Hydrogen practice · Mixed difficulty

Option A is correct because industrially, ${\mathrm{H}_\mathrm{2}}{\mathrm{O}_\mathrm{2}}$ is obtained from 2 – Ethyl anthraquinol.

Option C (${Pbs}+4 {H}_2 {O}_2 \rightarrow {PbSO}_4+4 {H}_2 {O}$) is correct because ${H}_2 {O}_2$ oxidizes $PbS$ to ${PbSO}_4$, thus acting as an oxidizing agent.

Option A (Hydrated sodium aluminium silicate) is correct because Permutit is a synthetic zeolite, which is a hydrated sodium aluminum silicate.

Option A (10 V) is correct because the volume strength is calculated by dividing the concentration in g/L by the equivalent weight and multiplying by 11.2.

Option B is correct because in solid hydrogen, the molecules are held together by weak van der Waals forces, which are intermolecular forces arising from temporary fluctuations in electron distribution.

Option B (Oxidising $\mathrm{PbS}$ to $\mathrm{PbS}{\mathrm{O}_4}$) is correct because ${\mathrm{H}_2}{\mathrm{O}_2}$ oxidizes black lead sulfide (PbS) to white lead sulfate ($\mathrm{PbS}{\mathrm{O}_4}$), restoring the painting's color.

Option D ($F{e_2}{O_3} + C{r_2}{O_3}$) is correct because it is the catalyst used in the Bosch process for the manufacture of ${H_2}$.

Option D (They are covalent in nature) is correct because saline hydrides are ionic, not covalent, in nature.

Option A ($1:1$) is correct because zinc reacts with both sulfuric acid and sodium hydroxide to produce hydrogen gas in a 1:1 molar ratio.

Option B (If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion) is correct because both statements are true, but the reason doesn't explain why we feel cold.

Option C (Blue) is correct because ${\mathrm{H}_2}{\mathrm{O}_2}$ oxidizes $Cr^{3+}$ to $CrO_5$ which has a blue color when dissolved in ether.

Option B is correct because sodium carbonate reacts with both calcium and magnesium ions to form insoluble carbonates, removing both temporary and permanent hardness.

Option D ($Fe$) is correct because iron reacts with steam to produce hydrogen gas, but does not react with cold water.

Option C (${H_2}$ liberated at anode) is correct because in molten ionic hydrides, the hydride ion (${H^-}$) migrates to the anode and gets oxidized to form hydrogen gas.

Option A is correct because magnesium bicarbonate decomposes upon boiling to form magnesium hydroxide, which precipitates out.

Option C (${111.5^0}$) is correct because the dihedral angle in gaseous H2O2 is approximately 111.5 degrees.

Option C (Metallic hydride) is correct because $\mathrm{Ti}{\mathrm{H}_{1.73}}$ is a non-stoichiometric hydride formed by transition metals, which are metallic hydrides.

Option A (${C_2}{D_2}$) is correct because calcium carbide reacts with heavy water to produce deuterated acetylene (${C_2}{D_2}$).

Option A is correct because the tailing of mercury is a laboratory test specifically for ${\mathrm{O}_3}$.

Option C is correct because the reaction of zinc with aqueous alkali produces dihydrogen in the laboratory.

Option A ($10,\mathrm{ }10,\mathrm{ }10$) is correct because a molecule of heavy water ($D_2O$) contains 2 deuterium atoms (2 protons + 2 neutrons each) and 1 oxygen atom (8 protons + 8 neutrons + 8 electrons). Therefore, the total number of protons is 2+2+8=10, electrons is 8+2=10 and neutrons is 2+2+6=10.

Option D (Heated aluminium oxide) is correct because aluminium oxide is very stable and cannot be reduced by hydrogen gas.

Option B (Only one third of a second) is correct because atomic hydrogen is highly reactive and has a very short lifespan, typically around one-third of a second.

Option D is correct because the O-O-H bond angle in H2O is approximately 97 degrees due to the two lone pairs on the oxygen atom causing greater repulsion and reducing the bond angle from the ideal tetrahedral angle.

Option D (More in ${\mathrm{H}_2}\mathrm{O}$) is correct because ${\mathrm{H}_2}\mathrm{O}$ has a slightly higher dielectric constant and better solvating power for ionic compounds like $\mathrm{NaCl}$.

Option B (water gas) is correct because water gas is primarily used in Bosch's process for hydrogen production.

Option D is correct because water can act as both a proton donor (acid) and a proton acceptor (base), making it an amphoteric solvent.

Option D (All of these) is correct because hydrogen can be manufactured through Lane's process, Bosch process, and from natural gas.

Option A ($\mathrm{C}$) is correct because carbon is generally unreactive with NaOH under normal conditions.

Option B is correct because the structure of ${\mathrm{H}_\mathrm{2}}{\mathrm{O}_\mathrm{2}}$ is non - planar.