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JEE • PHYSICS • WORK-ENERGY-POWER

Work-energy-power practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 361-390 of 496 questions

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361 Medium
361 of 496
Understanding +4 | -1
For a body in uniform circular motion, the
View answer and explanation
Correct option: C
Angular velocity is constant
Option C (Angular velocity is constant) is correct because uniform circular motion implies constant angular speed.
362 Medium
362 of 496
Understanding +4 | -1
Statement I In an elastic collision between two bodies, the relative speed of the bodies after collision is equal to the relative speed before the collision. Statement II Inan elastic collision, the linear momentum of the system is conserved.
View answer and explanation
Correct option: B
Statement I is true, Statement II is true; statement II is not correct explanation for statement I
Option B (Statement I is true, Statement II is true; statement II is not correct explanation for statement I) is correct because both statements are true about elastic collisions, but the conservation of momentum doesn't directly explain the relative speed relationship.
363 Medium
363 of 496
Understanding +4 | -1
Which of the following statement(s) is/are correct?

I. Spring force is a conservative force.

II. Potential energy is defined only for conservative forces.
View answer and explanation
Correct option: C
Both I and II
Option C (Both I and II) is correct because spring force is a conservative force, and potential energy is defined only for conservative forces.
364 Medium
364 of 496
Application +4 | -1
A simple pendulum is oscillating with an angular amplitude 600{60^0}. If mass of bob is 50 gm, then the tension in the string at mean position (in N) is (g=10  m/s2)\left( {\mathrm{g = 10}\,\,\mathrm{m/}{\mathrm{s}^\mathrm{2}}} \right)
View answer and explanation
Correct option: A
1
Option A (1) is correct because the tension in the string at the mean position is calculated considering both the weight and the centripetal force.
365 Medium
365 of 496
Application +4 | -1
Find W.D in stretching a storing of spring constant K\mathrm{K} from extension x0x_0 to extension 3x03 x_0 ?
View answer and explanation
Correct option: D
4kx024kx_0^2
Option D (4kx024kx_0^2) is correct because it is the work done in stretching the spring from x0x_0 to 3x03x_0, calculated as the change in potential energy.
366 Medium
366 of 496
Understanding +4 | -1
A body of mass m kg is lifted by a man to a height of one metre in 30 sec. Another man lifts the same mass to the same height in 60 sec. The work done by them are in the ratio
View answer and explanation
Correct option: B
1:11:1
Option B (1:11:1) is correct because the work done only depends on the force (weight) and the displacement (height), not the time taken.
367 Medium
367 of 496
Application +4 | -1
A particle of mass 100 gm moves in a potential well given by U=8x2−4x+400U=8 x^2-4 x+400 Joule. Find its acceleration at a distance of 25 cm25 \mathrm{~cm} from equilibrium in the positive direction
View answer and explanation
Correct option: C
−40 ms−1-40 \mathrm{~ms}^{-1}
Option C (−40 ms−1-40 \mathrm{~ms}^{-1}) is correct because it is the acceleration calculated from the force derived from the potential well, evaluated at the given displacement from equilibrium.
368 Medium
368 of 496
Analyzing +4 | -1
Two identical spheres move in opposite directions with speeds v1v_1 and v2v_2 and pass behind an opaque screen where they may either cross without touching (event 1 ) or make an elastic head-on collision (event 2) -
View answer and explanation
Correct option: A
We can never make out which event has occurred
Option A is correct because due to the conservation of momentum and the identical nature of the spheres, we cannot distinguish between crossing without touching and an elastic head-on collision.
369 Medium
369 of 496
Application +4 | -1
A person with a mass of M kgM \mathrm{~kg} stands in contact against the wall of a cylindrical drum of radius rr rotating with an angular velocity ω\omega. If the coefficient of friction between the wall and the clothing is μ\mu, the minimum rotational speed of the cylinder which enables the person to remain stuck to the wall when the floor is suddenly removed, is
View answer and explanation
Correct option: A
ωmin⁡=gμr\omega_{\min }=\sqrt{\frac{g}{\mu r}}
Option A is correct because the minimum rotational speed is derived by equating the frictional force to the weight of the person.
370 Medium
370 of 496
Application +4 | -1
A constant power p is applied to a car starting from rest. If v is the velocity of the car at time t, then
View answer and explanation
Correct option: C
v∝tv \propto \sqrt t
Option C (v∝tv \propto \sqrt t) is correct because with constant power, the velocity squared is proportional to time, thus velocity is proportional to the square root of time.
371 Medium
371 of 496
Application +4 | -1
A ball of mass m1{m_1} is a moving with velocity vv. It collides head on elastically with a stationary ball of mass m2{m_2}. The velocity of ball becomes v/3 after collision. Then the value of the ratio m2m1\frac{{{m_2}}}{{{m_1}}} is
View answer and explanation
Correct option: B
2
Option B (2) is correct because the ratio of masses is calculated using the conservation of momentum and the coefficient of restitution for an elastic collision.
372 Medium
372 of 496
Understanding +4 | -1
A) For any collision, momentum transfer takes place.
B) In any collision, energy transfer takes place.
C) Impulsive forces are involved in collisions.
View answer and explanation
Correct option: A
A and C are true
Option A (A and C are true) is correct because momentum transfer always occurs in a collision, and collisions involve impulsive forces. Energy transfer does not necessarily occur in every collision (e.g., perfectly elastic collision).
373 Medium
373 of 496
Analyzing +4 | -1
Assertion: Uniform circular motion is always an accelerated motion.
Reason: Direction of acceleration is parallel to the velocity vector.
View answer and explanation
Correct option: C
If assertion is true but reason is false
Option C (If assertion is true but reason is false) is correct because uniform circular motion is accelerated due to the changing direction of velocity, but the acceleration is perpendicular to the velocity, not parallel.
374 Medium
374 of 496
Analyzing +4 | -1
Statement I A cyclist is moving on an unbanked road with a speed of 7 kmh−17\,km{h^{ - 1}} and takes a sharp circular turn along a path of radius of 2 m without reducing the speed. The static friction coefficient is 0.2. The cyclist will not slip and pass the curve (g = 9.8 m/s2)\left( {g\, = \,9.8\,m/{s^2}} \right)
Statement II If the road is banked at an angle of 45o{45^\mathrm{o}}, cyclist can cross the curve of 2 m radius with the speed of 18.5 kmh−118.5\,km{h^{ - 1}} without slipping.
In the light of the above statements, choose the correct answer from the options given below.
View answer and explanation
Correct option: D
Both statement I and II are true.
Option D (Both statement I and II are true) is correct because both statements are verifiable through calculations using friction and banking angle formulas.
375 Medium
375 of 496
Analyzing +4 | -1
Motion of a particle in x−yx - y plane is described by a set of following equations x=4sin⁡(π2−ωt)mx = 4\sin \left( {\frac{\pi }{2} - \omega t} \right)m and y=4sin⁡(ωt)m.y = 4\sin \left( {\omega t} \right)m. The path of the particle will be
View answer and explanation
Correct option: A
Circular
Option A is correct because the given equations describe a circular path with a radius of 4 m.
376 Medium
376 of 496
Understanding +4 | -1
A man pushes a wall and falls to displace it. He does
View answer and explanation
Correct option: C
No work at all
Option C (No work at all) is correct because work is only done when there is displacement, and the wall does not move.
377 Medium
377 of 496
Understanding +4 | -1
One end of string of length ll is connected to a particle of mass ′m′'m' and the other end is connected to a small peg on a smooth horizontal table. If the particle moves in circle with speed ′v′,'v', the net force on the particle (directed towards center) will be ( TT represents the tension in the string)
View answer and explanation
Correct option: B
TT
Option B (TT) is correct because the tension in the string provides the necessary centripetal force for the circular motion.
378 Medium
378 of 496
Application +4 | -1
Velocity of a particle of mass 4 kg4 \mathrm{~kg} moving along x\mathrm{x}-axis is given as v=2(x)3/2{v}=2({x})^{3 / 2} then work done by forces acting on the particle when it moves from x=0{x}=0 to x=2 m{x}=2 \mathrm{~m} is :-
View answer and explanation
Correct option: B
64 J
Option B (64 J) is correct because the work done is equal to the change in kinetic energy, which is calculated using the given velocity function.
379 Medium
379 of 496
Understanding +4 | -1
A body of mass m is moving in a circle of radius r with a constant speed v. The force on the body is mv2r\frac{{m{v^2}}}{r} and is directed towards the centre. What is the work done by this force in moving the body over half the circumference of the circle
View answer and explanation
Correct option: B
Zero
Option B (Zero) is correct because the centripetal force is always perpendicular to the displacement, resulting in zero work done.
380 Medium
380 of 496
Application +4 | -1
A simple pendulum is oscillating with an angular amplitude 600{60^0}. If mass of bob is 50 gm, then the tension in the string at mean position (in N) is (g=10  m/s2)\left( {\mathrm{g = 10}\,\,\mathrm{m/}{\mathrm{s}^\mathrm{2}}} \right)
View answer and explanation
Correct option: A
1
Option A (1) is correct because the tension in the string at the mean position is calculated considering both the weight and the centripetal force.
381 Medium
381 of 496
Understanding +4 | -1
The speed of a particle moving in a circle is increasing. The dot product of its acceleration and velocity is
View answer and explanation
Correct option: C
positive
Option C (positive) is correct because when the speed of a particle moving in a circle is increasing, the tangential component of acceleration is in the same direction as the velocity, resulting in a positive dot product.
382 Medium
382 of 496
Understanding +4 | -1
A body is travelling in a circle at a constant speed. It
View answer and explanation
Correct option: C
has an inward radial acceleration
Option C (has an inward radial acceleration) is correct because an object moving in a circle at constant speed experiences centripetal acceleration directed towards the center.
383 Medium
383 of 496
Application +4 | -1
Power delivered to a particle varies with time as P=(3t2−2t)P=\left(3 t^2-2 t\right) watt, where ' tt ' is in seconds, then change in its kinetic energy between time t=1t=1 to t=3 st=3 \mathrm{~s}.
View answer and explanation
Correct option: A
18 J18 \mathrm{~J}
Option A (18 J18 \mathrm{~J}) is correct because it is the result of integrating the power function with respect to time between the given limits, representing the work done and thus the change in kinetic energy.
384 Medium
384 of 496
Understanding +4 | -1
When a body slides against a rough horizontal surface, the work done by friction is:
View answer and explanation
Correct option: C
Negative
Option C (Negative) is correct because the force of friction acts in the opposite direction to the displacement, resulting in negative work done.
385 Medium
385 of 496
Application +4 | -1
Consider a car moving on a straight road with a speed of 60 m/s60 \mathrm{~m} / \mathrm{s}. If the engine is switched off then the distance affer which car will be stopped is [μk=0.4][\mu_{k}=0.4]
View answer and explanation
Correct option: B
450 m450 \mathrm{~m}
Option B (450 m450 \mathrm{~m}) is correct because it is the stopping distance calculated using the work-energy theorem with the given coefficient of kinetic friction.
386 Medium
386 of 496
Application +4 | -1
A ball moving horizontally with a velocity of 2 ms−12 \mathrm{~ms}^{-1} strikes the bob of a seconds pendulum at rest. If the mass of the bob is equal to the mass of the ball and the collision is perfectly elastic, after collision the bob of the pendulum will raise to a height of (g=10 ms−2g=10 \mathrm{~ms}^{-{2}})
View answer and explanation
Correct option: D
20 cm20 \mathrm{~cm}
Option D (20 cm20 \mathrm{~cm}) is correct because it calculates the height the pendulum bob rises to after an elastic collision.
387 Medium
387 of 496
Application +4 | -1
A force of 1200 N acting on a stone by means of rope slides the stone through a distance of 10 m in a direction inclined at 600{60^0} to the force. The work done by the force is [Joules].
View answer and explanation
Correct option: B
6000
Option B (6000) is correct because the work done is calculated using W = F * S * cos(θ).
388 Medium
388 of 496
Remembering +4 | -1
A body is tided with a string and is given a circular motion with velocity v in radius r. The magnitude of the acceleration
View answer and explanation
Correct option: B
υ2r\frac{{{\upsilon ^2}}}{r}
Option B (υ2r\frac{{{\upsilon ^2}}}{r}) is correct because the centripetal acceleration of an object in circular motion is given by the formula a = v²/r.
389 Medium
389 of 496
Analyzing +4 | -1
A metal ball hits a wall and does not rebound whereas a rubber ball of the same mass on hitting the wall rebounds with the same speed. It can be concluded that
View answer and explanation
Correct option: B
Rubber ball suffers greater change in momentum
Option B (Rubber ball suffers greater change in momentum) is correct because the rubber ball rebounds, resulting in a larger change in momentum compared to the metal ball which does not rebound.
390 Medium
390 of 496
Application +4 | -1
The centripetal acceleration of a particle varies inversely with the square of the radius rof the circular path .The KE of this particle varies directly as
View answer and explanation
Correct option: D
r−1{r^{ - 1}}
Option D (r−1{r^{ - 1}}) is correct because the kinetic energy is inversely proportional to the radius of the circular path given the centripetal acceleration's dependence on the radius.
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