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JEE • PHYSICS • WAVES

Waves practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 211-240 of 543 questions

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211 Medium
211 of 543
Remembering +4 | -1
The waves in which the particles of the medium vibrate in a direction perpendicular to the direction of wave motion is known as
View answer and explanation
Correct option: A
Transverse wave
Option A (Transverse wave) is correct because in transverse waves, the particle's motion is perpendicular to the wave's direction of travel.
212 Medium
212 of 543
Application +4 | -1
If the pressure amplitude in a sound wave is tripled, then the intensity of sound is increased by a factor of
View answer and explanation
Correct option: A
99
Option A (99) is correct because intensity is proportional to the square of the pressure amplitude.
213 Medium
213 of 543
Analyzing +4 | -1
Statement-I: The intensity of sound increases with increase in the density of the medium.
Statement-II: The sound heard is more intense in carbon dioxide in comparison to air.
View answer and explanation
Correct option: A
Statement-I is correct
Option A is correct because the intensity of sound is directly proportional to the density of the medium.
214 Medium
214 of 543
Application +4 | -1
Fundamental frequency of an open pipe of length 0.5  m0.5\,\,m is equal to the frequency of the first overtone of a closed pipe of length ll. The value of lc{l_c} is (m)\left( m \right)
View answer and explanation
Correct option: B
0.75
Option B (0.75) is correct because the length of the closed pipe is calculated by equating the fundamental frequency of the open pipe to the first overtone of the closed pipe.
215 Medium
215 of 543
Understanding +4 | -1
A uniform heavy string of mass M hangs vertically from a rigid ceiling. A transverse wave is sent from its free end towards fixed end. As the wave moves upward
View answer and explanation
Correct option: B
Its speed and wavelength increases
Option B (Its speed and wavelength increases) is correct because as the wave moves upward, the tension increases, leading to an increase in speed and wavelength.
216 Medium
216 of 543
Understanding +4 | -1
The periodic waves of amplitudes A1A_1 and A2A_2 pass through a region. If A1>A2A_1 > A_2, the difference in the maximum and minimum resultant amplitudes possible is
View answer and explanation
Correct option: B
2A22 {A}_2
Option B (2A22 {A}_2) is correct because the difference between the maximum and minimum resultant amplitudes is twice the smaller amplitude.
217 Medium
217 of 543
Understanding +4 | -1
In stationary waves all particles between two nodes pass through the mean position
View answer and explanation
Correct option: D
at the same time with different velocities
Option D (at the same time with different velocities) is correct because in a stationary wave, all particles between two nodes reach their mean position simultaneously, but their velocities depend on their distance from the nodes.
218 Medium
218 of 543
Analyzing +4 | -1
Assertion(A): The fundamental frequency of an open organ pipe increases as the temperature is increased.

Reason(R): As the temperature increases, the velocity of sound increases more rapidly than length of the pipe.
View answer and explanation
Correct option: A
Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
Option A is correct. The fundamental frequency of an open organ pipe increases with temperature because the velocity of sound increases more rapidly than the length of the pipe.
219 Medium
219 of 543
Application +4 | -1
An open pipe and a closed pipe having same length. The ratio of pth{p^{th}} overtones of two pipes is
View answer and explanation
Correct option: C
2(p+1)2p+1\frac{{2(p + 1)}}{{2p + 1}}
Option C (2(p+1)2p+1\frac{{2(p + 1)}}{{2p + 1}}) is correct because it represents the ratio of the frequencies of the p-th overtones in an open and a closed pipe of the same length.
220 Medium
220 of 543
Analyzing +4 | -1
The three lowest resonant frequencies of a system are 50 Hz,150 Hz50 \mathrm{~Hz}, 150 \mathrm{~Hz} and 250 Hz250 \mathrm{~Hz}. The system could be:
View answer and explanation
Correct option: B
A tube of air open at one end
The system is a tube of air open at one end (Option B) because the resonant frequencies are odd multiples of the fundamental frequency.
221 Medium
221 of 543
Application +4 | -1
The temperature at which the velocity of sound in air will be 1.5 times its velocity at 0∘C0^\circ C is
View answer and explanation
Correct option: C
341.2∘C341.2^\circ C
Option C (341.2∘C341.2^\circ C) is correct because the velocity of sound is proportional to the square root of the absolute temperature.
222 Medium
222 of 543
Understanding +4 | -1
Velocity of sound in air
I. increases with temperature

II. Decreases with temperature

III. Increase with pressure

IV. Is independent of pressure

V. Is independent of temperature

Choose the correct answer
View answer and explanation
Correct option: D
Only I  and  IVI\,\,and\,\,IV are true
Option D (Only I;and;IVI\\;and\\;IV are true) is correct because the velocity of sound in air increases with temperature and is independent of pressure.
223 Medium
223 of 543
Application +4 | -1
A tube of length 1.05 m1.05 \mathrm{~m} is closed at one end. If the velocity of sound in air is 336 ms−1336 \mathrm{~ms}^{-1}, then the fundamental and the next higher overtone (in Hz\mathrm{Hz} ) are respectively
View answer and explanation
Correct option: B
80,24080,240
Option B (80,24080,240) is correct because the fundamental frequency is calculated as v/4l and the next higher overtone is three times the fundamental frequency for a tube closed at one end.
224 Medium
224 of 543
Understanding +4 | -1
The minimum intensity of sound is zero at a point due to two sources of nearly equal frequencies, when
View answer and explanation
Correct option: C
At the point of observation, the amplitudes of two S.H.M. produced by two sources are equal and both the S.H.M. are along the same straight line
Option C (At the point of observation, the amplitudes of two S.H.M. produced by two sources are equal and both the S.H.M. are along the same straight line) is correct because minimum intensity is zero when amplitudes are equal and the waves are in opposite phase.
225 Medium
225 of 543
Application +4 | -1
If the maximum speed of a particle carrying a travelling wave is v0v_0, then find the speed of a particle when the displacement is half that of the maximum value
View answer and explanation
Correct option: C
3v02\frac{\sqrt{3} v_0}{2}
Option C (3v02\frac{\sqrt{3} v_0}{2}) is correct because it is derived from the wave equation and the given condition where displacement is half the maximum value.
226 Medium
226 of 543
Remembering +4 | -1
The speed of sound in a gas of density ρ\rho at a pressure PP is proportional to
View answer and explanation
Correct option: D
Pρ\sqrt {\frac{P}{\rho }}
Option D (Pρ\sqrt {\frac{P}{\rho }}) is correct because the speed of sound in a gas is proportional to the square root of the pressure divided by the density.
227 Medium
227 of 543
Application +4 | -1
A train moves towards a stationary observer with speed 34  ms−134\,\,\mathrm{m}{\mathrm{s}^{ - 1}}. The train sounds a whistle and its frequency registered by the observer is f1{f_1}. If the train’s speed is reduced to 17 ms−117\,\mathrm{m}{\mathrm{s}^{ - 1}}, the frequency registered isf2{f_2}. If the peed of sound is 340  ms−1340\,\,\mathrm{m}{\mathrm{s}^{ - 1}}, then the ratio f1/f2{f_1}/{f_2} is
View answer and explanation
Correct option: D
1918\frac{{19}}{{18}}
The correct answer is D (19/18). The ratio of frequencies is calculated using the Doppler effect formula for a moving source approaching a stationary observer, considering the two different speeds of the train.
228 Medium
228 of 543
Application +4 | -1
A boy is walking away from a wall towards an observer at a speed of 1   metre/sec⁡1\,\,\,metre/\sec and blows a whistle whose frequency is 680  Hz680\,\,Hz. The number of beats heard by the observer per second is (Velocity of sound in air =340  metres/sec⁡= 340\,\,metres/\sec
View answer and explanation
Correct option: D
4
Option D (4) is correct because the number of beats heard by the observer is the difference between the frequencies heard directly from the source and from its reflection.
229 Medium
229 of 543
Understanding +4 | -1
A stretched string instead of being plucked in the middle is plucked at a point (1/4)th of its length from either of its ends. The frequency of vibration would be
View answer and explanation
Correct option: B
Twice when plucked in the middle
Option B (Twice when plucked in the middle) is correct because plucking at 1/4th length creates a higher frequency, specifically twice the frequency when plucked in the middle.
230 Medium
230 of 543
Application +4 | -1
Two forks exited together produced 3 beats per second. What is the time interval between the maximum intensity and the next minimum?
View answer and explanation
Correct option: A
16sec⁡\frac{1}{6}\sec
Option A (16sec⁡\frac{1}{6}\sec) is correct because the time interval between maximum intensity and the next minimum is half the time period of the beat frequency.
231 Medium
231 of 543
Application +4 | -1
A closed organ pipe and an open pipe of same length produce 22 beats s−1{\mathrm{s}^{ - 1}} when they are set into vibrations together in fundamental mode. The length of open pipe is now halved and that of closed pipe is doubled. The number of beats produced will be
View answer and explanation
Correct option: A
7
Option A (7) is correct because the number of beats produced is calculated by finding the difference in frequencies after changing the lengths of the pipes.
232 Medium
232 of 543
Application +4 | -1
A closed organ pipe has fundamental frequency 100Hz100\mathrm{ }Hz. What frequency will be produced, if its other end is also opened?
View answer and explanation
Correct option: A
200,400,600,800…\begin{array}{llllllllllllllllllll} {200,400,600,800 \ldots } \end{array}
Option A (200,400,600,800...) is correct because opening the other end of a closed organ pipe doubles the fundamental frequency, and all subsequent harmonics are integer multiples of this new fundamental frequency.
233 Medium
233 of 543
Understanding +4 | -1
The speed of sound in air at STP is 300 m/s.300 \mathrm{~m} / \mathrm{s}. If the air pressure becomes double, the temperature remaining the same, the speed of sound would become
View answer and explanation
Correct option: C
300 m/s300 \mathrm{~m} / \mathrm{s}
Option C (300 m/s300 \mathrm{~m} / \mathrm{s}) is correct because the speed of sound in air is independent of pressure at a constant temperature.
234 Medium
234 of 543
Understanding +4 | -1
Velocity of sound in vacuum is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because sound requires a medium to travel and cannot propagate through a vacuum.
235 Medium
235 of 543
Application +4 | -1
The electric field part of an electromagnetic wave in vacuum is

E=3.1 N C−1×cos⁡[(1.8 rad m−1)y+(5.4×108 rad s−1)t]i^\mathrm{E}=3.1 \mathrm{~N~C}^{-1} \times \cos \left[\left(1.8 \mathrm{~rad} \mathrm{~m}^{-1}\right) \mathrm{y}+\left(5.4 \times 10^8 \mathrm{~rad} \mathrm{~s}^{-1}\right) \mathrm{t}\right] \hat{\mathrm{i}}

The wavelength of this part of electromagnetic wave is
View answer and explanation
Correct option: D
3.5 m3.5 \mathrm{~m}
Option D (3.5 m3.5 \mathrm{~m}) is correct because it is the wavelength calculated from the wave number (k) in the given electromagnetic wave equation.
236 Medium
236 of 543
Application +4 | -1
The displacement of a particle is given by
x=3  sin⁡(5πt)+4  cos⁡(5πt)x = 3\,\,\sin \left( {5\pi t} \right) + 4\,\,\cos \left( {5\pi t} \right)
The amplitude of the particle is
View answer and explanation
Correct option: C
5
Option C (5) is correct because the amplitude of the resultant wave is calculated using the Pythagorean theorem since the two SHMs are perpendicular.
237 Medium
237 of 543
Understanding +4 | -1
Assertion(A): To hear different beats, difference of the frequencies of two sources should be less than 10 .

Reason(R): More the number of beats more is the confusion.
View answer and explanation
Correct option: B
Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
Option B (Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion) is correct because both statements are true, but the reason doesn't explain the assertion.
238 Medium
238 of 543
Understanding +4 | -1
Statement-I: The velocity of sound increases with increase of temperature.
Statement-II: Sound wave travel through longer distances during night than during day.
View answer and explanation
Correct option: A
Statement-I is correct
Option A (Statement-I is correct) is correct because the velocity of sound increases with temperature due to increased molecular kinetic energy.
239 Medium
239 of 543
Application +4 | -1
Find out the ratio of speed of sound in H2\mathrm{H}_2 & He\mathrm{He} at same temperature.
View answer and explanation
Correct option: B
4225\sqrt{\frac{42}{25}}
Option B (4225\sqrt{{\frac{{42}}{{25}}}}) is correct because it correctly applies the formula for the speed of sound in a gas, accounting for the ratio of specific heats and molar masses.
240 Easy
240 of 543
Analyzing +4 | -1
A closed organ pipe and an open organ pipe of the same length produce four beats, when sounded together. If the length of the closed organ pipe is increased then the number of beats will
View answer and explanation
Correct option: B
Increase
Option B (Increase) is correct because increasing the length of the closed pipe decreases its frequency, thus increasing the beat frequency with the open pipe.
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