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JEE PHYSICS MCQ: WORK-ENERGY-POWER

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An elastic string of unstretched length L and force constant k is stretched by a small length xx. It is further stretched by another small length y. The work done in the second stretching is
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Correct option: D
12ky(2x+y)\frac{1}{2}ky\left( {2x + y} \right)
Option D (12ky(2x+y)\frac{1}{2}ky(2x + y)) is correct because it represents the work done against the elastic force when stretching from x to x+y, accounting for the initial stretch.

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