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NEET • CHEMISTRY • ALCOHOLS & PHENOLS & ETHERS

Alcohols & phenols & ethers practice · Mixed difficulty

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61 Easy
61 of 180
Understanding +4 | -1
Which of the following is simple ether?
View answer and explanation
Correct option: D
MeOMe\mathrm{MeOMe}
Option D (MeOMe) is correct because MeOMe (dimethyl ether) is the simplest ether, consisting of two methyl groups bonded to an oxygen atom.
62 Hard
62 of 180
Application +4 | -1
Propene, CH3CH=CH2{CH}_3 {CH}={CH}_2 can be converted into 1-propanol by oxidation. Indicate which set of reagents amongst the following is ideal to effect the above conversion ?
View answer and explanation
Correct option: C
B6H6{B}_6 {H}_6 and alk. H2O2{H}_2 {O}_2
Option C (CH3CH2MgBr+CH3CH2COCH2CH3\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{MgBr}+\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COCH}_2 \mathrm{CH}_3) is correct because the Grignard reagent adds to the ketone to form a tertiary alcohol after hydrolysis.
63 Easy
63 of 180
Remembering +4 | -1
Carbolic acid is
View answer and explanation
Correct option: D
C6H5OH{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{OH}
Option D is correct because the chemical formula for carbolic acid (phenol) is C6H5OH.
64 Medium
64 of 180
Analyzing +4 | -1
The correct order of acid strength of the following compounds is

V. Phenol

VI. pp-cresol

VII. mm-nitrophenol

VIII. pp-nitrophenol
View answer and explanation
Correct option: B
IV > III > I > II
Option B (IV > III > I > II) is correct because electron-withdrawing groups increase acidity, and nitro groups are stronger electron-withdrawing groups than methyl groups.
65 Easy
65 of 180
Remembering +4 | -1
The formula of phenoxy benzene is:
View answer and explanation
Correct option: B
C6H5−O−C6H5{\mathrm{C}_6}{\mathrm{H}_5} - \mathrm{O} - {\mathrm{C}_6}{\mathrm{H}_5}
Option B (C6H5−O−C6H5{\mathrm{C}_6}{\mathrm{H}_5} - \mathrm{O} - {\mathrm{C}_6}{\mathrm{H}_5}) is correct because phenoxybenzene is an ether where an oxygen atom is bonded to two phenyl groups.
66 Medium
66 of 180
Remembering +4 | -1
In fermentation by zymase, alcohol and CO2\mathrm{C}{\mathrm{O}_2} are obtained from
View answer and explanation
Correct option: B
Glucose
Option B is correct because glucose is fermented by zymase to produce alcohol and carbon dioxide.
67 Hard
67 of 180
Analyzing +4 | -1
Assertion: Tertiary alcohols gets converted into an alkene instead of a carbonyl Compounds in the presence of heated metallic copper.

Reason: Tertiary alcohols prefer to undergo dehydrogenation instead of dehydration in the presence of heated copper.
View answer and explanation
Correct option: C
Assertion is correct, but reason is wrong statement.
Option C is correct because tertiary alcohols undergo dehydration to form alkenes in the presence of heated copper, not dehydrogenation to form carbonyl compounds.
68 Easy
68 of 180
Analyzing +4 | -1
Assertion (A): Phenoxide ion is more stable than carboxylate ion.
Reason (R): The –ve charge is delocalized over two electronegative atoms in carboxylate ion.
View answer and explanation
Correct option: B
Both A & R are correct and not correct explanation
Option B (Both A & R are correct and not correct explanation) is correct because while both the assertion and the reason are true, the reason does not fully explain why the phenoxide ion is more stable.
69 Medium
69 of 180
Remembering +4 | -1
Purity of ether before using it as anaesthetic agent is tested by:
View answer and explanation
Correct option: A
KI+\mathrm{KI} + starch
Option A (KI+\mathrm{KI} + starch ) is correct because the presence of peroxides in ether, which can form upon exposure to air, is detected by reaction with KI, liberating iodine which turns starch blue.
70 Hard
70 of 180
Remembering +4 | -1
Nobel’s oil is:
View answer and explanation
Correct option: C
Explosive
Option C (Explosive) is correct because Nobel's oil is another name for nitroglycerin, which is a powerful explosive.
71 Easy
71 of 180
Analyzing +4 | -1
C−O−C\mathrm{C} - \mathrm{O} - \mathrm{C}angle would be maximum in
View answer and explanation
Correct option: D
(CH3)2CH−O−CH(CH3)2{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{CH} - \mathrm{O} - \mathrm{CH}{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}
Option D ((CH3)2CH−O−CH(CH3)2{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{CH} - \mathrm{O} - \mathrm{CH}{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}) is correct because the bulky isopropyl groups attached to the oxygen atom experience greater steric repulsion, leading to a larger bond angle.
72 Hard
72 of 180
Application +4 | -1
Identify the major product that is obtained on treatment of CH3CH2CH(F)CH3\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}(\mathrm{F}) \mathrm{CH}_3 with CH3O−/CH3OH\mathrm{CH}_3 \mathrm{O}^{-} / \mathrm{CH}_3 \mathrm{OH} is
View answer and explanation
Correct option: B
CH3CH=CHCH3\mathrm{CH}_3 \mathrm{CH}=\mathrm{CHCH}_3
Option B (CH3CH=CHCH3\mathrm{CH}_3 \mathrm{CH}=\mathrm{CHCH}_3) is correct because the major product of the reaction is the more stable alkene, which is the more substituted alkene (Zaitsev's rule).
73 Hard
73 of 180
Remembering +4 | -1
Scientific aspect of fermentation was first studied by:
View answer and explanation
Correct option: C
Buchner
Option C (Buchner) is correct because Eduard Buchner demonstrated that fermentation could occur in the absence of living cells, marking a significant scientific advancement.
74 Easy
74 of 180
Analyzing +4 | -1
Which one can differentiate between C2H5OH{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{OH} and CH3OH\mathrm{C}{\mathrm{H}_3}\mathrm{OH}?
View answer and explanation
Correct option: B
Na2CO3+  I2\mathrm{N}{\mathrm{a}_2}\mathrm{C}{\mathrm{O}_3} + \mathrm{\;}{\mathrm{I}_2}
Option B (N2CO3+  I2{\mathrm{N}_2}\mathrm{C}{\mathrm{O}_3} + \mathrm{\;}{\mathrm{I}_2}) is correct because it can be used in the iodoform test, which differentiates between ethanol and methanol.
75 Hard
75 of 180
Analyzing +4 | -1
Consider the following compounds.

(A) Phenol

(B) Propyne

(C) Benzene sulphonic acid

(D) Benzoic acid

(E) Cyclopentadiene

(F) Ethane

(G) Picric acid

(H) 4-Nitro Cyclohexanol

If (X)(\mathrm{X}) is the total number of compounds which evolve H2\mathrm{H}_2 gas with Na\mathrm{Na} metal and (Y)(\mathrm{Y}) is the total number of compounds which evolve CO2\mathrm{CO}_2 gas with NaHCO3\mathrm{NaHCO}_3. Then find the value of (X−Y)(\mathrm{X}-\mathrm{Y}).
View answer and explanation
Correct option: A
4
The correct answer is A (4) because Phenol, Propyne, Benzoic acid, and Cyclopentadiene evolve H2 gas with Na metal, while only Benzoic acid reacts with NaHCO3 to evolve CO2 gas. Therefore, X = 4 and Y = 1, so X - Y = 4.
76 Easy
76 of 180
Remembering +4 | -1
Phthalein test is characteristics of ….and is given by it.
View answer and explanation
Correct option: B
Phenols
Option B is correct because the phthalein test is a characteristic reaction of phenols.
77 Hard
77 of 180
Understanding +4 | -1
Which one of the following does not undergo iodoform reaction
View answer and explanation
Correct option: C
Diethyl ketone
Option C (Diethyl ketone) is correct because it does not contain a CH3CO−CH_3CO- group or a CH3CH(OH)−CH_3CH(OH)- group which are necessary for the iodoform reaction.
78 Hard
78 of 180
Application +4 | -1
CH3−CH2−CH=CH2⟶xCH3CH2−CH2−CH2OH{CH}_3-{CH}_2-{CH}={CH}_2 \stackrel{x}{\longrightarrow} {CH}_3 {CH}_2-{CH}_2-{CH}_2 {OH}

What is the suitable reagent x?x?
View answer and explanation
Correct option: B
B2H6∣THF,H2O2∣OH−{B}_2 {H}_6\left|{THF}, {H}_2{O}_2\right| {OH}^{-}
Option B (B2H6∣THF,H2O2∣OH−{B}_2 {H}_6\left|{THF}, {H}_2{O}_2\right| {OH}^{-}) is correct because it represents hydroboration-oxidation, which converts an alkene to an alcohol with anti-Markovnikov regioselectivity.
79 Easy
79 of 180
Remembering +4 | -1
The alcohol manufactured from water gas is
View answer and explanation
Correct option: A
CH3OH\mathrm{C}{\mathrm{H}_3}\mathrm{OH}
Option A (CH3OH\mathrm{C}{\mathrm{H}_3}\mathrm{OH}) is correct because methanol is manufactured from water gas (CO + H₂).
80 Easy
80 of 180
Remembering +4 | -1
Picric acid is a yellow coloured compound. Its chemical name is:
View answer and explanation
Correct option: B
2,4,6-trinitrophenol
Option B is correct because picric acid is 2,4,6-trinitrophenol.
81 Easy
81 of 180
Application +4 | -1
To prepare an ether by Williamson’s synthesis, the reactants needed are
View answer and explanation
Correct option: C
Sodium tertiary butoxide and ethyl bromide
Option C (Sodium tertiary butoxide and ethyl bromide) is correct because it follows the Williamson ether synthesis which requires a primary alkyl halide (ethyl bromide) and an alkoxide (sodium tert-butoxide).
82 Medium
82 of 180
Understanding +4 | -1
Which one has highest boiling point?
View answer and explanation
Correct option: C
Butan-1-ol
Option C (Butan-1-ol) is correct because alcohols have higher boiling points than alkanes and alkenes of comparable molecular weight due to hydrogen bonding.
83 Medium
83 of 180
Analyzing +4 | -1
A compound XX with molecular formula C3H8O{\mathrm{C}_3}{\mathrm{H}_8}\mathrm{O} can be oxidised to a compound YY with the molecular formula C3H6O2{\mathrm{C}_3}{\mathrm{H}_6}{\mathrm{O}_2}. XX is most likely to be:
View answer and explanation
Correct option: A
Primary alcohol
Option A (Primary alcohol) is correct because primary alcohols can be oxidized to carboxylic acids, while secondary alcohols are oxidized to ketones, and aldehydes/ketones cannot be further oxidized to carboxylic acids with the same number of carbon atoms.
84 Hard
84 of 180
Application +4 | -1
An ether contains 60%60 \% carbon and 13.3%13.3 \% hydrogen. Formula of the ether is
View answer and explanation
Correct option: B
C3H8O{C_3}{H_8}O
Option B (C3H8O{C_3}{H_8}O) is correct because the empirical formula derived from the percentage composition matches the molecular formula of an ether with three carbons.
85 Medium
85 of 180
Analyzing +4 | -1
An unknown compound dissolves in H2SO4{H}_2 {SO}_4, but does not decolourise Br2{Br}_2 water and does not react with Na{Na}. Which of the following classes of molecules would behave in this manner?
View answer and explanation
Correct option: D
Ether
Option D (Ether) is correct because ethers dissolve in strong acids like H2SO4H_2SO_4 due to protonation of the oxygen atom, but they don't react with Br2Br_2 water (unlike alkenes/phenols) or Na (unlike alcohols/phenols).
86 Medium
86 of 180
Analyzing +4 | -1
Assertion: Anisole reacts with HIHI to give phenol and chloromethane.

Reason: The −OCH3-OCH_3 group in anisole enriches the electron density in the ring through Resonance.
View answer and explanation
Correct option: B
Both assertion and reason are correct statements, but reason is not the correct explanation of the assertion.
Option B is correct because both the assertion and reason are correct, but the reason (resonance) doesn't directly explain why anisole reacts with HI to give phenol and methyl iodide (not chloromethane). The reaction proceeds via cleavage of the ether bond by HI.
87 Easy
87 of 180
Analyzing +4 | -1
CH3CH2OH\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH} and C6H5OH\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH} can be distinguished by
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because each of the listed reagents can be used to distinguish between ethanol and phenol due to their different chemical properties and reactivity.
88 Medium
88 of 180
Remembering +4 | -1
The main product obtained from phenol with PCl5{PCl}_5 is
View answer and explanation
Correct option: D
Triphenyl phosphate
Option D is correct because phenol reacts with PCl5 to form triphenyl phosphate.
89 Medium
89 of 180
Remembering +4 | -1
Lucas reagent is
View answer and explanation
Correct option: A
Conc. HCI\mathrm{HCI} and anhydrous ZnCI2\mathrm{ZnC}{\mathrm{I}_2}
Option A (Conc. HCI\mathrm{HCI} and anhydrous ZnCI2\mathrm{ZnC}{\mathrm{I}_2}) is correct because Lucas reagent is a solution of concentrated hydrochloric acid and anhydrous zinc chloride.
90 Medium
90 of 180
Understanding +4 | -1
Which of the following compounds is resistant to nucleophilic attack by hydroxyl ions?
View answer and explanation
Correct option: C
Diethyl ether
Option C (Diethyl ether) is correct because ethers lack a good leaving group and are not susceptible to nucleophilic attack by hydroxyl ions under normal conditions.
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