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JEE • PHYSICS • WORK-ENERGY-POWER

Work-energy-power practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 421-450 of 496 questions

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421 Medium
421 of 496
Application +4 | -1
A particle moves in a circle of radius rr under the action of a centripetal force equal to −kr2r^-\frac{k}{r^2} \hat{r}, where kk is a constant. The total energy of the particle is
View answer and explanation
Correct option: C
−k2r-\frac{k}{2 r}
Option C (-k/2r) is correct because the total energy is the sum of kinetic and potential energies, where kinetic energy is k/2r and potential energy is -k/r.
422 Medium
422 of 496
Understanding +4 | -1
Which of the following is true:

Statement A: A particle is moving with constant speed must have constant velocity also.

Statement B: If velocity of a particle is zero then its acceleration may not be zero.
View answer and explanation
Correct option: C
Only A is wrong
Option C (Only A is wrong) is correct because a particle moving with constant speed can have changing velocity (e.g., circular motion), and zero velocity doesn't imply zero acceleration.
423 Medium
423 of 496
Analyzing +4 | -1
Statement I: The tendency to overturn of skidding/overturning is quadrupled, when a cyclist doubles his speed of turning.

Statement II: tan⁡θ=v2Rg⇒\tan \theta=\frac{\mathrm{v}^2}{\mathrm{Rg}} \Rightarrow becomes 4 times as vv doubled.
View answer and explanation
Correct option: A
If both Statement - I and Statement - II are true, and Statement - II is the correct explanation of Statement - I
Statement I and Statement II are both true, and Statement II correctly explains Statement I. The tendency to overturn increases with the square of the velocity, as shown by the equation tan⁡θ=v2Rg\tan \theta = \frac{{v^2}}{{Rg}}.
424 Medium
424 of 496
Application +4 | -1
Water falls from a height of 60 m at the rate of 15 kg/s to operate a turbine. The losses due to frictional force are 10% of the input energy. How much power is generated by the turbine? (g=10m/s2)(g = 10\mathrm{ m/}{\mathrm{s}^2})
View answer and explanation
Correct option: D
8.1 kW8.1\,\mathrm{kW}
Option D (8.1 kW8.1 \mathrm{~kW}) is correct because the power generated by the turbine is 90% of the input power, which is calculated from the potential energy of the water falling from a height of 60 m.
425 Medium
425 of 496
Analyzing +4 | -1
A time t=0 s Particle starts moving along the x-axis. If its kinetic energy increases uniformly with time t, the net force acting on it must be proportional to
View answer and explanation
Correct option: D
1t\frac{1}{{\sqrt t }}
Option D (1t\frac{1}{{\sqrt t }}) is correct because the force is inversely proportional to the square root of time when kinetic energy increases uniformly with time.
426 Medium
426 of 496
Understanding +4 | -1
A body of mass 1 kg1 \mathrm{~kg} is rotated in a horizontal circle of radius 1 m1 \mathrm{~m} and moves with velocity 2 m/sec2 \mathrm{~m} / \mathrm{sec}. The work done in 10 revolutions is
View answer and explanation
Correct option: D
Zero
Option D is correct because in circular motion with constant speed, the kinetic energy remains constant, and hence the work done is zero.
427 Medium
427 of 496
Application +4 | -1
A force F⃗=i^+5j^+7k^\vec{F}=\hat{i}+5 \hat{j}+7 \hat{k} acts on a particle and displaces it through s⃗=6i^+9k^\vec{s}=6 \hat{i}+9 \hat{k}. Calculate the work done if the force is in newton and displacement in metre.
View answer and explanation
Correct option: A
69 J69 \mathrm{~J}
Option A (69 J69 \mathrm{~J}) is correct because it is the dot product of the force and displacement vectors.
428 Medium
428 of 496
Application +4 | -1
A quarter horse power motor runs at a speed of 600 r.p.m. Assuming 40% efficiency the work done by the motor in one rotation will be
View answer and explanation
Correct option: A
7.46 J
Option A (7.46 J) is correct because it is the work done by the motor in one rotation, calculated considering the power, speed, and efficiency.
429 Medium
429 of 496
Application +4 | -1
A body starts from rest and acquires a velocity VV in time TT. The work done on the body in time tt will be proportional to
View answer and explanation
Correct option: D
V2T2t2\frac{V^2}{T^2} t^2
Option D (V2T2t2\frac{V^2}{T^2} t^2) is correct because work done is proportional to the square of velocity, which is proportional to the square of time.
430 Medium
430 of 496
Analyzing +4 | -1
Kinetic energy of a particle moving in a straight line varies with time tt as K=4t2K=4 t^2. The force acting on the particle
View answer and explanation
Correct option: A
is constant
Option B is correct because the force is found to be increasing with time.
431 Medium
431 of 496
Application +4 | -1
The potential energy of a body as a function of distance is given as U(x)=(−6x2+2x)JU(x)=\left(-6 x^2+2 x\right) {J}. The conservative force acting on body at x=1 mx=1 {~m} will be
View answer and explanation
Correct option: C
10 N10 {~N}
Option D (2Ω2\Omega) is correct because the resistance is calculated by dividing the voltage for full-scale deflection by the corresponding current.
432 Medium
432 of 496
Understanding +4 | -1
Assertion: The work done by the spring force in a cyclic process is zero.
Reason: Spring force is a conservative force.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of assertion
Option A is correct because the work done by a conservative force, like the spring force, in a cyclic process is zero, and the reason correctly explains why.
433 Medium
433 of 496
Understanding +4 | -1
A) Work done by frictional force is always negative
B) A body at rest can have mechanical energy
C) Mechanical energy of freely falling body decrease gradually
View answer and explanation
Correct option: B
Only B is true
Option B is correct because a body at rest can possess potential energy, which is a form of mechanical energy.
434 Medium
434 of 496
Understanding +4 | -1
Maximum energy transfer for an elastic collision will occur if one body is at rest when
View answer and explanation
Correct option: A
m1=m2m_1=m_2
Option A (m1=m2m_1=m_2) is correct because maximum energy transfer occurs when masses are equal in an elastic collision.
435 Medium
435 of 496
Understanding +4 | -1
In uniform circular motion which of the following quantity is zero?
View answer and explanation
Correct option: C
Change in magnitude of velocity
Option C is correct because in uniform circular motion, the magnitude of velocity (speed) remains constant, so the change in magnitude of velocity is zero.
436 Medium
436 of 496
Application +4 | -1
A 1 kg1 \mathrm{~kg} ball, moving at 12 ms−112 \mathrm{~m} \mathrm{s}^{-1}, collides head-on with a 2 kg2 \mathrm{~kg} ball moving in the opposite direction at 24 ms−124 \mathrm{~m} \mathrm{s}^{-1}. If the coefficient of restitution is 23\frac{2}{3}, then what is the energy lost in the collision?
View answer and explanation
Correct option: C
240 J240 \mathrm{~J}
Option C (240 J) is correct because it is the difference between the initial and final kinetic energies, calculated using the coefficient of restitution to find the final velocities.
437 Medium
437 of 496
Application +4 | -1
At what time PE\mathrm{PE} will be equal to half of the total energy (TE) :-
View answer and explanation
Correct option: D
T8\frac{T}{8}
Option D (T8\frac{T}{8}) is correct because the potential energy is half the total energy when sin⁡2(ωt)=12\sin^2(\omega t) = \frac{1}{2}, which occurs at t=T8t = \frac{T}{8}.
438 Medium
438 of 496
Application +4 | -1
A body of mass mm is moving with a velocity v1.v_1. If a force FF acts on it and displaces it by d,d, then final velocity will be
View answer and explanation
Correct option: B
2Fd+mv12m\sqrt {\frac{{2Fd + mv_1^2}}{m}}
Option B (2Fd+mv12m\sqrt {\frac{{2Fd + mv_1^2}}{m}}) is correct because it is derived from the work-energy theorem, relating work done to the change in kinetic energy.
439 Medium
439 of 496
Application +4 | -1
The potential energy of a particle of mass 3 kg3 {~kg} free to move along the xx-axis is given by U(x)=(3x22−2x)JU(x)=\left(\frac{3 x^2}{2}-2 x\right) {J}. If total mechanical energy of the particle is 5 J5 {~J}, then the maximum speed of the particle is;
View answer and explanation
Correct option: B
343 m/s\frac{\sqrt{34}}{3} {~m} / {s}
Option B (343 m/s\frac{\sqrt{34}}{3} {~m} / {s}) is correct because it is calculated by finding the minimum potential energy and then using conservation of energy to find the maximum kinetic energy and thus the maximum speed.
440 Medium
440 of 496
Application +4 | -1
Water falls down a 500.0 m500.0 \mathrm{~m} shaft to reach a turbine which generates electricity. How much water must fall per second in order to generate 1.00×109 W1.00 \times 10^9 \mathrm{~W} of power?

(Assume 50% efficiency of conversion and g=10 ms−2g=10 \mathrm{~ms}^{-2})
View answer and explanation
Correct option: B
400 m3400 \mathrm{~m}^3
Option B (400 m3400 \mathrm{~m}^3) is correct because it's the volume of water required per second to generate the specified power, considering the efficiency of conversion.
441 Medium
441 of 496
Application +4 | -1
A body is moving in a vertical circle such that the velocity of body at lowest point is critical. The ratio of velocities of body at angular displacements 600{60^0} and 1200{120^0} from lowest point is
View answer and explanation
Correct option: A
1.414
Option A (1.414) is correct because the ratio of velocities at 60 and 120 degrees is calculated using the conservation of energy in a vertical circle.
442 Medium
442 of 496
Understanding +4 | -1
Which of the following statements is false for a particle moving in a circle with a constant angular speed?
View answer and explanation
Correct option: B
The acceleration vector is tangent to the circle
Option B (The acceleration vector is tangent to the circle) is correct because in uniform circular motion, the acceleration vector always points towards the center of the circle (centripetal acceleration), not tangent to it.
443 Medium
443 of 496
Analyzing +4 | -1
The potential energy of a particle varies with x according to the relation U(x)=x2−4xU\left( x \right) = {x^2} - 4x . The point x = 2 is a point of
View answer and explanation
Correct option: A
Stable equilibrium
Option A (Stable equilibrium) is correct because the second derivative of the potential energy at x=2 is positive, indicating a minimum.
444 Medium
444 of 496
Understanding +4 | -1
Work done in raising a box depends on:
View answer and explanation
Correct option: C
The height by which it is raised
Option C (The height by which it is raised) is correct because the work done against gravity depends only on the change in potential energy, which is determined by the height.
445 Medium
445 of 496
Application +4 | -1
A force (3i^+j^−2k^)N(3 \hat{i}+\hat{j}-2 \hat{k}) \mathrm{N} acting on a body maintains its velocity at (3i^+3j^+3k^)ms−1(3 \hat{i}+3 \hat{j}+3 \hat{k}) \mathrm{ms}^{-1}. The power exerted is
View answer and explanation
Correct option: A
6 W6 \mathrm{~W}
Option A (6 W6 \mathrm{~W}) is correct because power is the dot product of force and velocity.
446 Medium
446 of 496
Application +4 | -1
A particle of mass m1\mathrm{m}_1 collides head-on with another stationary particle of mass m2(m2>m1)\mathrm{m}_2\left(\mathrm{m}_2 > \mathrm{m}_1\right). The collision is perfectly inelastic. The fraction of kinetic energy which is converted into heat in this collision is
View answer and explanation
Correct option: A
m2/(m1+m2)\mathrm{m}_2 /\left(\mathrm{m}_1+\mathrm{m}_2\right)
Option A (m2/(m1+m2)\mathrm{m}_2 /\left(\mathrm{m}_1+\mathrm{m}_2\right)) is correct because it represents the fraction of kinetic energy converted into heat during a perfectly inelastic collision, derived from conservation of momentum and energy loss calculations.
447 Medium
447 of 496
Application +4 | -1
A car is moving along a circular path of radius 500 m500 {~m} with a speed of 30 ms−130 {~ms}^{-1}. If at some instant, its speed increases at the rate of 2 ms−12 {~ms}^{-1}, then at that instant, the magnitude of resultant acceleration will be
View answer and explanation
Correct option: D
2.7 ms−22.7 {~ms}^{-2}
Option D (2.7 ms−22.7 {~ms}^{-2}) is correct because it is the magnitude of the resultant acceleration, calculated using both centripetal and tangential accelerations.
448 Medium
448 of 496
Application +4 | -1
A particle of mass mm collides head-on with another stationary particle of mass MM such that the second particle starts moving and the first particle comes to rest after the collision. Which of the following conditions is valid if the coefficient of restriction is ee?
View answer and explanation
Correct option: B
e=mM≤1e=\frac{m}{M} \leq 1
Option B (e=mM≤1e=\frac{m}{M} \leq 1) is correct because the coefficient of restitution is the ratio of velocities, which equals mM\frac{m}{M} and must be less than or equal to 1.
449 Medium
449 of 496
Understanding +4 | -1
Statement-I: A quick collision between two bodies is more violent than slow collision, even when initial and final velocities are identical.
Statement-II: The rate of change of momentum determines that the force is small or large.
View answer and explanation
Correct option: A
Statement-I &\& II are true.
Option A is correct because both statements are true. A quick collision involves a larger force due to a shorter impact time, and the rate of change of momentum directly determines the magnitude of the force.
450 Medium
450 of 496
Application +4 | -1
A long spring, when stretched by x cm has a potential energy U. On increasing the length of spring by stretching to nx cm, the potential energy stored in the spring will be
View answer and explanation
Correct option: C
n2U{n^2}U
Option C (n2U{n^2}U) is correct because the potential energy stored in a spring is proportional to the square of the extension.
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