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JEE • PHYSICS • WAVES

Waves practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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421 Medium
421 of 524
Application +4 | -1
If the frequency of sound produced by a siren increases from 400 Hz400 \mathrm{~Hz} to 1200 Hz1200 \mathrm{~Hz} while the wave amplitude remains constant, the ratio of the intensity of the 1200 Hz1200 \mathrm{~Hz} to that of the 400 Hz400 \mathrm{~Hz} wave will be
View answer and explanation
Correct option: D
9:19: 1
Option D (9:19: 1) is correct because the intensity of a sound wave is proportional to the square of its frequency, so when the frequency triples, the intensity increases by a factor of nine.
422 Medium
422 of 524
Analyzing +4 | -1
A wave represented by the given equation y=acos⁡(kx−ωt)y=a \cos (k x-\omega t) is superposed with another wave to form a stationary wave such that the point x=0x=0 is a node. The equation for the other wave is
View answer and explanation
Correct option: B
y=−acos⁡(kx+ωt)y=-a \cos (k x+\omega t)
Option B (y=−acos⁡(kx+ωt)y=-a \cos (k x+\omega t)) is correct because when superposed with y=acos⁡(kx−ωt)y=a \cos (k x-\omega t), it creates a stationary wave with a node at x=0 due to the phase difference of π\pi.
423 Medium
423 of 524
Analyzing +4 | -1
Assertion: On a rainy day sound travels slower than on a dry day.
Reason: When moisture is present in air the density of air increases.
View answer and explanation
Correct option: D
If both assertion and reason are false
Option D (If both assertion and reason are false) is correct because sound travels faster on a rainy day due to lower density of moist air.
424 Medium
424 of 524
Analyzing +4 | -1
Choose the correct statement from the following options.
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because all three statements regarding the speed of sound, sound absorption, and adiabatic processes are accurate.
425 Medium
425 of 524
Understanding +4 | -1
What is the effect of increase in temperature on the frequency of sound produced by an organ pipe?
View answer and explanation
Correct option: A
increases
Option A (increases) is correct because the speed of sound increases with temperature, leading to an increase in frequency.
426 Medium
426 of 524
Application +4 | -1
A set of 16 tuning forks are so arranged that each produce 4 beats with the previous one. If the frequency of last tuning fork is double that of first, the frequency of third tuning fork is
View answer and explanation
Correct option: A
68 Hz68 \mathrm{~Hz}
Option A (68 Hz) is correct because the frequency of each subsequent tuning fork increases by 4 Hz, and the frequency of the third tuning fork can be calculated accordingly.
427 Medium
427 of 524
Application +4 | -1
A Kundt's tube apparatus has a copper rod of length 1.0 m1.0 \mathrm{~m} clamped at 25 cm25 \mathrm{~cm} from one of the ends. The tube contains air in which the speed of sound is 340 m/s340 \mathrm{~m} / \mathrm{s}. The powder collects in heaps separated by a distance of 5.0 cm5.0 \mathrm{~cm}. Find the speed of sound waves in copper.
View answer and explanation
Correct option: A
3400 m/s
Option A (3400 m/s) is correct because the speed of sound waves in copper is calculated using the relationship between the speed of sound in the rod and the air, and the lengths of the rod and the distance between heaps.
428 Medium
428 of 524
Understanding +4 | -1
Statement-I: In transverse wave particle velocity is perpendicular to wave velocity.
Statement-II: In a longitudinal wave particle velocity is along the direction of propagation of wave.
View answer and explanation
Correct option: C
Both statement-I &\& II are correct
Option C (Both statement-I &IIarecorrect)iscorrectbecauseitaccuratelydescribestherelationshipbetweenparticleandwavevelocitiesintransverseandlongitudinalwaves.\& II are correct) is correct because it accurately describes the relationship between particle and wave velocities in transverse and longitudinal waves.
429 Medium
429 of 524
Understanding +4 | -1
A linearly polarised electromagnetic wave in vacuum is E=3.1cos⁡ [(1.8)z−(5.4×106)t]   i^  N/CE = 3.1\cos \,[(1.8)z - (5.4 \times {10^6})t]\,\,\widehat {\,i}\,\,N/C is incident
normally on a perfectly reflecting wall at z=az = a.
Choose the correct option.
View answer and explanation
Correct option: D
The reflected wave will be 3.1cos⁡[(1.8)z+(5.4×106)t]  i^  N/C3.1\cos [(1.8)z + (5.4 \times {10^6})t]\,\,\widehat i\;N/C
Option D is correct because the reflected wave will have the same amplitude and frequency, but the direction of propagation will be reversed, resulting in a change in sign in front of the z term.
430 Medium
430 of 524
Application +4 | -1
Each of the two strings of length 51.6  cm51.6\,\,cm and 49.1  cm49.1\,\,cm are tensioned separately by 20  N20\,\,N force. Mass per unit length of both the strings is same and equal to 1  g/m1\,\,g/m. When both the string vibrate simultaneously the number of beats is
View answer and explanation
Correct option: B
77
Option B (7) is correct because it is the number of beats calculated from the difference in frequencies of the two strings, using the formula for frequency of a vibrating string.
431 Medium
431 of 524
Application +4 | -1
A source oscillates with a frequency 25 Hz25 \mathrm{~Hz} and the wave propagates with 300 m/s300 \mathrm{~m} / \mathrm{s}. Two points AA and BB are located at distances 10 m10 \mathrm{~m} and 16 m16 \mathrm{~m} away from the source. The phase difference between AA and BB is
View answer and explanation
Correct option: C
π\pi
Option C (π\pi) is correct because the phase difference is calculated using the formula Δϕ=2πλΔx\Delta \phi = \frac{{2 \pi}}{\lambda} \Delta x, where Δx\Delta x is the path difference.
432 Medium
432 of 524
Analyzing +4 | -1
Assertion (A): The fundamental frequency of an organ pipe decreases as the temperature increases.
Reason (R): As the temperature increases, the velocity of sound increases more rapidly than length of the pipe during expansion.
View answer and explanation
Correct option: D
Assertion (A) is false, and Reason (R) is true
Option D is correct. The assertion is false because the fundamental frequency increases with temperature, while the reason is true because the velocity of sound increases more rapidly than the length of the pipe.
433 Medium
433 of 524
Application +4 | -1
If L1{L_1} and L2{L_2} are the lengths of the first and second resonating air columns in a resonance tube, then the wavelength of the note produced is
View answer and explanation
Correct option: B
2(L2−L1)2\left( {{L_2} - {L_1}} \right)
Option B (2(L2−L1)2\left( {{L_2} - {L_1}} \right)) is correct because the wavelength is twice the difference between the second and first resonating lengths in a resonance tube experiment.
434 Medium
434 of 524
Understanding +4 | -1
Which two of the given transverse waves will give stationary waves when get superimposed
z1=acos⁡(kx−ωt){z_1} = a\cos \left( {kx - \omega t} \right) …(AA)
z2=acos⁡(kx+ωt){z_2} = a\cos \left( {kx + \omega t} \right) …(BB)
z3=acos⁡(ky−ωt){z_3} = a\cos \left( {ky - \omega t} \right) …(CC)
View answer and explanation
Correct option: A
A  and  B\begin{array}{llllllllllllllllllll} {A\,\,and\,\,B} \end{array}
Option A (A and B) is correct because stationary waves are formed by the superposition of two waves with the same amplitude and frequency traveling in opposite directions.
435 Medium
435 of 524
Understanding +4 | -1
Two tuning forks of frequencies 512 Hz512 \mathrm{~Hz} and 524 Hz524 \mathrm{~Hz} respectively are vibrated simultaneously. The beat frequency heard will be-
View answer and explanation
Correct option: B
Beats will not be heard
Option C (12 Hz12 \mathrm{~Hz}) is correct because the beat frequency is the absolute difference between the two frequencies, which is 12 Hz.
436 Medium
436 of 524
Analyzing +4 | -1
Assertion (A) : Two waves y1=Asin⁡(ωt+kx)y_1=A \sin (\omega t+k x) and y2=Acos⁡(ωt−kx)y_2=A \cos (\omega t-k x) are superimposed, then x=0x=0 becomes a node.

Reason (R) : At node net displacement due to two waves should be zero.
View answer and explanation
Correct option: D
If Assertion is false but the Reason is true.
Option D (If Assertion is false but the Reason is true) is correct because the assertion is false as x=0 is not a node, but the reason is true as a node requires zero net displacement.
437 Medium
437 of 524
Understanding +4 | -1
Assertion (A): When a transverse wave propagates along a string it transports energy in two forms : kinetic energy and potential energy.
Reason (R): A transverse pulse reflected from a fixed end gets inverted.
View answer and explanation
Correct option: B
Both Assertion and Reason are true but Reason is not the correct explanation of Assertion
Option B is correct because both the assertion and reason are true, but the reason does not explain the assertion. The energy transport and pulse inversion are independent phenomena.
438 Medium
438 of 524
Application +4 | -1
A sonometer is set on the floor of a lift. When the lift is at rest, the sonometer wire vibrates with fundamental frequency 256 Hz. When the lift goes up with acceleration a=9g16a = \frac{{9g}}{{16}} vibration of the same wire changes to
View answer and explanation
Correct option: B
320 Hz
Option B (320 Hz) is correct because the frequency changes due to the effective acceleration in the lift.
439 Medium
439 of 524
Application +4 | -1
In Quincke's experiment the sound detected is changed from a maximum to a minimum when the sliding tube is moved through a distance of 2.50 cm2.50 \mathrm{~cm}. Find the frequency of sound if the speed of sound in air is 340 ms−1340 \mathrm{~ms}^{-1}.
View answer and explanation
Correct option: A
3.4 kHz
Option A (3.4 kHz) is correct because the frequency is calculated using the relationship between wavelength, speed, and the distance the sliding tube moved.
440 Medium
440 of 524
Analyzing +4 | -1
Assertion: If a vibrating tuning fork is held near the ear and given one full rotation, then intensity of sound becomes maximum four times and minimum two times.
Reason: A stationary wave transmits energy.
View answer and explanation
Correct option: D
If both assertion and reason are false
Option D (If both assertion and reason are false) is correct because the intensity of sound becomes maximum and minimum four times each, and stationary waves do not transmit energy.
441 Medium
441 of 524
Understanding +4 | -1
Which of the following statements are true for wave motion?
View answer and explanation
Correct option: C
Mechanical transverse waves can propagate through solids only
Option C (Mechanical transverse waves can propagate through solids only) is correct because transverse waves require a medium with shear strength, which is present in solids but not in fluids.
442 Medium
442 of 524
Analyzing +4 | -1
Assertion: In a medium group velocity is greater than phase velocity.
Reason: dvdλ\frac{dv}{d\lambda} is ++ve.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D is correct because both the assertion and the reason are false; group velocity can be less than phase velocity, and dvdλ\frac{{dv}}{{d\lambda}} can be negative.
443 Medium
443 of 524
Analyzing +4 | -1
A wave pulse in string is described by the equation y1=5(3x−4t)2+2{y}_1=\frac{5}{(3 x-4 t)^2+2} and another wave pulse in the same string is described by y2=−5(3x+4t−6)2+2{y}_2=\frac{-5}{(3 x+4 t-6)^2+2}. The values of y1,y2{y}_1, {y}_2 and x{x} are in meters and t{t} is in seconds. Which of the following statement is correct?
View answer and explanation
Correct option: C
At x=1m,y1x=1 m, y_1 and y2y_2 always cancel
Option C (At x=1m,y1x=1 m, y_1 and y2y_2 always cancel) is correct because when x=1, the equations for y1 and y2 become equal in magnitude but opposite in sign, causing them to cancel each other.
444 Medium
444 of 524
Application +4 | -1
If the speed of longitudinal waves is equal to 10 times the speed of the transverse waves in a stretched wire of material which has modulus of elasticity EE, then the stress in the wire is
View answer and explanation
Correct option: D
E100\frac{E}{100}
Option D (E100\frac{E}{100}) is correct because the stress in the wire is related to the modulus of elasticity and the ratio of longitudinal and transverse wave speeds.
445 Medium
445 of 524
Application +4 | -1
A string of length 0.4 m0.4 \mathrm{~m} and mass 10−2 kg10^{-2} \mathrm{~kg} is clamped at its ends. The tension in the string is 1.6 N1.6 \mathrm{~N}. When a pulse travels along the string, the shape of the string is found to be the same at times tt and t+Δtt+\Delta t. The value of Δt\Delta t is -
View answer and explanation
Correct option: B
0.1sec0.1 \mathrm{sec}
Option B (0.1sec0.1 \mathrm{sec}) is correct because it calculates the time interval for the pulse to travel the length of the string and return, using the wave speed and string length.
446 Medium
446 of 524
Application +4 | -1
When a train is at a distance of 2 km2 \mathrm{~km}, its engine sounds a whistle. A man near the railway track hears the whistle directly and by placing his ear against the track of the train. If the two sounds are heard att an interval of 5.2 s5.2 \mathrm{~s}, the speed of the sound in iron (material of the rail track) is

(Given that velocity of sound in air is 330 ms−1330 \mathrm{~ms}^{-1})
View answer and explanation
Correct option: A
2,325.6 ms−12,325.6 \mathrm{~ms}^{-1}
Option A (2,325.6 ms−12,325.6 \mathrm{~ms}^{-1}) is correct because it is the speed of sound in iron calculated using the time difference between hearing the sound through air and the railway track.
447 Medium
447 of 524
Application +4 | -1
The displacement yy of a particle in a medium can be expressed as y=10−6  sin⁡(100t+20x+π4)my = {10^{ - 6}}\,\,\sin \left( {100t + 20x + \frac{\pi }{4}} \right)m, where tt is in second and xx in metre. The speed of the wave is
View answer and explanation
Correct option: B
5  ms−15\,\,\mathrm{m}{\mathrm{s}^{ - 1}}
Option B (5  ms−15 \,\,\mathrm{m}{\mathrm{s}^{ - 1}}) is correct because the wave speed is calculated by dividing the angular frequency by the wave number.
448 Medium
448 of 524
Understanding +4 | -1
With propagation of longitudinal waves through a medium, the quantity transmitted is
View answer and explanation
Correct option: B
Energy
Option B (Energy) is correct because longitudinal waves transmit energy through a medium without transferring matter.
449 Medium
449 of 524
Application +4 | -1
A train moves towards a stationary observer with speed 34  ms−134\,\,m{s^{ - 1}}. The train sounds a whistle and its frequency registered by the observer is v1{v_1}. If the train’s speed is reduced to 17  ms−117\,\,m{s^{ - 1}}, the frequency registered is v2{v_2}. If the speed of sound is 340  ms−1340\,\,m{s^{ - 1}}, then the ratio v1/v2{v_1}/{v_2} is
View answer and explanation
Correct option: D
19/1819/18
Option D (19/1819/18) is correct because it is the ratio of the frequencies calculated using the Doppler effect formula for a moving source and a stationary observer.
450 Medium
450 of 524
Application +4 | -1
Four wires of identical length, diameters and of the same material are stretched on a sonometre wire. If the ratio of their tensions is 1:4:9:161\mathrm{ }:\mathrm{ }4\mathrm{ }:\mathrm{ }9\mathrm{ }:\mathrm{ }16 then the ratio of their fundamental frequencies are
View answer and explanation
Correct option: D
1:2:3:41\mathrm{ }:\mathrm{ }2\mathrm{ }:\mathrm{ }3\mathrm{ }:\mathrm{ }4
Option D (1:2:3:41\mathrm{ }:\mathrm{ }2\mathrm{ }:\mathrm{ }3\mathrm{ }:\mathrm{ }4) is correct because the fundamental frequency of a sonometer wire is directly proportional to the square root of the tension.
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