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JEE PHYSICS MCQ: WORK-ENERGY-POWER

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A particle of mass mm moves on a straight line with its velocity varying with the distance travelled according to the equation v=αx3/2v=\alpha x^{3 / 2}, where α\alpha is a constant. The total work done by all the forces during a displacement from x=0x=0 to x=bx=b is;
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Correct option: C
12mα2b3\frac{1}{2} m \alpha^2 b^3
Option C (12mα2b3\frac{1}{2} m \alpha^2 b^3) is correct because the work done is equal to the change in kinetic energy, which depends on the velocity as a function of distance.

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