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JEE • PHYSICS • WAVES

Waves practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 91-120 of 524 questions
91 Medium
91 of 524
Understanding +4 | -1
In the case of sustained forced oscillations, the amplitude of oscillations
View answer and explanation
Correct option: D
Always remains constant
Option D (Always remains constant) is correct because in sustained forced oscillations, an external force continuously compensates for energy losses, maintaining a constant amplitude.
92 Medium
92 of 524
Understanding +4 | -1
Choose the false statement(s) about speed of transverse waves on a stretched string.
(i) It depends on linear mass density of the string.
(ii) It depends on the tension in the string in.
(iii) It depends on the frequency of the wave.
View answer and explanation
Correct option: C
(iii) only
Option C ((iii) only) is correct because the speed of a transverse wave on a string depends on tension and linear mass density, but not the frequency of the wave.
93 Medium
93 of 524
Understanding +4 | -1
Assertion(A): If temperature is increased, fundamental frequency of an close pipe will increase.

Reason(R): By increasing the temperature, speed of sound wave will increase.
View answer and explanation
Correct option: A
If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
Option A is correct because increasing temperature increases the speed of sound, which in turn increases the fundamental frequency of a closed pipe.
94 Medium
94 of 524
Application +4 | -1
In order to double the frequency of the fundamental note emitted by a stretched string, the length is reduced to 3/4th3/4th of the original length and the tension is changed. The factor by which the tension is to be changed, is
View answer and explanation
Correct option: D
9/49/4
Option D (9/49/4) is correct because the frequency is inversely proportional to length and directly proportional to the square root of tension.
95 Medium
95 of 524
Application +4 | -1
Two waves of frequencies 20 Hz20 \mathrm{~Hz} and 30 Hz30 \mathrm{~Hz} travel out from a common point. How will they differ in phase at the end of 0.75 second?
View answer and explanation
Correct option: A
15π15 \pi
Option A (15π15 \pi) is correct because the phase difference is calculated using the formula δϕ=(ω2−ω1)t\delta \phi = (\omega_2 - \omega_1)t.
96 Medium
96 of 524
Application +4 | -1
A U-tube having unequal arm-lengths has water in it. A tuning fork of frequency 440 Hz440 \mathrm{~Hz} can set up the air in the shorter arm in its fundamental mode of vibration and the same tuning fork can set up the air in the longer arm in its first overtone vibration. Find the length of the air columns. Neglect any end effect and assume that the speed of sound in air =330 ms−1=330 \mathrm{~ms}^{-1}.
View answer and explanation
Correct option: A
18.8 cm, 56.3 cm
Option A (18.8 cm, 56.3 cm) is correct because the lengths are calculated using the fundamental frequency and first overtone conditions for open and closed pipes respectively.
97 Medium
97 of 524
Analyzing +4 | -1
The fundamental frequency of a vibrating organ pipe is 10 Hz10 \mathrm{~Hz}. Select the wrong alternative.
View answer and explanation
Correct option: C
The first overtone may be 300 Hz300 \mathrm{~Hz}
The correct answer is C. The first overtone may be 300 Hz because for an open pipe, the first overtone is 200 Hz, and for a closed pipe, it is 300 Hz, so 300 Hz is possible.
98 Medium
98 of 524
Remembering +4 | -1
Define Mach Number.
View answer and explanation
Correct option: C
It is the ratio of the velocity of an object to the velocity of sound.
Option C (It is the ratio of the velocity of an object to the velocity of sound) is correct because the Mach number is defined as the speed of an object divided by the speed of sound in the same medium.
99 Medium
99 of 524
Understanding +4 | -1
The engine of a train sounds a whistle at frequency vv. The frequency heard by a passanger is (If wind is blowing from passanger side to Train side):
View answer and explanation
Correct option: D
=v=v
Option D (=v) is correct because the wind blowing from the passenger to the train does not create a relative motion between the source (train) and the observer (passenger), so there is no Doppler effect and the frequency heard is the same as the emitted frequency.
100 Medium
100 of 524
Application +4 | -1
Two stretched strings have lengths ll and 2l2l while tensions are T and 4T respectively. If they are made of same material the ratio of their frequency is
View answer and explanation
Correct option: C
0.042361111
Option C (01:01) is correct because the ratio of frequencies is 1:1 when calculated using the formula for frequency of a stretched string.
101 Medium
101 of 524
Application +4 | -1
An observer moves towards a stationery source of sound with a velocity one-fifth of the velocity of sound. The percentage increase in the apparent frequency is
View answer and explanation
Correct option: B
0.2
Option B (0.2) is incorrect. The percentage increase is calculated to be 20%, not 0.2. The correct percentage increase in apparent frequency is 20%.
102 Medium
102 of 524
Application +4 | -1
The amplitude of a damped oscillator decreases to 0.9 times its original magnitude is 5 s. In another 10 s, it will decrease to α\alpha times its original magnitude, where α\alpha equals
View answer and explanation
Correct option: C
0.729
Option C (0.729) is correct because the amplitude decreases exponentially, and after 15 seconds, it will be 0.729 times the original amplitude.
103 Medium
103 of 524
Application +4 | -1
A long string, having a cross-sectional area 0.80 mm20.80 \mathrm{~mm}^2 and density 12.5 g/cm312.5 \mathrm{~g} / \mathrm{cm}^3 is subjected to a tension of 64 N along the x-axis. One end of the string is attached to a vibrator moving in transverse direction. At t=0,t=0, the source is at maximum displacement y=1 cm.y=1 \mathrm{~cm}. Find the speed of wave travelling on the string.
View answer and explanation
Correct option: B
80 m/s
Option B (80 m/s) is correct because the speed of the wave is calculated using the formula involving tension, density, and cross-sectional area of the string.
104 Medium
104 of 524
Understanding +4 | -1
Which of the following equations represents a wave?
View answer and explanation
Correct option: C
y=A  sin⁡(at−dx+c)y = A\,\,\sin \left( {at - dx + c} \right)
Option C, y=A sin⁡(at−dx+c)y = A\,\sin \left( {at - dx + c} \right), correctly represents a wave because it includes a sinusoidal function with arguments representing both time and position.
105 Medium
105 of 524
Application +4 | -1
If the successive frequencies in a one end closed organ pipe are 245 and 315 Hz315 \mathrm{~Hz} respectively, then the frequency of third overtone will be
View answer and explanation
Correct option: C
245 Hz245 \mathrm{~Hz}
Option C (245 Hz) is correct because it represents the frequency of the third overtone in a one-end closed organ pipe.
106 Medium
106 of 524
Understanding +4 | -1
The speed of sound in a medium depends on
View answer and explanation
Correct option: C
Both on inertial and elastic property of medium
Option C is correct because the speed of sound depends on both the elastic properties (like bulk modulus) and the inertial properties (like density) of the medium.
107 Medium
107 of 524
Application +4 | -1
A microphone of cross-sectional area ' 0.40′cm20.40 ' \mathrm{cm}^2 is placed in front of the small speaker emitting πW\pi \mathrm{W} of sound output. If the distance between microphone and the speaker is 2.0 m2.0 \mathrm{~m}, how much energy falls on the microphone in 5.0 s5.0 \mathrm{~s} ?
View answer and explanation
Correct option: A
12.5μJ12.5 \mu \mathrm{J}
Option A (12.5μJ12.5 \mu \mathrm{J}) is correct because it is calculated by finding the intensity of sound at the microphone and then multiplying by the area and time.
108 Medium
108 of 524
Understanding +4 | -1
Speed of sound wave in air
View answer and explanation
Correct option: C
Increases with increase in humidity
Option C is correct. The speed of sound increases with an increase in humidity because the density of air decreases as humidity increases.
109 Medium
109 of 524
Understanding +4 | -1
For a sinusoidal wave represented by y(x,t)=asin⁡(kx−ωt+ϕ)y(x, t)=a \sin (k x-\omega t+\phi) for a given aa, the factor determines the displacement of the wave of any position and at any instant is:
View answer and explanation
Correct option: D
Phase (kx−ωt+ϕ)(k x-\omega t+\phi)
Option D (Phase (kx−ωt+ϕ)(k x-\omega t+\phi)) is correct because the phase determines the displacement of the wave at any point and time.
110 Medium
110 of 524
Application +4 | -1
If the adiabatic constants for helium and hydrogen gases at the same temperature are 5/35 / 3 and 7/57 / 5 respectively, then the ratio of velocity of sound in these gases will be-
View answer and explanation
Correct option: A
5:425: \sqrt{42}
Option A (5:425: \sqrt{42}) is correct because it is the ratio of velocities of sound in helium and hydrogen calculated using the given adiabatic constants and molecular weights.
111 Medium
111 of 524
Understanding +4 | -1
Frequencies of sound produced from an organ pipe open at both ends are:
View answer and explanation
Correct option: D
Even and odd harmonics
Option D (Even and odd harmonics) is correct because an organ pipe open at both ends produces all harmonics (both even and odd).
112 Medium
112 of 524
Understanding +4 | -1
Which of the following functions represent a wave?
View answer and explanation
Correct option: C
e−(x+vt)2{e^{ - \left( {x + vt} \right)2}}
The correct answer is C (e−(x+vt)2{e^{ - \left( {x + vt} \right)2}}) because this function represents a wave due to its finite value at all times and its form.
113 Medium
113 of 524
Understanding +4 | -1
Which one of the following is a simple harmonic motion
View answer and explanation
Correct option: A
Wave moving through a string fixed at both ends
Option A (Wave moving through a string fixed at both ends) is correct because it exhibits oscillatory motion with a restoring force proportional to the displacement, a characteristic of SHM.
114 Medium
114 of 524
Application +4 | -1
The pressure wave p=0.01sin⁡[1000t−3x]Nm−2, p = 0.01\sin \left[ {1000t - 3x} \right]N{m^{ - 2}},\, corresponds to the sound produced by a vibrating blade on a day when atmospheric temperature is 0∘C0^\circ C. On some other day when temperature is TT, the speed of sound produced by the same blade and at the same frequency is found to be 336  ms−1336\;m{s^{ - 1}}. Approximate value of TT is
View answer and explanation
Correct option: D
4∘C4^\circ C
Option D (4∘C4^{\circ} C) is correct because the temperature is calculated using the relationship between the speed of sound and temperature.
115 Medium
115 of 524
Understanding +4 | -1
The complete destructive interference of two sound waves takes place when the two waves are travelling in the same direction
View answer and explanation
Correct option: B
With the same frequency and amplitude and are
in opposite phase
Option B (With the same frequency and amplitude and are in opposite phase) is correct because destructive interference occurs when waves are out of phase.
116 Medium
116 of 524
Understanding +4 | -1
If vv is the speed of sound in air then the shortest length of the closed pipe which resonates to a frequency vv, is
View answer and explanation
Correct option: B
v4v\frac{v}{{4v}}
Option B is correct. For a closed pipe, the shortest length that resonates at a frequency vv is given by l=v4vl = \frac{v}{4v}.
117 Medium
117 of 524
Application +4 | -1
The velocity of sound in a gas, in which two wavelengths 4.08 m  and 4.16 m4.08\,{\text{m}}\,\,{\text{and}}\,{\text{4}}{\text{.16}}\,{\text{m}} produce 40 beats in 12 s, will be:
View answer and explanation
Correct option: D
707.2 ms−1707.2\,m{s^{ - 1}}
Option D (707.2 ms−1707.2\,m{s^{ - 1}}) is correct because it is calculated by finding the velocity from the beat frequency and the two wavelengths.
118 Medium
118 of 524
Application +4 | -1
In a resonance tube, closed at one end by a smooth moving piston and the other end open, exhibits the first three resonance lengths of air column, L1,L2L_1, L_2 and L3L_3 for the same tuning fork. Then, they are related as
View answer and explanation
Correct option: B
L3=53L2=5L1L_3=\frac{5}{3} L_2=5 L_1
Option B (L3=53L2=5L1L_3=\frac{5}{3} L_2=5 L_1) is correct because it correctly relates the first three resonance lengths in a closed-open tube.
119 Medium
119 of 524
Understanding +4 | -1
Walls of auditorium should be
View answer and explanation
Correct option: A
Good absorber
Option A (Good absorber) is correct because walls of an auditorium should absorb sound to reduce reverberation and create clear acoustics.
120 Medium
120 of 524
Understanding +4 | -1
Statement-I: The change in frequency due to Doppler effect does not depend on separation between the source and the observer.
Statement-II: When a listener and sound source are moving with the same velocity in the same direction, the apparent frequency as heard by listener increases.
View answer and explanation
Correct option: A
Statement-I is correct
Option A is correct because the Doppler effect depends on the relative velocities of the source and observer, not the distance between them.
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