium
207 of 392
Understanding +4 | -1
The SN1{\mathrm{S}_\mathrm{N}}1 mechanism for substitution reaction by nucleophile is favoured by :
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Correct option: D
All of the above
Option D (All of the above) is correct because the SN1S_N1 mechanism is favored by a low concentration of nucleophile, a weak nucleophile, and a polar solvent.
208 Easy
208 of 392
Analyzing +4 | -1
The number of isomeric pentyl alcohols possible is
View answer and explanation
Correct option: D
Eight
Option D (Eight) is correct because there are eight different structural isomers of pentyl alcohol (C5H11OH{\mathrm{C}_5}{\mathrm{H}_{11}}\mathrm{OH}).
209 Easy
209 of 392
Understanding +4 | -1
Which of the following group shows +I+ I. effect
View answer and explanation
Correct option: D
−COO−- COO -
Option D (−COO−- COO -) is correct because negatively charged groups generally show +I effect due to the availability of extra electrons.
210 Hard
210 of 392
Analyzing +4 | -1
(i) F3C−COOH\mathrm{F}_3 \mathrm{C}-\mathrm{COOH}

(ii) CH3−COOH\mathrm{CH}_3-\mathrm{COOH}

(iii) C6H5−COOH\mathrm{C}_6 \mathrm{H}_5-\mathrm{COOH}

(iv) CH3CH2COOH\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COOH}

Correct order of pKa\mathrm{pK}_{\mathrm{a}} value is:
View answer and explanation
Correct option: B
iv >> ii >> iii >> i
Option B (iv > ii > iii > i) is correct because the pKa value increases with decreasing acidity. Electron-withdrawing groups increase acidity, thus decreasing pKa.
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