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JEE • PHYSICS • WORK-ENERGY-POWER

Work-energy-power practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 421-450 of 535 questions

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421 Medium
421 of 535
Remembering +4 | -1
A body is tided with a string and is given a circular motion with velocity v in radius r. The magnitude of the acceleration
View answer and explanation
Correct option: B
υ2r\frac{{{\upsilon ^2}}}{r}
Option B (υ2r\frac{{{\upsilon ^2}}}{r}) is correct because the centripetal acceleration of an object in circular motion is given by the formula a = v²/r.
422 Medium
422 of 535
Analyzing +4 | -1
A metal ball hits a wall and does not rebound whereas a rubber ball of the same mass on hitting the wall rebounds with the same speed. It can be concluded that
View answer and explanation
Correct option: B
Rubber ball suffers greater change in momentum
Option B (Rubber ball suffers greater change in momentum) is correct because the rubber ball rebounds, resulting in a larger change in momentum compared to the metal ball which does not rebound.
423 Medium
423 of 535
Application +4 | -1
The centripetal acceleration of a particle varies inversely with the square of the radius rof the circular path .The KE of this particle varies directly as
View answer and explanation
Correct option: D
r−1{r^{ - 1}}
Option D (r−1{r^{ - 1}}) is correct because the kinetic energy is inversely proportional to the radius of the circular path given the centripetal acceleration's dependence on the radius.
424 Medium
424 of 535
Application +4 | -1
In a shotput event an athlete throws the shotput of mass 10 kg10 \mathrm{~kg} with an initial speed of 1 ms−11 \mathrm{~m} \mathrm{s}^{-1} at 45∘45^{\circ} from a height 1.5 m above ground. Assuming a irresistance to be negligible and acceleration due to gravity to be 10 ms−210 \mathrm{~m} \mathrm{s}^{-2}, the kinetic energy of the shotput when it just reaches the ground will be
View answer and explanation
Correct option: D
155.0 J155.0 \mathrm{~J}
Option D (155.0 J155.0 \mathrm{~J}) is correct because the final kinetic energy is calculated using the conservation of mechanical energy, considering both initial potential and kinetic energies.
425 Medium
425 of 535
Application +4 | -1
The potential energy of an object of mass mm moving in xyxy plane in a conservative field is given by U=ax+by{U}={ax}+{by}, where x{x} and y{y} are position coordinates of the object. Find magnitude of its acceleration:
View answer and explanation
Correct option: A
a2+b2m\frac{\sqrt{a^2+b^2}}{m}
Option A (a2+b2m\frac{\sqrt{a^2+b^2}}{m}) is correct because the magnitude of the acceleration is the magnitude of the force divided by the mass, and the force is derived from the potential energy.
426 Medium
426 of 535
Understanding +4 | -1
Assertion: Centripetal acceleration is applied in the direction of the centre of rotation of an object during uniform circular motion.
Reason: Centripetal acceleration is a constant vector.
View answer and explanation
Correct option: C
If assertion is true but reason is false
Option C (If assertion is true but reason is false) is correct because centripetal acceleration is directed towards the center, but it's not a constant vector as its direction continuously changes.
427 Medium
427 of 535
Application +4 | -1
A porter with a suitcase of mass 20 kg20 \mathrm{~kg} on his head moves up a staircase upto a height of 4 m4 \mathrm{~m}. The amounts of work done by the upward lifting force relative to him and relative to a person on the ground respectively, are
View answer and explanation
Correct option: A
0;800 J0 ; 800 \mathrm{~J}
Option A (0;800 J0 ; 800 \mathrm{~J}) is correct because the work done by the porter relative to himself is zero, while relative to the ground is calculated using the formula W = mgh.
428 Medium
428 of 535
Application +4 | -1
A police officer fires a bullet of mass 50 gm50 \,{gm} with speed 400 m/s400 {~m} / {s} on soft plywood of thickness 2 cm2 {~cm}. The bullet emerges with only 25%25 \% of it's kinetic energy. What is the emergent speed of the bullet?
View answer and explanation
Correct option: C
200 m/s200 {~m} / {s}
Option C (200 m/s) is correct because it accurately calculates the emergent speed of the bullet using the given kinetic energy reduction.
429 Medium
429 of 535
Analyzing +4 | -1
Two students are sitting face to face, at two ends of a long compartment of a train, running at a constant acceleration. They toss a ball to each other, with the same muzzle velocity and at the same inclination to the vertical.
Statement-1: The time intervals for the free fall in either direction are equal.
Statement-2: In the frame of compartment velocity is changing but the vertical velocity remains unaffected by the horizontal acceleration of the cart.
View answer and explanation
Correct option: A
Statement-1 and Statement-2 are true, Statement-2 is the correct explanation for Statement-1
Option A (Statement-1 and Statement-2 are true, Statement-2 is the correct explanation for Statement-1) is correct because the time intervals are equal due to the vertical velocity being unaffected by the horizontal acceleration.
430 Medium
430 of 535
Application +4 | -1
A force of 5 N moves the particle through a distance of 10 m. If 25 J of work is performed, then the angle between the force and the direction of motion is
View answer and explanation
Correct option: D
600{60^0}
Option D (600{60^0}) is correct because it is derived from the work formula W=Fscos⁡θW = Fs \cos \theta, solving for θ\theta.
431 Medium
431 of 535
Analyzing +4 | -1
Three identical balls A,B and C are lying on a horizontal frictionless table as shown in figure. If ball A is imparted a velocity v towards B and C and the collisions are perfectly elastic, then finally
View answer and explanation
Correct option: B
Ball A and B are a rest and ball C roll out with speed v
Option A (Statement-I & II are true) is correct because pushing a block increases the normal reaction, leading to greater friction and thus more work done.
432 Medium
432 of 535
Understanding +4 | -1
Two identical bodies are executing uniform circular motion in the paths of radii r1{r_1} and r2{r_2} respectively. If both the bodies complete one revolution in the same time interval, then the ratio of their angular speeds is
View answer and explanation
Correct option: D
1:11:1
Option D (1:11:1) is correct because angular speed depends only on the time for one revolution, which is the same for both bodies.
433 Medium
433 of 535
Analyzing +4 | -1
Assertion: A light body and a heavy body have same momentum. Then they also have same kinetic energy.
Reason: Kinetic energy does not depend on mass of the body.
View answer and explanation
Correct option: D
If both assertion and reason are false
The correct answer is D because if two bodies have the same momentum, their kinetic energies are inversely proportional to their masses, and kinetic energy does depend on mass.
434 Medium
434 of 535
Application +4 | -1
A body of mass 1 kg1 \mathrm{~kg} is moving in a vertical circular path of radius 1 m1 \mathrm{~m}. The difference between the kinetic energies at its highest and lowest position is
View answer and explanation
Correct option: A
20 J20 \mathrm{~J}
Option A (20 J20 \mathrm{~J}) is correct because the difference in kinetic energy is equal to the change in potential energy, which is 2mgr2mgr.
435 Medium
435 of 535
Application +4 | -1
A meter stick of mass 400 g400 \mathrm{~g} lying horizontally is pivoted at one end and displaced through an angle 60∘60^{\circ}. The increase in its potential energy is
View answer and explanation
Correct option: A
2 J2 \mathrm{~J}
Option A (2 J2 \mathrm{~J}) is correct because the increase in potential energy is calculated using the formula PE=mghPE = mgh, where hh is the change in height of the center of mass.
436 Medium
436 of 535
Understanding +4 | -1
Identify the wrong statement
View answer and explanation
Correct option: A
A body can have momentum without energy
Option A (A body can have momentum without energy) is the wrong statement because if a body has momentum, it must also have kinetic energy.
437 Medium
437 of 535
Application +4 | -1
A dam is situated at a height of 550 m above sea level and supplies water to a power house which is at a height of 50 m above sea level. 2000 kg of water passes through the turbines per second. What would be the maximum electrical power output of the power house if the whole system were 80% efficient?
View answer and explanation
Correct option: A
8 MW
Option A (8 MW) is correct because it is the maximum electrical power output calculated considering the efficiency and the potential energy conversion.
438 Medium
438 of 535
Understanding +4 | -1
In uniform circular motion, the velocity vector and acceleration vector are
View answer and explanation
Correct option: A
Perpendicular to each other
Option A (Perpendicular to each other) is correct because in uniform circular motion, the velocity is tangential and the acceleration is radial, making them perpendicular.
439 Medium
439 of 535
Application +4 | -1
If momentum of a body increases by 30%30 \% then percentage increase in its KEKE will be
View answer and explanation
Correct option: C
69%69 \%
Option C (69%69 \%) is correct because the kinetic energy increases by 69% when momentum increases by 30%.
440 Medium
440 of 535
Application +4 | -1
Two balls of masses 2g and 6g are moving with KE in the ratio of 3:13:1. What is the ratio of their linear momenta?
View answer and explanation
Correct option: A
1:11:1
Option A (1:11:1) is correct because the ratio of kinetic energies and masses leads to equal linear momenta.
441 Medium
441 of 535
Application +4 | -1
A hollow sphere has radius 6.4 m. minimum velocity required by a motor cyclist at bottom to complete the circle will be [in m/s]
View answer and explanation
Correct option: A
17.7
Option A (17.7 m/s) is correct because it is the minimum velocity required to complete the circle, calculated using the formula Vmin=5grV_{min} = \sqrt{5gr}.
442 Medium
442 of 535
Application +4 | -1
A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m, 1000 times. Assume that the potential energy lost each time he lowers the mass is dissipated. How much fat will he use up considering the work done only when the weight is lifted up? Fat supplies 3.8×107 J3.8 \times {10^7}\,J of energy per kg which is converted to mechanical energy with a 20% of efficiency rate. (Take, g=9.8 ms−2g = 9.8\,m{s^{ - 2}})
View answer and explanation
Correct option: D
12.89×10−3 kg12.89 \times {10^{ - 3}}\,kg
Option D (12.89×10−3 kg12.89 \times {10^{ - 3}}\,kg) is correct because it is the mass of fat that will be used up, calculated using the potential energy gained and the efficiency rate.
443 Medium
443 of 535
Analyzing +4 | -1
The vessels AA and BB of equal volume and weight are immersed in water to depth hh. The vessel AA has an opening at the bottom through which water can enter. If the work done in immersing AA and BB are WAW_A and WBW_B respectively, then
View answer and explanation
Correct option: B
WA>WBW_A>W_B
Option C (WA < WB) is correct because the work done in immersing A is less than that in immersing B, as water enters A, making it heavier and requiring less external work.
444 Medium
444 of 535
Application +4 | -1
A stone of mass 1 kg tied to the end of a string of length 1 m, is whirled in a horizontal circle with a uniform angular velocity 2 rads−1\mathrm{rad}{\mathrm{s}^{ - 1}}. The tension of the string is (in newton)
View answer and explanation
Correct option: C
4
The correct answer is 4 because the tension in the string is equal to the centripetal force, which can be calculated using the given mass, radius, and angular velocity.
445 Medium
445 of 535
Understanding +4 | -1
For an isolated system in the absence of any dissipative effect
a) KE is conserved
b) PE is conserved
c) Energy is conserved
d) ME is conserved
View answer and explanation
Correct option: C
c, d
Option C (c, d) is correct because in an isolated system without dissipative effects, total energy and mechanical energy are conserved.
446 Medium
446 of 535
Understanding +4 | -1
When force and displacement are in the same direction, the kinetic energy of the body:
View answer and explanation
Correct option: A
Increases
Option A is correct. When force and displacement are in the same direction, the work done is positive, resulting in an increase in the kinetic energy of the body.
447 Medium
447 of 535
Application +4 | -1
A ball is thrown vertically upwards with a velocity of 20 m/s20 \mathrm{~m} / \mathrm{s}. At what height, will its kinetic energy be half its original value?
View answer and explanation
Correct option: A
10.20 m
Option A (10.20 m) is correct because it is the height at which the potential energy equals half the initial kinetic energy, calculated using conservation of energy.
448 Medium
448 of 535
Analyzing +4 | -1
A body moves along a path PQR\mathrm{PQR} in horizontal plane from P\mathrm{P} to R\mathrm{R}. When the particle is at Q\mathrm{Q}, its speed is decreasing. The acceleration of the particle at Q\mathrm{Q} is best represented by the vector.(A, B, C and D are vectors)
View answer and explanation
Correct option: C
C\mathrm{C}
Option C (C) is correct because the acceleration vector at Q must have components both opposite to the velocity (to decrease speed) and towards the center of curvature.
449 Medium
449 of 535
Analyzing +4 | -1
A certain body of mass MM moves under the action of a conservative force with potential energy UU given by U=Kxx2+a2(x→U=\frac{K x}{x^2+a^2}(x \rightarrow distance, a→a \rightarrow amplitude)) In this equation the units of K{K} will be equal to that of:
View answer and explanation
Correct option: C
Joule-metre
Option C (Joule-metre) is correct because the units of K are derived from the potential energy equation, resulting in Joule-metre.
450 Medium
450 of 535
Application +4 | -1
A force acts on a 3 g3 \mathrm{~g} particle in such a way that position of particle as a function of time is given by x=3t−4t2+t3x=3 t-4 t^2+t^3, where xx is in metre and tt is in sec. The work done during first 4 s4 \mathrm{~s} is
View answer and explanation
Correct option: D
528 mJ528 \mathrm{~mJ}
Option D (528 mJ528 \mathrm{~mJ}) is correct because it is the work done calculated by integrating the force over the displacement during the first 4 seconds.
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