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NEET • CHEMISTRY • ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

Organic chemistry-some basic principles and techniques practice · Mixed difficulty

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Showing 301-330 of 392 questions

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301 Medium
301 of 392
Understanding +4 | -1
Which of the following compounds will show metamerism?
View answer and explanation
Correct option: B
C2H5−S−C2H5{\mathrm{C}_2}{\mathrm{H}_5} - \mathrm{S} - {\mathrm{C}_2}{\mathrm{H}_5}
Option B (C2H5−S−C2H5{\mathrm{C}_2}{\mathrm{H}_5} - \mathrm{S} - {\mathrm{C}_2}{\mathrm{H}_5}) is correct because metamerism requires different alkyl groups attached to the same functional group, which is possible with sulfur.
302 Hard
302 of 392
Remembering +4 | -1
An indicator ‘XX’ is used for studying the effect of variation in concentration of iodide on the rate of reaction of iodide ion with H2O2{H_2}{O_2} at room temp. The indicator ‘XX’ forms blue colored complex with
compound ‘AA’ present in the solution. The indicator ‘XX’ and compound ‘AA’ respectively are
View answer and explanation
Correct option: B
Starch and iodine
The correct answer is Starch and iodine because starch forms a blue-colored complex with iodine in solution, which is used as an indicator in redox titrations.
303 Hard
303 of 392
Understanding +4 | -1
False statement is
View answer and explanation
Correct option: C
Diastereomers have identical physical properties
Option C (Diastereomers have identical physical properties) is the false statement because diastereomers have different physical properties.
304 Easy
304 of 392
Remembering +4 | -1
Isomerism among compounds due to the migration of a proton is known as :
View answer and explanation
Correct option: C
Tautomerism
Option C is correct because tautomerism involves the migration of a proton, resulting in two interconvertible structural isomers.
305 Easy
305 of 392
Understanding +4 | -1
Different structures generated due to rotation about, C – C axis, of an organic molecule, are examples of
View answer and explanation
Correct option: B
Conformational isomerism
Option B (Conformational isomerism) is correct because different structures generated due to rotation about C-C axis are called conformers, and this phenomenon is called conformational isomerism.
306 Hard
306 of 392
Analyzing +4 | -1
Arrange the following in decreasing order of acidic strength.

(i) Benzoic acid

(ii) 4-nitrobenzoic acid

(iii) 3,4-dinitrobenzoic acid

(iv) 4-methoxy benzoic acid
View answer and explanation
Correct option: A
III >> II >> I >> IV
Option A (III >> II >> I >> IV) is correct because electron-withdrawing groups increase acidity, while electron-donating groups decrease acidity.
307 Hard
307 of 392
Application +4 | -1
The silver salt of a monobasic acid on ignition gave 60% of Ag. The molecular weight of the acid is
View answer and explanation
Correct option: C
73
Option C (73) is correct because the molecular weight of the acid can be determined from the percentage of silver in the silver salt.
308 Easy
308 of 392
Analyzing +4 | -1
Which of the following is strongest nucleophile
View answer and explanation
Correct option: C
CN−C{N^ - }
Option C (CN−C{N^ - }) is the strongest nucleophile because carbon is less electronegative than oxygen, making the carbon atom in cyanide more willing to donate its electrons compared to the oxygen in hydroxide or ethoxide. Also, cyanide is a weaker base than ethoxide, making it a better nucleophile.
309 Easy
309 of 392
Understanding +4 | -1
The correct IUPAC name of Cl−−CH2−−CH=CH2Cl\mathrm{ }--\mathrm{ }C{H_2}--\mathrm{ }CH\mathrm{ } = \mathrm{ }C{H_2} is
View answer and explanation
Correct option: A
3-Chloroprop-1-ene
Option A (3-Chloroprop-1-ene) is correct because the chlorine is on the 3rd carbon and the double bond starts at the 1st carbon.
310 Medium
310 of 392
Application +4 | -1
If a compound on analysis was found to contain C=18.5%,  H=1.55%,  Cl=55.04%\mathrm{C} = 18.5\mathrm{\% },\mathrm{\;H} = 1.55\mathrm{\% },\mathrm{\;Cl} = 55.04\mathrm{\% } and O=24.81%\mathrm{O} = 24.81\mathrm{\% } then its empirical formula is
View answer and explanation
Correct option: D
CHClO\mathrm{CHClO}
Option D (CHClO\mathrm{CHClO}) is correct because the mole ratio of C:H:Cl:O is approximately 1:1:1:1, which corresponds to the empirical formula CHClO\mathrm{CHClO}.
311 Medium
311 of 392
Application +4 | -1
The number of optical isomers of 2, 3-dihydroxy butanal is
View answer and explanation
Correct option: B
4
Option B (4) is correct because 2,3-dihydroxybutanal has two chiral centers, and since it's not a meso compound, the number of stereoisomers is 2^n = 22 = 4.
312 Hard
312 of 392
Understanding +4 | -1
Given below are two statements:
Statement I: Emulsions of oil in water are unstable and sometimes they separate into two layers on standing.
Statement II: For stabilisation of an emulsion, excess of electrolyte is added.
In the light of the above statements, choose the most appropriate answer from the options given below:
View answer and explanation
Correct option: C
Statement I is correct but Statement II is incorrect.
Option C is correct because emulsions are indeed unstable, but adding excess electrolyte destabilizes them further, not stabilizes them.
313 Easy
313 of 392
Analyzing +4 | -1
In what order the reagents Na2S,NaClNa_2S, NaCl and NaINaI are added to an aqueous solution containing Ag+,Cu+2Ag^+, Cu^{+2} and Ni+2Ni^{+2} ions in order to precipitate Ag+Ag^+ first, Cu+2Cu^{+2} second and Ni+2Ni^{+2} last.
View answer and explanation
Correct option: D
NaCl,NaI,Na2SNaCl, NaI, Na_2S
Option D (NaCl,NaI,Na2SNaCl, NaI, Na_2S) is correct because the solubility products (KspK_{sp}) of the silver, copper, and nickel salts determine the order of precipitation.
314 Medium
314 of 392
Understanding +4 | -1
A strong base can abstract an α-hydrogen from :
View answer and explanation
Correct option: B
Ketone
Option B (Ketone) is correct because ketones have alpha hydrogens that are relatively acidic due to the adjacent carbonyl group, making them susceptible to abstraction by a strong base.
315 Easy
315 of 392
Understanding +4 | -1
Which of the following is a primary halide?
View answer and explanation
Correct option: D
Neo hexyl chloride
Option D (Neo hexyl chloride) is correct because the chlorine atom is attached to a primary carbon (a carbon bonded to only one other carbon).
316 Medium
316 of 392
Analyzing +4 | -1
Among the following the most stable compound is:
View answer and explanation
Correct option: D
trans-1,3-cyclohexanediol
Option D is correct because trans-1,3-cyclohexanediol is the most stable due to the hydroxyl groups being in equatorial positions, minimizing steric hindrance.
317 Medium
317 of 392
Remembering +4 | -1
The weakest +M group of the given species is:
View answer and explanation
Correct option: C
−I-\text{I}
Option C (−I-\text{I}) is correct because Iodine is the least electron-donating group among the given options due to its lower electronegativity compared to the others.
318 Medium
318 of 392
Understanding +4 | -1
Rotational angle requires to get maximum stable conformer from minimum stable conformer in nn-butane is
View answer and explanation
Correct option: B
1800{180^0}
Option B (1800{180^0}) is correct because the most stable conformer (anti) and the least stable conformer (eclipsed) in n-butane are 180 degrees apart in terms of rotational angle.
319 Medium
319 of 392
Remembering +4 | -1
The permanent displacement of electron through a chain involving only σ\sigma-bonds is called
View answer and explanation
Correct option: A
inductive effect
Option A (inductive effect) is correct because the permanent displacement of electrons through a chain involving only sigma bonds is the definition of the inductive effect.
320 Medium
320 of 392
Analyzing +4 | -1
Which of the following organic compounds has same hybridization as its combustion product (CO2)?\left(\mathrm{CO}_2\right)?
View answer and explanation
Correct option: B
Ethyne
Option B (Ethyne) is correct because ethyne (C₂H₂) has sp hybridization, and its combustion product, CO₂, also has sp hybridization.
321 Medium
321 of 392
Analyzing +4 | -1
In which of the following p−p -electrons of the halogens are not involved in delocalisation?
View answer and explanation
Correct option: C
Allyl chloride
Option C (Allyl chloride) is correct because the p-electrons of the halogen are not directly conjugated with the pi system of the double bond. The chlorine is attached to an sp3 carbon adjacent to the double bond.
322 Easy
322 of 392
Remembering +4 | -1
Carbon and hydrogen are estimated in organic compounds by
View answer and explanation
Correct option: C
Leibig's method
Option C (Leibig's method) is correct because Leibig's method is used for the estimation of carbon and hydrogen in organic compounds.
323 Medium
323 of 392
Application +4 | -1
Which one of the following will show optical isomerism?
View answer and explanation
Correct option: B
H3C−C∣∣OHH−CO2H{\mathrm{H}_3}\mathrm{C} - \mathop {\mathop \mathrm{C}\limits_|^| }\limits_{OH}^\mathrm{H} - \mathrm{C}{\mathrm{O}_2}\mathrm{H}
Option B (H3C - CH(OH) - CO2H) is correct because the central carbon atom is bonded to four different groups (H, CH3, OH, and CO2H), making it a chiral center.
324 Hard
324 of 392
Understanding +4 | -1
Arrange the following in order of reactivity towards sulphonation with fuming sulphuric acid
a) Benzene \quad b) Toluene \quad c) Methoxy benzene \quad d) Chloro benzene
View answer and explanation
Correct option: B
c > b > a > d
Option B (c > b > a > d) is correct because methoxybenzene (c) is the most activating group due to the +M effect of -OCH3, followed by toluene (b) with a +I effect of -CH3, then benzene (a), and finally chlorobenzene (d) which is deactivating due to the -I effect of -Cl.
325 Easy
325 of 392
Understanding +4 | -1
In the hydrocarbon .CH3   −C CH  =5 CH   −4 CH2−3 C   ≡ 2 CH1_{C{H_3}\,\,\, - }^C\,_{CH\,\, = }^5\,_{CH\,\,\, - }^4\,_{C{H_2} - }^3\,_{C\,\,\, \equiv \,}^2\,_{CH}^1 the state of hybridisation of 1, 3 and 5 are in the following sequence
View answer and explanation
Correct option: B
SP,SP3,SP2SP,S{P^3},S{P^2}
Option B (SP,SP3,SP2SP,S{P^3},S{P^2}) is correct because carbon 1 is sp hybridized, carbon 3 is sp3 hybridized, and carbon 5 is sp2 hybridized.
326 Easy
326 of 392
Application +4 | -1
Which of the following molecules represents the order of hybridization SP2,SP2,SP,SPS{P^2},S{P^2},SP,SP from left to right atoms
View answer and explanation
Correct option: B
CH2=CH−C≡CHC{H_2} = CH - C \equiv CH
Option B (CH2=CH−C≡CHC{H_2} = CH - C \equiv CH) is correct because the hybridization of the carbon atoms from left to right is SP2, SP2, SP, SP.
327 Hard
327 of 392
Analyzing +4 | -1
Correct order of acidity is as follows
View answer and explanation
Correct option: D
C2H2<H2O<Phenol<H2CO3{C_2}{H_2} < {H_2}O < {\text{Phenol}} < {H_2}C{O_3}
Option D (C2H2<H2O<Phenol<H2CO3{C_2}{H_2} < {H_2}O < {\text{Phenol}} < {H_2}C{O_3}) is correct because the acidity order is based on the stability of the conjugate base and the strength of the acid.
328 Medium
328 of 392
Analyzing +4 | -1
How many isomers of C5H11OH{C_5}{H_{11}}OH will be primary alcohols?
View answer and explanation
Correct option: B
4
Option A (4) is correct because there are four isomers of C5H11OHC_5H_{11}OH that are primary alcohols.
329 Easy
329 of 392
Understanding +4 | -1
Overlap of which of the following atomic orbitals would be maximum to form the strongest covalent bond?
View answer and explanation
Correct option: B
1s−2p(σ)1s - 2p\left( \sigma \right)
Option B (1s - 2p(σ)) is correct because sigma bonds formed by the overlap of s and p orbitals are generally stronger than those formed by s-s overlap, and much stronger than pi bonds from p-p overlap.
330 Medium
330 of 392
Remembering +4 | -1
Which is most commonly used to dry organic liquids?
View answer and explanation
Correct option: B
Sodium
The correct answer is Sodium because it reacts with water present in the organic liquid to form hydrogen gas and sodium hydroxide, effectively drying the liquid.
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