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JEE PHYSICS MCQ: WORK-ENERGY-POWER

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A particle moves in a circular of radius 0.8 m at a speed that uniformly increases. Find the angular acceleration of particle if its speed changes from 3.0 m/s to 6.0 m/s in 6.0s.
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Correct option: B
0.62 rad /s20.62\,rad\,/{s^2}
Option B (0.62 rad /s20.62\,rad\,/{s^2}) is correct because it is calculated by dividing the tangential acceleration by the radius of the circular path.

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