JEE PHYSICS MCQ: WORK-ENERGY-POWER

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A bullet of mass

m

moving at a speed

v

hits a ball of mass

M

kept at rest. A small part having mass

m^{\prime}

breaks from the ball and sticks to the bullet. The remaining ball is found to move at a speed

v_1

in the direction of the bullet. Find the velocity of the bullet after the collision.

View answer and explanation

Correct option: A

\frac{m v-\left(M-m^{\prime}\right) v_1}{m+m^{\prime}}

Option A (

\frac{{m v - (M - m^{\prime}) v_1}}{{m + m^{\prime}}}

) is correct because it is derived from the conservation of momentum principle during the collision.

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