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NEET • CHEMISTRY • ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

Organic chemistry-some basic principles and techniques practice · Mixed difficulty

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121 Medium
121 of 392
Analyzing +4 | -1
Which resonating structure of vinyl. Chloride is least stable
View answer and explanation
Correct option: C
CΘH2−C⊕H−Cl\mathop C\limits^\Theta {H_2} - \mathop C\limits^ \oplus H - Cl
Option C (CΘH2−C⊕H−Cl\mathop C\limits^\Theta {H_2} - \mathop C\limits^ \oplus H - Cl) is correct because it has charge separation and an incomplete octet on the carbon, making it the least stable resonating structure.
122 Medium
122 of 392
Analyzing +4 | -1
Which one of the following compounds is most polar?
View answer and explanation
Correct option: B
CH2F2\mathrm{C}{\mathrm{H}_2}{\mathrm{F}_2}
Option B (CH2F2\mathrm{C}{\mathrm{H}_2}{\mathrm{F}_2}) is correct because polarity depends on the electronegativity difference between atoms and the molecular geometry. Fluorine is the most electronegative halogen, leading to a larger dipole moment.
123 Medium
123 of 392
Understanding +4 | -1
Thiophene is separated from benzene by:
View answer and explanation
Correct option: A
Chlorination of thiophene
Option B is correct because thiophene undergoes sulfonation more readily than benzene, leading to a product that can be easily separated.
124 Medium
124 of 392
Remembering +4 | -1
Correct order of -I effect is:

(a) −N⊕R3-\stackrel{\oplus}{\text{N}} \text{R}_3

(b) −N⊕H3-\stackrel{\oplus}{\mathrm{N}} \mathrm{H}_3

(c) -CHO

(d) -COOH
View answer and explanation
Correct option: A
a >> b >> c >> d
Option A (a >> b >> c >> d) is correct because the order of -I effect depends on the electronegativity and positive charge, with positively charged nitrogen having a strong -I effect.
125 Medium
125 of 392
Understanding +4 | -1
Consider thiol anion (RS⊖)\left( {R{S^ \ominus }} \right) and alkoxy anion(RS⊖)\left( {R{S^ \ominus }} \right). Which of the following statement is correct?
View answer and explanation
Correct option: B
RS⊖R{S^ \ominus } is less basic but more nucleophilic than RO ⊖R{O^{\, \ominus }}
Option B (CH3−C.H−CH3<(CH3)2C.−CH2−CH3<(CH3)3C.C{H_3} - \mathop C\limits^. H - C{H_3} < {\left( {C{H_3}} \right)_2}\mathop C\limits^. - C{H_2} - C{H_3} < {\left( {C{H_3}} \right)_3}\mathop C\limits^.) is correct because the stability of free radicals increases with increasing substitution due to hyperconjugation and inductive effects.
126 Hard
126 of 392
Analyzing +4 | -1
The order of decreasing stability of the carbanions

(CH3)3C−(CH3)2CH−CH3CH2−C6H5CH2−(I)(II)(III)(IV)\begin{array}{cccccccccccccccccccc} {{{\left( {{\text{C}}{{\text{H}}_3}} \right)}_3}{{\text{C}}^ - }}&{{{\left( {{\text{C}}{{\text{H}}_3}} \right)}_2}{\text{C}}{{\text{H}}^ - }}&{{\text{C}}{{\text{H}}_3}{\text{CH}}_2^ - }&{{{\text{C}}_6}{{\text{H}}_5}{\text{CH}}_2^ - } \\ {\left( {\text{I}} \right)}&{\left( {{\text{II}}} \right)}&{\left( {{\text{III}}} \right)}&{\left( {{\text{IV}}} \right)} \end{array}
View answer and explanation
Correct option: B
IV >> III >> II >> I
Option A (Electron loving species) is correct because electrophiles are electron-deficient species that are attracted to electron-rich species.
127 Medium
127 of 392
Application +4 | -1
IUPAC name of [Pt(NH3)3(Br)(NO2)Cl]  Cl[Pt{(N{H_3})_3}(Br)(N{O_2})Cl]\,\,Cl is
View answer and explanation
Correct option: C
Triamminebromochloronitroplatinum (IV) chloride
Option C (Triamminebromochloronitroplatinum (IV) chloride) is correct because it follows the IUPAC naming conventions for coordination compounds, listing ligands alphabetically and indicating the oxidation state of the metal.
128 Medium
128 of 392
Application +4 | -1
An organic compound has carbon and hydrogen percentage in the ratio 6:1 and carbon and oxygen percentages in the ratio 3:4. The compound has the empirical formula
View answer and explanation
Correct option: D
CH2O\mathrm{C}{\mathrm{H}_2}\mathrm{O}
Option D (CH2O\mathrm{C}{\mathrm{H}_2}\mathrm{O}) is correct because the ratio of C:H:O is 1:2:1, which corresponds to the empirical formula CH2O\mathrm{C}{\mathrm{H}_2}\mathrm{O}.
129 Easy
129 of 392
Understanding +4 | -1
The number of 1∘,2∘{1^ \circ },{2^ \circ } and 3∘{3^ \circ } carbon atoms present in isopentane are respectively :
View answer and explanation
Correct option: C
3, 1, 1
Option A (3, 1, 1) is correct because isopentane has three primary (1°), one secondary (2°), and one tertiary (3°) carbon atoms.
130 Medium
130 of 392
Application +4 | -1
Give IUPAC name of the compound given below
CH3−CH∣Cl−CH2−CH2−CH2−CH∣OH−CH3C{H_3} - \mathop {CH}\limits_{\mathop |\limits_{Cl} } - C{H_2} - C{H_2} - C{H_2} - \mathop {CH}\limits_{\mathop |\limits_{OH} } - C{H_3}
View answer and explanation
Correct option: C
6 – Chloro heptan – 2 – ol
Option D (HC≡Cˉ>CH2=CˉH>CH3−CˉH2\mathrm{HC} \equiv \mathrm{\bar C} > C{\mathrm{H}_2} = \mathrm{\bar CH} > C{\mathrm{H}_3} - \mathrm{\bar C}{\mathrm{H}_2}) is correct because the stability of carbanions increases with increasing s-character of the carbon bearing the negative charge (sp > sp2 > sp3).
131 Easy
131 of 392
Analyzing +4 | -1
The compound isomeric with acetone is :
View answer and explanation
Correct option: A
Propionaldehyde
Option A (Propionaldehyde) is correct because acetone (CH3COCH3) and propionaldehyde (CH3CH2CHO) have the same molecular formula (C3H6O) but different structural arrangements, making them isomers.
132 Hard
132 of 392
Analyzing +4 | -1
Statetment-1: In chromatographic technique retardation factor (Rf)(R_f) does not depend on the polarity of solvent.
Statement -2: Thin layer chromatography is an example of absorption chromatography.
View answer and explanation
Correct option: D
Both Statements are false
Option D (Both Statements are false) is correct because both the retardation factor and thin layer chromatography are incorrectly described.
133 Hard
133 of 392
Application +4 | -1
The ammonia evolved from the treatment of 0.30 g of an organic compound for the estimation of nitrogen was passed in 100 mL of 0.1 M sulphuric acid. The excess of acid required 20 mL of 0.5 M sodium hydroxide solution for complete neutralization. the organic compound is
View answer and explanation
Correct option: C
urea
Option C (urea) is correct because the molar mass of urea (60 g/mol) corresponds to the amount of nitrogen estimated from the given data.
134 Medium
134 of 392
Remembering +4 | -1
Mesomeric effect involves delocalisation of
View answer and explanation
Correct option: A
Pi-electrons
Option A (Pi-electrons) is correct because the mesomeric effect involves the delocalization of pi-electrons or lone pairs of electrons.
135 Hard
135 of 392
Analyzing +4 | -1
9.9 g9.9 \mathrm{~g} amide with molecular formula C4H5NxOy\mathrm{C}_4 \mathrm{H}_5 \mathrm{N}_x \mathrm{O}_y on heating with alkali liberated 1.7 g1.7 \mathrm{~g} of ammonia. If the percentage of oxygen is 33.33%33.33 \% then the ratio of 'N\mathrm{N}' and 'O\mathrm{O}' atoms in the compound is:
View answer and explanation
Correct option: B
1:21: 2
Option B (1:21: 2) is correct because calculations based on the given data lead to a N:O ratio of 1:2.
136 Medium
136 of 392
Remembering +4 | -1
Stereoisomers (geometrical or opticals) which are neither superimposable nor mirror image to each other are called :
View answer and explanation
Correct option: D
Diastereomers
Option D (Diastereomers) is correct because diastereomers are stereoisomers that are not mirror images and are non-superimposable.
137 Easy
137 of 392
Understanding +4 | -1
The C−C\mathrm{C}-\mathrm{C} bond length of the following molecules is in the order.
View answer and explanation
Correct option: B
C2H2<  C2H4<  C6H6<  C2H6{\mathrm{C}_2}{\mathrm{H}_2} < \mathrm{\;}{\mathrm{C}_2}{\mathrm{H}_4} < \mathrm{\;}{\mathrm{C}_6}{\mathrm{H}_6} < \mathrm{\;}{\mathrm{C}_2}{\mathrm{H}_6}
Option B (C2H2<C2H4<C6H6<C2H6{\mathrm{C}_2}{\mathrm{H}_2} < {\mathrm{C}_2}{\mathrm{H}_4} < {\mathrm{C}_6}{\mathrm{H}_6} < {\mathrm{C}_2}{\mathrm{H}_6}) is correct because bond length decreases with increasing bond order due to stronger attraction between the carbon atoms.
138 Easy
138 of 392
Remembering +4 | -1
The group named as benzal possesses ……nature.
View answer and explanation
Correct option: B
Bivalent
Option B (Bivalent) is correct because the benzal group (C₆H₅CH=) has two valencies available for bonding.
139 Medium
139 of 392
Analyzing +4 | -1
Percentage of hydrogen is maximum in .
View answer and explanation
Correct option: B
CH4\mathrm{C}{\mathrm{H}_4}
Option B (CH4\mathrm{C}{\mathrm{H}_4}) is correct because methane has the highest hydrogen to carbon ratio among the given options.
140 Easy
140 of 392
Application +4 | -1
On monochlorination of nn- pentane, the number of isomers formed is :
View answer and explanation
Correct option: B
3
Option A (4) is correct because monochlorination of n-pentane yields 3 distinct monochlorinated isomers (1-chloropentane, 2-chloropentane, and 3-chloropentane).
141 Easy
141 of 392
Remembering +4 | -1
Which of the following alkyl halides is used as a methylating agent?
View answer and explanation
Correct option: D
CH3I\mathrm{C}{\mathrm{H}_3}\mathrm{I}
Option D is correct because methyl iodide (CH3I) is a common methylating agent due to the relatively weak C-I bond, making the methyl group readily transferable.
142 Easy
142 of 392
Understanding +4 | -1
Select the correct statements
View answer and explanation
Correct option: B
−NH2- N{H_2} group activates benzene nucleus for attack of electrophile at ortho and parasites.
Option B (−NH2-NH_2 group activates benzene nucleus for attack of electrophile at ortho and parasites) is correct because the amino group is an activating and ortho/para-directing group.
143 Medium
143 of 392
Application +4 | -1
Arrange priority CIP sequence of given groups in decreasing order

i) OHOH \quad ii) COOHCOOH \quad iii) CHOHCH3CHOHCH_3 \quad iv) CH2OHCH_2OH
View answer and explanation
Correct option: A
I >> II >> III >> IV
Option A (I > II > III > IV) is correct because the priority in CIP sequence is based on atomic number, with higher atomic number having higher priority. O > C > C > C.
144 Medium
144 of 392
Analyzing +4 | -1
When thiourea is heated with metallic sodium, the compound which can't be formed is
View answer and explanation
Correct option: C
Na2SO4\mathrm{N}{\mathrm{a}_2}\mathrm{S}{\mathrm{O}_4}
Option C (Na2SO4\mathrm{N}{\mathrm{a}_2}\mathrm{S}{\mathrm{O}_4}) is correct because thiourea when heated with metallic sodium does not produce sodium sulfate.
145 Easy
145 of 392
Remembering +4 | -1
Nucleophiles are :
View answer and explanation
Correct option: C
Nucleus loving
The correct answer is Nucleus loving because nucleophiles are species that are attracted to the positively charged nucleus.
146 Easy
146 of 392
Remembering +4 | -1
Who pointed out the concept hyperconjugation?
View answer and explanation
Correct option: A
Nathan and Baker
Option A (Nathan and Baker) is correct because Nathan and Baker are credited with pointing out the concept of hyperconjugation.
147 Easy
147 of 392
Understanding +4 | -1
Example of chain isomerism are
View answer and explanation
Correct option: C
pentanoic acid and 2 – methyl butanoic acid
Option C (pentanoic acid and 2 – methyl butanoic acid) is correct because they have the same molecular formula but different carbon chain arrangements.
148 Easy
148 of 392
Understanding +4 | -1
Which of the following group show +M+ M. effect
View answer and explanation
Correct option: B
−ONO- ONO
Option B (−ONO- ONO) is correct because the +M effect is shown by groups with lone pairs that can donate electrons through resonance, and -ONO has lone pairs on oxygen.
149 Medium
149 of 392
Application +4 | -1
CH3−C∣CH3CH3∣−CH2−Cl→Δalc. KOHP(major)C{H_3} - \mathop C\limits_{\begin{array}{cccccccccccccccccccc} | \\ {C{H_3}} \end{array}}^{\begin{array}{cccccccccccccccccccc} {C{H_3}} \\ | \end{array}} - C{H_2} - Cl\xrightarrow[\Delta ]{{{\text{alc}}{\text{. }}KOH}}{\text{P}}\left( {{\text{major}}} \right)

Major product 'P\mathrm{P}' is
View answer and explanation
Correct option: A
CH3−CCH3∣=CH−CH3C{H_3} - \mathop C\limits^{\begin{array}{cccccccccccccccccccc} {C{H_3}} \\ | \end{array}} = CH - C{H_3}
Option A (CH3−CCH3∣=CH−CH3C{H_3} - \mathop C\limits^{\begin{array}{cccccccccccccccccccc} {C{H_3}} \\ | \\ \end{array}} = CH - C{H_3}) is correct because the major product of E2 elimination is the most stable alkene, which is the most substituted alkene (Zaitsev's rule).
150 Hard
150 of 392
Application +4 | -1
0.38 g0.38 \mathrm{~g} of a silver salt of a dibasic acid on ignition gave 0.27 g0.27 \mathrm{~g} of silver. Calculate the molecular mass of the acid.
View answer and explanation
Correct option: A
90
Option A (90) is correct because the molecular mass of the acid is calculated from the mass of silver salt and the mass of silver obtained after ignition.
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