Wave optics practice · Mixed difficulty

An unpolarised beam of intensity $2{a^2}$ passes through a thin Polaroid. Assuming zero absorption in the Polaroid, the intensity of emergent plane polarized light is

In the ideal double-slit experiment, when a glass-plate (refractive index 1.5) of thickness $t$ is introduced in the path of one of the interfering beams (wave-length $\lambda$ ), the intensity at the position where the central maximum occurred previously remains unchanged. The minimum thickness of the glass-plate is -

In Young's double slit experiment $\frac{\mathrm{d}}{\mathrm{D}}=10^{-4}$ ( $\mathrm{d}=$ distance between slits, $\mathrm{D}=$ distance of screen from the slits). At a point $\mathrm{P}$ on the screen the resulting intensity is equal to the intensity due to individual slit $\mathrm{I}_0$. Then the minimum distance of point $\mathrm{P}$ from the central maximum is $(\lambda=6000 \mathop {\text{A}}\limits^ \circ)$ :-

Which one of the following phenomena is not explained by Huygen’s construction of wavefront

In young's experiment a plate of thickness $\mathrm{t}$ having refractive index $\mu$ is placed infront of one slit. Find the minimum thickness of plate which will make the intensity at centre of the screen zero.

When unpolarised light is incident on a plane glass plate at Brewster's angle, then which of the following statements is correct?

A beam of natural light falls on a system of 5 nicol prisms, whose transmission axis are turned, each through an angle $\alpha=30^{\circ},$ with respect to the previous prism. The fraction of the intensity that passed through the system is

A polarizer is used to

In YDSE of equal width slits, if intensity at the centre of screen is $I_0$, then intensity at a distance of $\beta / 4$ from the central maxima is ($\beta$ is the fringe width):

According to Newton’s corpuscular theory, the speed of light is

To demonstrate the phenomenon of interference, we require two sources which emit radiation

A single slit of width a is illuminated by violet light of wavelength $400\;nm$ and the width of the diffraction pattern is measured as $y$. When half of the slit width is covered and illuminated by yellow light of wavelength $600\;nm$, the width of the diffraction pattern is

Evidence for the wave nature of light cannot be obtained from

The wavelength of the light used in Young’s double slit experiment is $\lambda$. The intensity at a point on the screen is $I$, where the path difference is $\frac{\lambda }{6}$. If ${{I_0}}$ denotes the maximum intensity, then the ratio of ${I\;and\;{I_0}}$ is

In Young’s double slit experiment the wavelength of light was changed from $7000\;\mathop {\mathrm{A}\;to\;}\limits^ \circ \;3500\;\mathop \mathrm{A}\limits^ \circ$. While doubling the separation between the slits which of the following is not true for this experiment

The two coherent sources of intensity that ratio $2: 8$ produce an interference pattern. The values of maximum and minimum intensities will be respectively. Where $I_1$ is the intensity of first source

A slit of width ‘a’ is illuminated by white light. For red light $\left( {\lambda = 6500\,{A^ \circ }} \right)$, the first minima is obtained at $\left( {\lambda = 6500\,{A^ \circ }} \right)$, then the value of ‘a’ will be

For Young's double slit experiment, two statements are given below:

Statement I : If screen is moved away from the plane of slits, angular separation of the fringes remains constant.

Statement II : If the monochromatic source is replaced by another monochromatic source of larger wavelength, the angular separation of fringes decreases.

In the light of the above statements, choose the correct answer from the options given below:

In a single slit diffraction pattern with slit width $a$ and wavelength of light $\lambda$, find the angular position of first minima if screen distance is $D(D \gg a)$

An incident plane wavefront makes angle $53^{\circ}$ with surface of medium in air. The refracted wavefront makes angle $37^{\circ}$ with the surface. Refractive index of medium is :-

Astronomical wavelength increase due to doppler effect known as

Assertion: In interference, only redistribution of light energy occurs in the form of maximum and minimum.

Reason: Average energy in the interference pattern is smae as it would be if there were no interference.

What is the path difference of destructive interference

In young's experiment light of wavelength $4800 ~\mathop {\text{A}}\limits^ \circ$ is used. If one slit is covered with glass of refractive index $1.4$ and another slit is covered with a film of same thickness having refractive index $1.7,$ the centre fringe shifts to the position of $5^{\text {th}}$ bright fringe then find the thickness of film.

The principle of superposition is basic to the phenomenon of

In the phenomenon of diffraction of light, when blue light is used in the experiment instead of red light, then

In Young’s double slit experiment, the distance between the two slits is made half, then the fringe width will become

Assertion: If the phase difference between the light waves emerging from the slits of the Young's experiment is $\pi$-radian, the central fringe will be dark.

Reason: Phase difference is equal to $(2 \pi / \lambda)$ times the path difference.

In Young’s double slit experiment we get 60 fringes in the field of view of monochromatic light of wavelength ${4000\;\mathop \mathrm{A}\limits^ \circ }$. If we use monochromatic light of wavelength ${6000\;\mathop \mathrm{A}\limits^ \circ }$, then the number of fringes obtained in the same field of view are

In a Young's double slit experiment the angular width of a fringe formed on a distant screen is $1^{\circ}$. The wavelength of the light used is $6280\mathop {\text{A}}\limits^ \circ$. What is the distance between the two coherent sources?