${\rm{HBr}}$ reacts with${\rm{C}}{{\rm{H}}_2}$=${\rm{CH}}$—${\rm{OC}}{{\rm{H}}_3}$ under anhydrous conditions at room temperature to give:

${{\rm{H}}_3}{\rm{C}}$—${\rm{CHBr}}$—${\rm{OC}}{{\rm{H}}_3}$

${\rm{C}}{{\rm{H}}_3}{\rm{CHO}}$ and C${\rm{C}}{{\rm{H}}_3}{\rm{CHO}}$

${\rm{BrC}}{{\rm{H}}_2}{\rm{CHO}}$ and ${\rm{C}}{{\rm{H}}_3}{\rm{OH}}$

${\rm{BrC}}{{\rm{H}}_2}$—${\rm{C}}{{\rm{H}}_2}$—${\rm{OC}}{{\rm{H}}_3}$

${\left( {{\rm{C}}{{\rm{H}}_3}} \right)_3}{\rm{CONa}}$ on reaction with ${\rm{C}}{{\rm{H}}_3}{\rm{Br}}$ will give:

${\left( {{\rm{C}}{{\rm{H}}_3}} \right)_3}{\rm{COC}}{{\rm{H}}_3}$

${\left( {{\rm{C}}{{\rm{H}}_3}} \right)_3}{\rm{COC}}{\left( {{\rm{C}}{{\rm{H}}_3}} \right)_3}$

${\rm{C}}{{\rm{H}}_3}{\rm{OC}}{{\rm{H}}_3}$

${\rm{C}}{{\rm{H}}_3}{\rm{C}}{{\rm{H}}_2}{\rm{OC}}{{\rm{H}}_2}{\rm{C}}{{\rm{H}}_3}$

Back to ALCOHOLS & PHENOLS & ETHERS

Your Progress

0 / 180 Answered

Correct

Incorrect

Accuracy

NEET • CHEMISTRY • ALCOHOLS & PHENOLS & ETHERS

Alcohols & phenols & ethers practice · Mixed difficulty

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

The practice player uses single-correct-answer MCQs. Chapter quizzes help you review a topic; they are not full-length NEET mock papers.

Take a chapter quiz →

Showing 121-150 of 180 questions

Preparing practice and saved progress…

121 Hard

121 of 180

Remembering +4 | -1

Pepperment can be extracted from plant sources by using solvents like:

View answer and explanation

Correct option: D

{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{OH}

Option D (

{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{OH}

) is correct because ethanol is a common solvent used to extract peppermint oil from plant sources.

122 Medium

122 of 180

Analyzing +4 | -1

Which of the property given below is not associated with glycerol?

View answer and explanation

Correct option: A

Formation of water and

\mathrm{C}{\mathrm{O}_2}

on reduction

Option A is correct because glycerol does not form water and carbon dioxide upon reduction; it typically undergoes reactions like esterification or ether formation.

123 Medium

123 of 180

Remembering +4 | -1

Ether fire can be extinguished by:

View answer and explanation

Correct option: D

All of these

Option D (All of these) is correct because sand, pyrene, and CO2 can all be used to extinguish ether fires by smothering the flames or inhibiting the combustion process.

124 Medium

124 of 180

Understanding +4 | -1

Which of the following gives immediate turbidity with Lucas reagent?

View answer and explanation

Correct option: A

2 – methyl – propan – 2 – ol

Option A (2 – methyl – propan – 2 – ol) is correct because tertiary alcohols react fastest with Lucas reagent (HCl and ZnCl2) due to the formation of a stable tertiary carbocation intermediate.

125 Hard

125 of 180

Understanding +4 | -1

The number of methoxy groups in a compound can be determined by treating it with:

View answer and explanation

Correct option: A

\mathrm{HI}

and

\mathrm{AgN}{\mathrm{O}_3}

Option A (

\mathrm{HI}

and

\mathrm{AgN}{\mathrm{O}_3}

) is correct because HI cleaves methoxy groups to form methyl iodide, which then reacts with silver nitrate to form a precipitate of silver iodide.

126 Medium

126 of 180

Analyzing +4 | -1

Which of the following is not isomeric with diethyl ether?

View answer and explanation

Correct option: D

Butan-2-one

Option D (Butan-2-one) is correct because it has a different molecular formula (

C_4H_8O

) compared to diethyl ether (

C_4H_{10}O

127 Hard

127 of 180

Analyzing +4 | -1

An alcohol (A) on dehydration gives (B) which on ozonolysis gives acetone and formaldehyde. (A) and (B) are respectively

View answer and explanation

Correct option: C

\left(\mathrm{CH}_3\right)_3 \mathrm{COH}

and

\left(\mathrm{CH}_3\right)_2 \mathrm{C}=\mathrm{CH}_2

Option C is correct because (CH3)3COH on dehydration gives (CH3)2C=CH2, which on ozonolysis gives acetone and formaldehyde.

128 Medium

128 of 180

Application +4 | -1

\mathrm{HBr}

reacts with

\mathrm{C}{\mathrm{H}_2}

\mathrm{CH}

—

\mathrm{OC}{\mathrm{H}_3}

under anhydrous conditions at room temperature to give:

View answer and explanation

Correct option: D

{\mathrm{H}_3}\mathrm{C}

—

\mathrm{CHBr}

—

\mathrm{OC}{\mathrm{H}_3}

The correct answer is D (

{\mathrm{H}_3}\mathrm{C}

—

\mathrm{CHBr}

—

\mathrm{OC}{\mathrm{H}_3}

) because the reaction follows Markovnikov's rule, where the hydrogen adds to the carbon with more hydrogens and the bromine adds to the other carbon.

129 Medium

129 of 180

Application +4 | -1

The compound

B\;

formed in the following sequence of reactions,

\mathrm{C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}\mathrm{C}{\mathrm{H}_2}\mathrm{OH}\xrightarrow{{\mathrm{PC}{\mathrm{l}_5}}}A\xrightarrow{{\mathrm{Alc}.\mathrm{\;NaOH}}}B

will be:

View answer and explanation

Correct option: B

Propene

Option B (Propene) is correct because the reaction sequence involves converting an alcohol to an alkyl halide, followed by elimination to form an alkene.

130 Hard

130 of 180

Remembering +4 | -1

Which of the following is an anaesthetic?

View answer and explanation

Correct option: D

All of these

Option D (All of these) is correct because ether, thiobarbiturates, and trichloromethane (chloroform) have all been used as anesthetic agents.

131 Easy

131 of 180

Application +4 | -1

Acetylene and formaldehyde interact in the presence of copper acetylide as a catalyst to furnish the compound:

View answer and explanation

Correct option: A

Butyne-1, 4-diol

Option A (Butyne-1, 4-diol) is correct because acetylene reacts with formaldehyde in the presence of a copper acetylide catalyst to form but-2-yne-1,4-diol.

132 Medium

132 of 180

Application +4 | -1

{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_3}\mathrm{CONa}

on reaction with

\mathrm{C}{\mathrm{H}_3}\mathrm{Br}

will give:

View answer and explanation

Correct option: D

{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_3}\mathrm{COC}{\mathrm{H}_3}

The correct answer is D (

{{\left( {\mathrm{C}{\mathrm{H}_3}} \right)}_3}\mathrm{COC}{\mathrm{H}_3}}

) because tert-butoxide reacts with methyl bromide via an SN2 mechanism to form tert-butyl methyl ether.

133 Easy

133 of 180

Understanding +4 | -1

Phenol on sulphonation gives:

View answer and explanation

Correct option: D

Mixture of

o - \,\mathrm{and}\,p -

phenol sulphonic acids

Option D is correct because phenol on sulfonation gives a mixture of ortho- and para-phenol sulfonic acids.

134 Easy

134 of 180

Remembering +4 | -1

Phenol is:

View answer and explanation

Correct option: B

Weakly acidic

Option B is correct because phenol is weakly acidic due to the resonance stabilization of the phenoxide ion.

135 Easy

135 of 180

Remembering +4 | -1

Compound used for covering wounds caused by bite of mad dog is:

View answer and explanation

Correct option: C

Phenol

Option C is correct because phenol is used as a disinfectant and antiseptic for wounds, including those caused by animal bites.

Explore Other Chapters in CHEMISTRY

View All →

CHEMICAL BONDING & MOLECULAR STRUCTURE 595 MCQs THERMODYNAMICS 583 MCQs STRUCTURE OF ATOM 499 MCQs CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES 429 MCQs Equilibrium 412 MCQs STATES OF MATTER 410 MCQs

136 Easy

136 of 180

Understanding +4 | -1

Phenol is more acidic than cyclohexanol because:

View answer and explanation

Correct option: A

Benzene ring exists in resonance

Option A (Benzene ring exists in resonance) is correct because the resonance in the benzene ring of phenol stabilizes the phenoxide ion, making phenol more acidic than cyclohexanol.

137 Easy

137 of 180

Application +4 | -1

In which of the following reactions the product is an ether?

View answer and explanation

Correct option: D

{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{Cl} + {\mathrm{C}_2}{\mathrm{H}_5}\mathrm{ONa}

Option D (

{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{Cl} + {\mathrm{C}_2}{\mathrm{H}_5}\mathrm{ONa}

) is correct because it represents a Williamson ether synthesis, which directly produces an ether.

138 Easy

138 of 180

Understanding +4 | -1

The ease of dehydrohalogenation of alkyl halide with alcoholic KOH is

View answer and explanation

Correct option: B

{3^ \circ } > {2^ \circ } > {1^ \circ }

Option B (

{3^ \circ } > {2^ \circ } > {1^ \circ }

) is correct because the stability of the alkene formed during dehydrohalogenation increases with the degree of substitution.

139 Easy

139 of 180

Analyzing +4 | -1

If the boiling point of ethanol (molecular weight=46) is 78

^ \circ C

, what is the boiling point of diethyl ether?
(molecular weight=74)

View answer and explanation

Correct option: D

^ \circ C

Option D (34

^ \circ C

) is correct because diethyl ether has weaker intermolecular forces (van der Waals) than ethanol (hydrogen bonding), resulting in a lower boiling point.

140 Medium

140 of 180

Understanding +4 | -1

Ethyl alcohol reacts with following to form a compound of fruity smell:

View answer and explanation

Correct option: C

\mathrm{C}{\mathrm{H}_3}\mathrm{COOH}

Option C (

\mathrm{CH}_3\mathrm{COOH}

) is correct because ethyl alcohol reacts with acetic acid to form ethyl acetate, an ester with a fruity smell.

141 Easy

141 of 180

Analyzing +4 | -1

The strongest acid among the following aromatic compounds is:

View answer and explanation

Correct option: C

para

-nitrophenol

Option C (

para

-nitrophenol) is correct because the nitro group is a strong electron-withdrawing group that stabilizes the phenoxide ion through resonance and inductive effects, making it the most acidic.

142 Easy

142 of 180

Understanding +4 | -1

Ethyl iodide on treatment with dry

\mathrm{A}{\mathrm{g}_2}\mathrm{O}

will yield:

View answer and explanation

Correct option: B

Diethyl ether

Option B (Diethyl ether) is correct because ethyl iodide reacts with dry Ag2O to form diethyl ether via Williamson's ether synthesis.

143 Medium

143 of 180

Remembering +4 | -1

Methylated spirit is:

View answer and explanation

Correct option: B

Methanol containing some pyridine

Option A (Methanol containing some pyridine) is correct because methylated spirit is ethanol made unfit for drinking by adding methanol and pyridine.

144 Medium

144 of 180

Understanding +4 | -1

Most viscous among the following is:

View answer and explanation

Correct option: D

Propane-1,2,3-triol

Option D (Propane-1,2,3-triol) is correct because viscosity increases with the number of hydroxyl groups due to increased hydrogen bonding.

145 Medium

145 of 180

Understanding +4 | -1

A simple method to remove peroxides from ethes is to treat them with an aqueous solution of

View answer and explanation

Correct option: A

Option A (KI) is correct because KI reduces peroxides to ethers and itself gets oxidized to iodine.

146 Hard

146 of 180

Remembering +4 | -1

The most important ingredient of dynamite is:

View answer and explanation

Correct option: B

Glycerine trinitrate

Option B (Glycerine trinitrate) is correct because glycerine trinitrate, also known as nitroglycerin, is the primary explosive component of dynamite.

147 Medium

147 of 180

Remembering +4 | -1

A solution of

Cr{O_5}

in amyl alcohol has a ______
colour

View answer and explanation

Correct option: A

Blue

Option A is correct because a solution of CrO5 in amyl alcohol has a blue color.

148 Hard

148 of 180

Application +4 | -1

Which of the following reagents can be used for preparation of cumene?

(i)

{C}_6 {H}_6, {Cl}_2

, hv; Mg.THF; acetone.

(ii)

{C}_6 {H}_6, {CH}_3 {CH}_2 {CH}_2 {Cl}, {AlCl}_3

.

(iii)

{C}_6 {H}_6, {CH}_3 {CHClCH}_3, {AlCl}_3

.

(iv)

{C}_6 {H}_6, {CH}_3 {CH}_2 {Cl}, {AlCl}_3

;

View answer and explanation

Correct option: B

(ii) and (iii)

Option B ((ii) and (iii)) is correct because cumene (isopropylbenzene) can be prepared by Friedel-Crafts alkylation of benzene with either 1-chloropropane or 2-chloropropane in the presence of AlCl3.

149 Easy

149 of 180

Application +4 | -1

The best reagent to convert pent-3-en-2-ol into pent-3-en-2-one is:

View answer and explanation

Correct option: D

Pyridinium chlorochromate

Option D (Pyridinium chlorochromate) is correct because PCC is a mild oxidizing agent that can convert a secondary alcohol to a ketone without oxidizing the alkene.

150 Easy

150 of 180

Remembering +4 | -1

Which of the following is dihydric alcohol?

View answer and explanation

Correct option: B

Ethylene glycol

Option B (Ethylene glycol) is correct because it contains two hydroxyl (-OH) groups.

Revision notes and key takeaways

Review ALCOHOLS & PHENOLS & ETHERS in your textbook or class notes, then use this set to check your understanding.

Showing 121-150 of 180 questions

Your Progress

Alcohols & phenols & ethers practice · Mixed difficulty

Explore Other Chapters in CHEMISTRY

Continue Your Practice

Your practice