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JEE PHYSICS MCQ: WORK-ENERGY-POWER

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A box of mass mm is initially at rest on a horizontal surface. A constant horizontal force of mg/2{mg} / 2 is applied to the box directed to the right. The coefficient of friction of the surface changes with the distance pushed as m=m0xm=m_0 x where xx is the distance from the initial location. For what distance is the box pushed until it comes to rest again?
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Correct option: B
1μ0\frac{1}{\mu_0}
Option B (1μ0\frac{1}{\mu_0}) is correct because the box comes to rest when the work done by the applied force equals the work done by friction.

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