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JEE • PHYSICS • WORK-ENERGY-POWER

Work-energy-power practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 151-180 of 496 questions

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151 Medium
151 of 496
Analyzing +4 | -1
Two bodies A and B of definite shape (dimensions of bodies are not ignored). A is moving with speed of 10 ms−1\mathrm{m}{\mathrm{s}^{ - 1}} and B is in rest, collide elastically. The
View answer and explanation
Correct option: B
They may move perpendicular to each other
They may move perpendicular to each other (Option B) because in an oblique elastic collision, the bodies can move at right angles to each other.
152 Medium
152 of 496
Understanding +4 | -1
Assertion (A): The change in kinetic energy of a particle is equal to work done on it by the resultant force.
Reason (R): Change in kinetic energy is equal to work done in case of system of one particle.
View answer and explanation
Correct option: A
If both Assertion and Reason are true and Reason is correct explanation of Assertion.
Option A is correct because the work-energy theorem states that the net work done on a particle equals its change in kinetic energy, and this applies to single-particle systems.
153 Medium
153 of 496
Understanding +4 | -1
For a particle in non-uniform accelerated circular motion
View answer and explanation
Correct option: D
Velocity is transverse and acceleration has both radial and transverse components
Option D is correct because in non-uniform circular motion, the velocity is always tangential, and the acceleration has both radial (centripetal) and tangential components.
154 Medium
154 of 496
Application +4 | -1
A man cycles up a hill, whose slope is 1 in 20 with a velocity of 6.4 kmh−16.4 \mathrm{~kmh}^{-1} along the hill. The weight of the man and the cycle is 98 kg98 \mathrm{~kg}. What work per minute is he doing? What is his horse power?
View answer and explanation
Correct option: A
5122.1 J,0.144 hp5122.1 \mathrm{~J}, 0.144 \mathrm{~hp}
Option A (5122.1 J,0.144 hp5122.1 \mathrm{~J}, 0.144 \mathrm{~hp}) is correct because it is the work per minute and horsepower calculated based on the given parameters.
155 Medium
155 of 496
Understanding +4 | -1
Assertion (A): No work is done by gravitational force if a body moves along a horizontal surface.
Reason (R): In horizontal motion, angle between gravity and displacement is 90∘90^{\circ}
View answer and explanation
Correct option: A
If both Assertion and Reason are true and Reason is correct explanation of Assertion.
Option A (If both Assertion and Reason are true and Reason is correct explanation of Assertion) is correct because the gravitational force is vertical, and if the displacement is horizontal, the angle between them is 90 degrees, resulting in zero work done.
156 Medium
156 of 496
Application +4 | -1
A ball is allowed to fall from a height of 10 m. If there is 40% loss of energy due to impact, then after one impact ball will go up to
View answer and explanation
Correct option: D
6 m
Option C (5.3×1012m5.3 \times {10^{12}}\mathrm{m}) is correct because it is the comet's farthest distance from the sun, calculated using Kepler's third law and the properties of an ellipse.
157 Medium
157 of 496
Application +4 | -1
The power of a water pump is 200 kW. If g=10ms−2\mathrm{g} = 10\mathrm{m}{\mathrm{s}^{ - 2}}, then the amount of water it can raise in 1 min to a height of 10 m is
View answer and explanation
Correct option: D
1200 L
Option D (1200 L) is correct because it is calculated by using the power formula P = mgh/t and solving for m.
158 Medium
158 of 496
Application +4 | -1
In position AA, kinetic energy of a particle is 60 J60 \mathrm{~J} and potential energy is −20 J-20 \mathrm{~J}. In position BB, kinetic energy is 100 J100 \mathrm{~J} and potential energy is 40 J40 \mathrm{~J}. Choose the correct statement, if the particle moves from AA to BB.
View answer and explanation
Correct option: C
Net work done by all the forces is 40 J40 \mathrm{~J}.
The correct answer is C (Net work done by all the forces is 40 J) because the net work done equals the change in kinetic energy.
159 Medium
159 of 496
Analyzing +4 | -1
If v,pv, p and EE denote velocity, linear momentum and kinetic energy of the particle respectively, then
View answer and explanation
Correct option: A
p=dEdvp=\frac{d E}{d v}
Option A (p=dEdvp=\frac{d E}{d v}) is correct because the derivative of kinetic energy with respect to velocity equals momentum.
160 Medium
160 of 496
Understanding +4 | -1
In an elastic collision of two particles, the
following is conserved
View answer and explanation
Correct option: D
Total kinetic energy of both the particles
Option D (Total kinetic energy of both the particles) is correct because in an elastic collision, both momentum and total kinetic energy of the system are conserved.
161 Medium
161 of 496
Application +4 | -1
A porter lifts a heavy suitcase of mass 80 kg and at the destination lowers it down by a distance of 80 cm with a constant velocity. Calculate the work done by the porter in lowering the suitcase. [Take, g=9.8 ms−2g = 9.8\,m{s^{ - 2}}]
View answer and explanation
Correct option: B
−627.2 J- 627.2\,J
Option B (−627.2 J- 627.2\,J) is correct because the work done by the porter is negative as the force applied is opposite to the direction of displacement.
162 Medium
162 of 496
Analyzing +4 | -1
The slope of the kinetic energy displacement curve of a particle in motion is
View answer and explanation
Correct option: C
Directly proportional to the acceleration
Option C is correct because the slope of the kinetic energy-displacement curve is directly proportional to the acceleration.
163 Medium
163 of 496
Application +4 | -1
An electric pump is used to fill an overhead tank of capacity 8 m38 \mathrm{~m}^3 kept at a height of 10 m10 \mathrm{~m} above the ground. If the pump takes 4 minutes to fill the tank by consuming 10 kW10 \mathrm{~kW} power, the efficiency of the pump should be

(Take g=10 ms−2g=10 \mathrm{~m} \mathrm{s}^{-2} )
View answer and explanation
Correct option: D
30%30 \%
Option A (4.17 m/s4.17\,m/s) is correct because it is calculated using conservation of momentum and the Rydberg formula.
164 Medium
164 of 496
Application +4 | -1
An electron of mass 9.0×10−28 g9.0 \times 10^{-28} \mathrm{~g} is moving at a speed of 1000 m/sec1000 \mathrm{~m} / \mathrm{sec}. Calculate its kinetic energy if the electron takes up this speed after moving a distance of 10 cm10 \mathrm{~cm} from rest. Also calculate the force in kg\mathrm{kg} weight acting on it.
View answer and explanation
Correct option: A
0.46×10−240.46 \times 10^{-24}
Option A (0.46×10−240.46 \times 10^{-24}) is correct because it is the force in kg weight acting on the electron, calculated using the electron's kinetic energy and the distance it traveled.
165 Medium
165 of 496
Application +4 | -1
A block having mass mm collides with an another stationary block having mass 2 m2 \mathrm{~m}. The lighter block comes to rest after collision. If the velocity of first block is vv, then the value of coefficient of restitution will must be
View answer and explanation
Correct option: A
0.5
Option A (0.5) is correct because the coefficient of restitution is calculated using the velocities of separation and approach.
166 Medium
166 of 496
Understanding +4 | -1
The net work done by kinetic friction
View answer and explanation
Correct option: C
May be negative or positive
Option C (May be negative or positive) is correct because kinetic friction always opposes motion, but the displacement direction determines the sign of the work.
167 Medium
167 of 496
Analyzing +4 | -1
A free body of mass 8 kg is travelling at 2 meter per second in a straight line. At a certain instant, the body splits into two equal parts due to internal explosion which releases 16 joules of energy. Neither part leaves the original line of motion finally, then
View answer and explanation
Correct option: B
One part comes to rest and the other moves in the same direction as that of the original body
Option B is correct. Applying conservation of momentum and energy, one part comes to rest, and the other continues in the original direction.
168 Medium
168 of 496
Understanding +4 | -1
When a body moves with a constant speed along a circle
View answer and explanation
Correct option: A
No work is done on it
Option A (No work is done on it) is correct because the centripetal force is perpendicular to the displacement, resulting in zero work done.
169 Medium
169 of 496
Application +4 | -1
Force on a particle moving in straight line is given by F⃗=6t2i^−3tj^\vec{F}=6 t^2 \hat{i}-3 t \hat{j} and velocity is v⃗=3t2i^+6tj^\vec{v}=3 t^2 \hat{i}+6 t \hat{j}. Find power at t=2t=2.
View answer and explanation
Correct option: A
216 W216 \mathrm{~W}
Option A (216 W216 \mathrm{~W}) is correct because it is calculated using the formula for power as the dot product of force and velocity at t=2.
170 Medium
170 of 496
Application +4 | -1
Two springs with spring constants k1=1200 N/mk_1=1200 \mathrm{~N} / \mathrm{m} and k2=500 N/mk_2=500 \mathrm{~N} / \mathrm{m} are stretched by the same force. The ratio of potential energy in the springs will be
View answer and explanation
Correct option: C
510\frac{5}{10}
The correct answer is C (510\frac{5}{10}), which simplifies to 5/12, because the potential energy is inversely proportional to the spring constant when the force is the same.
171 Medium
171 of 496
Application +4 | -1
A steel sphere of mass 100 gm moving with a velocity of 4 m/s collides with a dust particle elastically moving in the same direction with a velocity of 1 m/s. The velocity of the dust particle after the collision is
View answer and explanation
Correct option: B
7 m/s
Option B (7 m/s) is correct because it is calculated using the formula for the final velocity of the second object in an elastic collision when the mass of the second object is negligible.
172 Medium
172 of 496
Analyzing +4 | -1
A ball AA moving with certain velocity along positive xx-axis collides with a stationary ball BB. After collision their directions of motion make angles α\alpha and β\beta with the xx-axis. The possible values of α\alpha and β\beta are
View answer and explanation
Correct option: A
α=30∘\alpha=30^{\circ} and β=−45∘\beta=-45^{\circ}
Option A (α=30∘\alpha=30^{\circ} and β=−45∘\beta=-45^{\circ}) is correct because the y-component of momentum must be conserved (zero) and the x-component must be non-zero.
173 Medium
173 of 496
Application +4 | -1
A long spring when stretched by 2 cm its potential energy is UU. If the same spring is stretched by 8 cm, then the potential energy of the spring is
View answer and explanation
Correct option: B
16 U
Option B (16 U) is correct because the potential energy of a spring is proportional to the square of the displacement, so stretching it four times increases the energy by a factor of 16.
174 Medium
174 of 496
Analyzing +4 | -1
Assertion(A): The relative velocity of the two particles in head on elastic collision is unchanged both in magnitude and direction.

Reason(R): The relative velocity is unchanged in magnitude but gets reversed in direction.
View answer and explanation
Correct option: D
If Assertion is incorrect but Reason is correct.
Option D is correct because in an elastic collision the relative velocity is unchanged in magnitude but gets reversed in direction.
175 Medium
175 of 496
Application +4 | -1
A force F→=(i^+2j^+3k^)N\overrightarrow F = (\hat i + 2\hat j + 3\hat k)N displaces a particle from position r1→=(i^+j^+k^)m\overrightarrow {{r_1}} = (\hat i + \hat j + \hat k)m to position r2→=(j^+k^)m\overrightarrow {{r_2}} = (\hat j + \hat k)m. The work done by the force in doing so is
View answer and explanation
Correct option: A
– 1 J
Option A (– 1 J) is correct because the work done is the dot product of the force and the displacement vector.
176 Medium
176 of 496
Understanding +4 | -1
Statement-I: Work done by spring force on a block connected to the spring may be positive or negative.
Statement-II: Spring force is both pushing and pulling.
View answer and explanation
Correct option: A
Statement-I &\& II are true.
Option A (Statement-I & II are true) is correct because spring force can do positive or negative work depending on the direction of displacement, and it can either push or pull.
177 Medium
177 of 496
Application +4 | -1
A body having weight 0.4 kg0.4 \mathrm{~kg} is whirled in a vertical circle with a string making 2 revolutions/second. Given that the radius of this circle is 1.2 m\mathrm{m}. Find out the tension

(a) At the top of the circle

(b) At the lowermost point of the circle.

Given : g=10 m s−2\mathrm{g}=10 \mathrm{~m} \mathrm{~s}^{-2} and π=3.14\pi=3.14.
View answer and explanation
Correct option: D
71.2 N71.2 \mathrm{~N} , 80 N80 \mathrm{~N}
Option D (71.2 N71.2 \mathrm{~N} , 80 N80 \mathrm{~N}) is correct because it calculates the tension at the top and bottom of the vertical circle using centripetal force and gravity.
178 Medium
178 of 496
Understanding +4 | -1
Assertion (A): Graph between potential energy of a spring versus the extension or compression of the spring is parabola
Reason (R): Potential energy of a stretched or compressed spring proportional to square of extension or compression
View answer and explanation
Correct option: A
If both Assertion and Reason are true and Reason is correct explanation of Assertion.
Option A (If both Assertion and Reason are true and Reason is correct explanation of Assertion) is correct because the potential energy of a spring is proportional to the square of its extension or compression, resulting in a parabolic relationship.
179 Medium
179 of 496
Analyzing +4 | -1
Statement I Two particles moving in the same direction do not lose all their energy in a completely inelastic collision. Statement II Principle of conservation of momentum holds true for all kinds of collisions.
View answer and explanation
Correct option: D
Statement I is true, Statement II is false.
Option D is correct because Statement I is true; kinetic energy is not fully lost in inelastic collisions due to momentum conservation, but Statement II is false; momentum is always conserved.
180 Medium
180 of 496
Analyzing +4 | -1
Assertion: If a body moving in a circular path has constant speed, then there is no force acting on it.
Reason: The direction of the velocity vector of a body moving in a circular path is changing.
View answer and explanation
Correct option: D
Assertion is incorrect, reason is correct
Option D is correct. A body moving in a circular path with constant speed experiences a centripetal force, and the direction of the velocity vector is indeed changing.
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