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JEE • PHYSICS • WORK-ENERGY-POWER

Work-energy-power practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 241-270 of 535 questions

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241 Medium
241 of 535
Understanding +4 | -1
During "elastic collision"
a) There is no loss of kinetic energy
b) The bodies are perfectly elastic
c) Temporarily some of the kinetic energy is used to deform the bodies
d) After collision the bodies regain the original shape keeping the total energy constant
View answer and explanation
Correct option: B
a, b, c, d are true
Option B (a, b, c, d are true) is correct because all the statements accurately describe the characteristics of an elastic collision.
242 Medium
242 of 535
Analyzing +4 | -1
A ball is thrown up from the earth by a person and then caught by him on its return. When the ball falls towards the earth, the ratio of kinetic energies gained by the ball (KB)\left(K_B\right) and the earth (KE)\left(K_E\right) is
View answer and explanation
Correct option: C
KEKB=mBmE\frac{K_E}{K_B}=\frac{m_B}{m_E}
Option C (KEKB=mBmE\frac{K_E}{K_B}=\frac{m_B}{m_E}) is correct because the ratio of kinetic energies is inversely proportional to the ratio of masses due to conservation of momentum.
243 Medium
243 of 535
Application +4 | -1
An elastic string of unstretched length L and force constant k is stretched by a small length xx. It is further stretched by another small length y. The work done in the second stretching is
View answer and explanation
Correct option: D
12ky(2x+y)\frac{1}{2}ky\left( {2x + y} \right)
Option D (12ky(2x+y)\frac{1}{2}ky(2x + y)) is correct because it represents the work done against the elastic force when stretching from x to x+y, accounting for the initial stretch.
244 Medium
244 of 535
Analyzing +4 | -1
A girl throws a ball with initial velocity vv at an inclination of 45∘45^{\circ}. The ball strikes the smooth vertical wall at a horizontal distance dd from the girl and after rebounding returns to her hand. What is the coefficient of restitution between wall and the ball?
View answer and explanation
Correct option: B
gdv2−gd\frac{g d}{v^2-g d}
Option B (gdv2−gd\frac{g d}{v^2-g d}) is correct because it represents the coefficient of restitution derived from the collision with the wall and the return to the girl's hand.
245 Medium
245 of 535
Application +4 | -1
A ball of mass m1{m_1} is a moving with velocity vv. It collides head on elastically with a stationary ball of mass m2{m_2}. The velocity of ball becomes v/3 after collision. Then the value of the ratio m2m1\frac{{{m_2}}}{{{m_1}}} is
View answer and explanation
Correct option: B
2
Option B (2) is correct because the ratio of masses is calculated using the conservation of momentum and the coefficient of restitution for an elastic collision.
246 Medium
246 of 535
Understanding +4 | -1
Two perfoctly elastic balls of same mass m\mathrm{m} are moving with velocities u1\mathrm{u}_1 and u2\mathrm{u}_2. They collide head on elastically n\mathrm{n} times. The kinetic energy of the system finally is:
View answer and explanation
Correct option: C
12m(u12+u22)\frac{1}{2} \mathrm{m}\left(\mathrm{u}_1^2+\mathrm{u}_2^2\right)
Option C is correct because kinetic energy is conserved in an elastic collision, so the final kinetic energy is the same as the initial kinetic energy.
247 Medium
247 of 535
Application +4 | -1
A 10 m long iron chain of linear mass density 0.8  kg  m−10.8\mathrm{\;kg\;}{\mathrm{m}^{ - 1}} is hanging freely from a rigid support. If g=10  ms−2\mathrm{g} = 10\mathrm{\;m}{\mathrm{s}^{ - 2}}, then the power required to lift the chain upto the point of support in 10 s is
View answer and explanation
Correct option: D
40 W
The correct answer is D (40 W) because the power required is calculated by finding the potential energy gained by lifting the chain and dividing by the time taken.
248 Medium
248 of 535
Understanding +4 | -1
Which of the following option is not correct for inelastic collision:
View answer and explanation
Correct option: D
Velocity of seperation may be greater than velocity of approach
Option D (Velocity of separation may be greater than velocity of approach) is correct because in an inelastic collision, kinetic energy is not conserved, and the velocity of separation is always less than the velocity of approach.
249 Medium
249 of 535
Understanding +4 | -1
If F is the force required to keep a train moving at a constant speed v,the power required is
View answer and explanation
Correct option: D
Fv  Fv\;
Option D (Fv  Fv\;) is correct because power is the product of force and velocity when the train moves at a constant speed.
250 Easy
250 of 535
Remembering +4 | -1
When two bodies stick after collision, the collision is known as
View answer and explanation
Correct option: D
Total inelastic
Option D (Total inelastic) is correct because in a perfectly inelastic collision, the two bodies stick together and move as one.
251 Medium
251 of 535
Analyzing +4 | -1
Which of the following statement(s) is/are correct?

I. If momentum of a body increases by 50%50 \%, its kinetic energy will increase by 125%125 \%.

II. Kinetic energy is proportional to square of velocity.
View answer and explanation
Correct option: C
Both I and II
Option C (Both I and II) is correct because the kinetic energy increases by 125% when momentum increases by 50%, and kinetic energy is proportional to the square of velocity.
252 Medium
252 of 535
Analyzing +4 | -1
A heavy weight is suspended from a spring. A person raises the weight till the spring becomes slack. The work done by him is WW. The energy stored in the stretched spring was EE. What will be the gain in gravitational potential energy?
View answer and explanation
Correct option: C
W+EW+E
Option C (W+EW+E) is correct because the total gain in gravitational potential energy is the sum of the work done by the person and the energy stored in the spring.
253 Medium
253 of 535
Understanding +4 | -1
A stone tied to one end of rope and rotated in a circular motion. If the string suddenly breaks, then the stone travels
View answer and explanation
Correct option: D
in tangential direction
The stone travels in a tangential direction because, upon the string breaking, the centripetal force vanishes, and the stone continues its motion along the tangent to the circular path.
254 Medium
254 of 535
Application +4 | -1
A Neutron's moving with a certain kinetic energy collide head on with an atom of mass number 'AA'. Find the fraction of kinetic energy retained by it
View answer and explanation
Correct option: C
(A−1A+1)2\left(\frac{A-1}{A+1}\right)^2
Option C, (A−1A+1)2\left(\frac{A-1}{A+1}\right)^2, is correct because it represents the fraction of kinetic energy retained by the neutron after a head-on collision with an atom of mass number A, derived from the principles of conservation of energy and momentum.
255 Medium
255 of 535
Application +4 | -1
A block of mass mm moving with speed vv collides with another block of mass 2 m2 {~m} at rest. The lighter block comes to rest after the collision. The coefficient of restitution is
View answer and explanation
Correct option: A
12\frac{1}{2}
Option A (12\frac{1}{2}) is correct because the coefficient of restitution is the ratio of the relative velocity of separation to the relative velocity of approach.
256 Easy
256 of 535
Analyzing +4 | -1
The two moving particles collide and clump together on a smooth horizontal surface. The following statements are given below
a) Mechanical energy is conserved
b) Total energy is conserved
c) Work done by the system is positive
d) Work done by the system is negative
Choose the correct option.
View answer and explanation
Correct option: D
(b) and (d) are correct
Option D ((b) and (d) are correct) is correct because total energy is always conserved, and in a collision where particles clump together, kinetic energy is lost, resulting in negative work done by the system.
257 Medium
257 of 535
Application +4 | -1
A particle strikes elastically with another particle with velocity V\mathrm{V}. After the collision, it moves with half the velocity in the same direction. Find the velocity of the second particle if it is initially at rest
View answer and explanation
Correct option: A
3V2\frac{3 V}{2}
Option A (3V2\frac{{3 V}}{{2}}) is correct because it is the velocity of the second particle after the elastic collision, calculated using conservation of momentum and the coefficient of restitution.
258 Medium
258 of 535
Application +4 | -1
A block of 200 g200 \mathrm{~g} mass is dropped from a height of 2 m2 \mathrm{~m} on to a spring and compresses the spring to a distance of 50 cm50 \mathrm{~cm}. The force constant of the spring is
View answer and explanation
Correct option: B
40 Nm−140 \mathrm{~Nm}^{-1}
Option B (40 Nm−140 \text{{ Nm}}^{-1}) is correct because the potential energy lost by the block equals the potential energy stored in the spring when it's compressed.
259 Medium
259 of 535
Analyzing +4 | -1
Assertion: The resultant acceleration of an object in circular motion is towards the centre if the speed is constant.
Reason: A vector is necessarily changed if it is rotated through an angle.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C (If Assertion is True but the Reason is False) is correct because the resultant acceleration is towards the center, but a vector can change without rotation.
260 Medium
260 of 535
Understanding +4 | -1
For inelastic collision between two spherical rigid bodies
View answer and explanation
Correct option: D
The liner momentum is conserved
Option D is correct because linear momentum is always conserved in collisions if no external forces are acting, even in inelastic collisions.
261 Easy
261 of 535
Understanding +4 | -1
A particle moving with uniform speed in a circular path maintains:
View answer and explanation
Correct option: C
Varying velocity and varying acceleration
Option C is correct because while the speed is constant, the direction of the velocity and acceleration are constantly changing in uniform circular motion.
262 Medium
262 of 535
Application +4 | -1
A ship weighing 0.3×1080.3 \times {10^8} kg-wt is pulled by a force of 0.5×1050.5 \times {10^5}N through a distance of 3 m. If the ship were originally at rest and water-resistance is negligibly small, then the ship will acquire a speed of
View answer and explanation
Correct option: A
0.1  ms−10.1\mathrm{\;m}{\mathrm{s}^{ - 1}}
Option A (0.1  ms−10.1\mathrm{\;m}{\mathrm{s}^{ - 1}}) is correct because the speed is calculated by equating the work done to the kinetic energy gained by the ship.
263 Medium
263 of 535
Understanding +4 | -1
If a motorcyclist skids and stops after
covering a distance of 15 m. The stopping
force acting on the motorcycle by the road is
100 N, then the work done by the motorcycle
on the road is
View answer and explanation
Correct option: D
Zero
Option D is correct because the road does not undergo any displacement, so no work is done by the motorcycle on the road.
264 Medium
264 of 535
Understanding +4 | -1
Assertion: If work done by the force depends on path then force is said to be conservative.
Reason: All the conservative forces are central force.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D (If both Assertion & Reason are false) is correct because work done by a conservative force is path-independent, and not all conservative forces are central forces.
265 Medium
265 of 535
Analyzing +4 | -1
Assertion(A): Force applied on a block moving in one dimension is producing a constant power, then the motion should be uniformly accelerated.

Reason(R): This constant power multiplied with time is equal to the change in kinetic energy.
View answer and explanation
Correct option: D
If Assertion is incorrect but Reason is correct.
Option D is correct. The assertion is incorrect because constant power implies non-uniform acceleration, while the reason is correct as it states the work-energy theorem.
266 Medium
266 of 535
Application +4 | -1
A cane filled with water is revolved in a vertical circle of radius 4 m and the water just does not fall down. The time period of revolution will be
View answer and explanation
Correct option: D
4 sec
Option D (4 sec) is correct because it is calculated using the formula for the time period of revolution in a vertical circle.
267 Medium
267 of 535
Analyzing +4 | -1
Assertion (A): In case of bullet fired from gun, the ratio of kinetic energy of gun and bullet is equal to ratio of mass of bullet and gun.

Reason (R) : In firing, momentum is conserved.
View answer and explanation
Correct option: A
Both A\mathrm{A} and R\mathrm{R} are true and R\mathrm{R} is the correct explanation of A\mathrm{A}.
Option A is correct because momentum conservation leads to the ratio of kinetic energies being the inverse ratio of masses.
268 Easy
268 of 535
Application +4 | -1
The kinetic energy of a particle is 1000 joule with the mass 2 kg2 {~kg}. Find the momentum for the particle?
View answer and explanation
Correct option: A
201020\sqrt {10}
Option A (201020\sqrt {10}) is correct because the momentum is calculated using the relationship between kinetic energy and momentum: p=2mKp = \sqrt{2mK}.
269 Medium
269 of 535
Understanding +4 | -1
Which among the following remains conserved in all types of collisions?
View answer and explanation
Correct option: C
Linear momentum of system
Option C (Linear momentum of system) is correct because, in all types of collisions, the total linear momentum of the system remains conserved due to the absence of external forces.
270 Medium
270 of 535
Understanding +4 | -1
In stable equilibrium position, a body has
View answer and explanation
Correct option: B
Minimum potential energy
Option B (Minimum potential energy) is correct because stable equilibrium corresponds to the lowest potential energy state.
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