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JEE • PHYSICS • WORK-ENERGY-POWER

Work-energy-power practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 1-30 of 535 questions
1 Medium
1 of 535
Application +4 | -1
A ball throwing cannon, lifts ball and throws with 72 km/hr72 \mathrm{~km} / \mathrm{hr} Speed. If balls are raised upto 10 m10 \mathrm{~m}. then find Input power of cannon if it lifts 8 balls per minute and its efficiency is 80%80 \%. Mass of each ball is 1 kg1 \mathrm{~kg}.
View answer and explanation
Correct option: A
50 watt
Option A (50 watt) is correct because it is the input power calculated considering the potential and kinetic energy changes of the balls and the efficiency of the cannon.
2 Medium
2 of 535
Analyzing +4 | -1
Assertion:When a particle moves in a circle with a uniform speed its acceleration is constant but the velocity changes.
Reason: Angular displacement is not an axial vector.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D (If both Assertion & Reason are false) is correct because the acceleration of a particle moving in a circle with uniform speed is not constant (it changes direction), and angular displacement is an axial vector.
3 Medium
3 of 535
Application +4 | -1
A body of mass mm thrown vertically upwards attains a maximum height hh. As what height will its kinetic energy be 75%75 \% of its initial value?
View answer and explanation
Correct option: C
h4\frac{h}{4}
Option C (h4\frac{h}{4}) is correct because at this height, 75% of the initial kinetic energy is converted into potential energy, leaving 25% as kinetic energy.
4 Easy
4 of 535
Understanding +4 | -1
Assertion: Centripetal force does no work.

Reason: Force and displacement are perpendicular to each other.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion.
Option A is correct because centripetal force does no work as it is always perpendicular to the displacement, and the reason correctly explains this.
5 Medium
5 of 535
Understanding +4 | -1
Statement I: Both stretched and compressed springs possess potential energy.

Statement II: Work done against restoring force is stored as potential energy.
View answer and explanation
Correct option: A
If both Statement - I and Statement - II are true, and Statement - II is the correct explanation of Statement - I
Option A (If both Statement - I and Statement - II are true, and Statement - II is the correct explanation of Statement - I) is correct because both stretched and compressed springs store potential energy due to the work done against the restoring force.
6 Medium
6 of 535
Application +4 | -1
A bullet of mass mm moving at a speed vv hits a ball of mass MM kept at rest. A small part having mass m′m^{\prime} breaks from the ball and sticks to the bullet. The remaining ball is found to move at a speed v1v_1 in the direction of the bullet. Find the velocity of the bullet after the collision.
View answer and explanation
Correct option: A
mv−(M−m′)v1m+m′\frac{m v-\left(M-m^{\prime}\right) v_1}{m+m^{\prime}}
Option A (mv−(M−m′)v1m+m′\frac{{m v - (M - m^{\prime}) v_1}}{{m + m^{\prime}}}) is correct because it is derived from the conservation of momentum principle during the collision.
7 Medium
7 of 535
Application +4 | -1
A 2.0 kg block is dropped from a height of 40 cm onto a spring of spring constant k=1960  Nm−1k = 1960\;\mathrm{N}{\mathrm{m}^{ - 1}} . Find the maximum distance the spring is compressed
View answer and explanation
Correct option: D
0.10m0.10\mathrm{ }m
Option D (0.10m0.10\mathrm{ }m) is correct because it is the positive solution to the quadratic equation derived from the conservation of energy.
8 Medium
8 of 535
Application +4 | -1
A ring of mass MM and radius rr is rotating with angular velocity ω\omega. Two particles of mass mm are gently placed on the ends of a diameter. Final angular velocity will be:
View answer and explanation
Correct option: B
ωMM+2m\frac{{\omega M}}{{M + 2m}}
Option B (ωMM+2m\frac{{\omega M}}{{M + 2m}}) is correct because it is derived from the conservation of angular momentum, considering the initial and final moments of inertia.
9 Medium
9 of 535
Application +4 | -1
A cricket ball is hit for a six leaving the bat at an angle of 60o{60^\mathrm{o}} to the horizontal with kinetic energy k. At the top K.E of ball is
View answer and explanation
Correct option: C
k/4
Option C (k/4) is correct because the kinetic energy at the top is only due to the horizontal component of velocity.
10 Medium
10 of 535
Analyzing +4 | -1
A ball is dropped from height 10 m. Ball is embedded in sand 1 m and stops, then
View answer and explanation
Correct option: A
Only momentum remains conserved
Neither K.E. nor momentum is conserved (Option D) because the collision with the sand is inelastic, and external forces are acting on the ball.
11 Easy
11 of 535
Analyzing +4 | -1
Assertion: A cyclist leans inwards while taking a turn, while a man sitting in a car leans outwards on a curve.

Reason: Centripetal acceleration is acting towards the centre of the curve.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion.
Option A (If both assertion and reason are true and reason is the correct explanation of the assertion) is correct because the leaning is a response to the centripetal acceleration required for circular motion.
12 Medium
12 of 535
Application +4 | -1
An engine is hauling a train of mass M kgM \mathrm{~kg} on a level track at a constant speed v ms−1v \mathrm{~m} \mathrm{s}^{-1}. The resistance due to friction is f N kg−1f \mathrm{~N} \mathrm{~kg}^{-1}. What extra power must the engine develop to maintain the speed up a gradient of hh in travelling distances ss up a incline?
View answer and explanation
Correct option: A
mghvs\frac{m g h v}{s}
Option A (mghvs\frac{m g h v}{s}) is correct because the extra power is the product of the extra force needed to overcome gravity and the velocity.
13 Medium
13 of 535
Application +4 | -1
A particle moves in a circular of radius 0.8 m at a speed that uniformly increases. Find the angular acceleration of particle if its speed changes from 3.0 m/s to 6.0 m/s in 6.0s.
View answer and explanation
Correct option: B
0.62 rad /s20.62\,rad\,/{s^2}
Option B (0.62 rad /s20.62\,rad\,/{s^2}) is correct because it is calculated by dividing the tangential acceleration by the radius of the circular path.
14 Medium
14 of 535
Understanding +4 | -1
If force is always perpendicular to motion
a) KE remains constant
b) Work done by the force is zero
c) Momentum remains constant
d) Speed remains constant
View answer and explanation
Correct option: A
a, b, d
Option A (a, b, d) is correct because if force is always perpendicular to motion, kinetic energy and speed remain constant, and the work done by the force is zero.
15 Medium
15 of 535
Understanding +4 | -1
A block hangs freely from the end of a spring. A boy then slowly pushes the block upwards so that the spring becomes strain free. The gain in gravitational potential energy of the block during this process is equal to
View answer and explanation
Correct option: A
Work done by the boy against the gravitational force acting on the block
Option A (Work done by the boy against the gravitational force acting on the block) is correct because the gain in gravitational potential energy is equal to the work done against gravity.
16 Medium
16 of 535
Understanding +4 | -1
Identify the false statement from the following
View answer and explanation
Correct option: C
Work done by friction over a closed path is zero
Option C is correct because work done by friction over a closed path is non-zero as friction is a non-conservative force.
17 Medium
17 of 535
Understanding +4 | -1
Assertion: Centripetal and centrifugal forces cancel each other.
Reason: This is because they are always equal and opposite.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D is correct because both the assertion and the reason are false. Centripetal and centrifugal forces do not cancel each other as they act on different bodies or are pseudo forces in different frames of reference.
18 Medium
18 of 535
Analyzing +4 | -1
The force exerted by a compression device is given by F(x)=kx(x−l)F(x)=k x(x-l) for 0≤x≤l0 \leq x \leq l, where ll is the maximum possible compression, xx is the compression and k{k} is a constant. The work required to compress the body by a distance d{d} will be maximum when:
View answer and explanation
Correct option: D
d=ld=l
Option D (d=ld=l) is correct because the work required is the integral of the force over the compression distance, and the maximum compression yields the maximum work.
19 Medium
19 of 535
Understanding +4 | -1
The work done by a conservative force in closed path is
View answer and explanation
Correct option: B
Zero
Option B (Zero) is correct because the net work done by a conservative force over a closed path is always zero due to the path independence of conservative forces.
20 Medium
20 of 535
Application +4 | -1
A cyclist speeding at 18 km h−118 \mathrm{~km} \mathrm{~h}^{-1} on a level road takes a sharp circular turn of radius 3 m3 \mathrm{~m} without reducing the speed and without bending towards the centre of the circular path. The coefficient of static friction between the tyres and the road is 0.1. Will the cyclist slip while taking the turn?
View answer and explanation
Correct option: A
5 ms−15 \mathrm{~ms}^{-1}
Option A (5 ms−15 \mathrm{~ms}^{-1}) is correct because the cyclist will slip since the actual speed is greater than the maximum safe speed calculated using the coefficient of static friction.
21 Medium
21 of 535
Remembering +4 | -1
Which of the following is a unit of energy
View answer and explanation
Correct option: D
None
Option D (None) is correct because Watt and Horsepower are units of power, not energy.
22 Medium
22 of 535
Application +4 | -1
A body of mass 1 kg is projected vertically up with certain velocity. At certain point its P.E. and K.E. are 8 J and 90 J. The maximum height reached by it is
View answer and explanation
Correct option: C
10 m
Option C (10 m) is correct because the maximum height is calculated by equating the total energy (PE + KE) at a given point to the potential energy at the maximum height.
23 Medium
23 of 535
Analyzing +4 | -1
Assertion (A): If the momentum of a body increases by 20%20 \%, then its KE also increases by 20%20 \%
Reason (R): The KE of a body is directly proportional to its momentum
View answer and explanation
Correct option: D
If both Assertion and Reason are false
Option D is correct. If the momentum of a body increases by 20%, its KE increases by 44%. KE is proportional to the square of momentum, not directly proportional.
24 Medium
24 of 535
Understanding +4 | -1
Statement-1 : Work done is positive when force acts in the
direction of displacement.
Statement-2 : Work done by friction force cannot be positive
View answer and explanation
Correct option: C
Statement-1 is true, Statement-2 is false.
Option C (Statement-1 is true, Statement-2 is false) is correct because work done is positive when the force acts in the direction of displacement, but work done by friction can be positive in certain situations.
25 Medium
25 of 535
Understanding +4 | -1
An electron and a proton are moving under the influence of mutual forces. In calculating the change in the kinetic energy of the system during motion, one ignores the magnetic force of one on another. This is because,
View answer and explanation
Correct option: B
the magnetic forces do no work on each particle.
Option B (the magnetic forces do no work on each particle) is correct because magnetic forces are velocity-dependent and always act perpendicular to the direction of motion, thus doing no work.
26 Medium
26 of 535
Application +4 | -1
A ball rolls off the top of stair-way with a horizontal velocity of magnitude 1.8 ms−1.1.8\,m{s^{ - 1}}. The steps are 0.20 m high and 0.20 m wide. Which step will the ball hit first?
View answer and explanation
Correct option: D
Fourth
Option D (Fourth) is correct because the ball will hit the fourth step, calculated by finding the step number using projectile motion equations.
27 Medium
27 of 535
Analyzing +4 | -1
Assertion : Power developed in circular motion is always zero.

Reason : Work done in case of circular motion is zero.
View answer and explanation
Correct option: D
If both assertion and reason are false.
Option D is correct because both the assertion and the reason are false. Power developed and work done are zero only in uniform circular motion.
28 Medium
28 of 535
Application +4 | -1
A body of mass mm is dropped from a height hh above the ground. The velocity VV of the body when it has lost half its initial potential energy is given by
View answer and explanation
Correct option: A
V=ghV=\sqrt{{gh}}
Option A (V=ghV=\sqrt{{gh}}) is correct because it is derived from equating the gain in kinetic energy to the loss in potential energy when the body has lost half of its initial potential energy.
29 Medium
29 of 535
Understanding +4 | -1
If a machine gun fires nn bullets per second each with kinetic energy KK, then the power of the machine gun is
View answer and explanation
Correct option: D
nKn K
Option D (nKn K) is correct because the power is the total kinetic energy of the bullets fired per second.
30 Medium
30 of 535
Application +4 | -1
A man holds a ball of mass (1/2)kg(1 / 2) \mathrm{kg} in his hand. He throws it vertically upward. During this process his hand moves up by 40 cm40 \mathrm{~cm} and the ball leaves his hand with an upward velocity of 4 ms−14 \mathrm{~ms}^{-1}. The constant force with which the man pushes the ball is (g=10 m/s2)\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right)
View answer and explanation
Correct option: C
15 N15 \mathrm{~N}
Option C (15 N15 \mathrm{~N}) is correct because it is calculated using Newton's second law, considering both the acceleration of the ball and the gravitational force.
Revision notes and key takeaways

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Key Takeaways

  • ✓ This set contains 535 single-correct-answer MCQs on WORK-ENERGY-POWER.
  • ✓ Try each question before opening its answer. Read the explanation where one is available.
  • ✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.
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