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JEE • PHYSICS • WAVE OPTICS

Wave optics practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-210 of 418 questions

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181 Medium
181 of 418
Understanding +4 | -1
In Young’s double slit interference pattern the fringe width
View answer and explanation
Correct option: C
Can be changed either by changing the wavelength or by changing the separation between two sources
Option C (Can be changed either by changing the wavelength or by changing the separation between two sources) is correct because the fringe width in Young's double-slit experiment depends on both the wavelength of light and the slit separation.
182 Medium
182 of 418
Remembering +4 | -1
The resolving power of a telescope depends on
View answer and explanation
Correct option: D
Diameter of the objective lens
Option D (Diameter of the objective lens) is correct because the resolving power of a telescope is directly proportional to the diameter of its objective lens.
183 Medium
183 of 418
Understanding +4 | -1
Consider the following statements in case of Young’s double slit experiment.
I. A slit S is necessary if we use an ordinary extended source of light.
II. A slit S is not needed if we use an ordinary but well collimated beam of light.
III. A slit S is not needed if we use a spetially coherent source of light.
Which of the above statement are correct?
View answer and explanation
Correct option: D
(i), (ii) and (iii)
Option D is correct because all three statements are correct regarding the necessity of a slit in Young's double-slit experiment depending on the light source.
184 Medium
184 of 418
Remembering +4 | -1
For the sustained interference of light, the necessary condition is that the two sources should
View answer and explanation
Correct option: A
Have constant phase difference
Option A (Hot wire voltmeter) is correct because hot wire voltmeters are designed to measure AC voltages.
185 Medium
185 of 418
Remembering +4 | -1
Refractive index of material is equal to tangent of polarising angle. It is called
View answer and explanation
Correct option: A
Brewster's law
Option A (Brewster's law) is correct because Brewster's law states that the refractive index of a material is equal to the tangent of the polarizing angle.
186 Medium
186 of 418
Understanding +4 | -1
Assertion: The phase difference between any two poitns on a wave front is zero.

Reason: Light from the source reaches every point ofthe wave front at the same time.
View answer and explanation
Correct option: A
Both Assertion and Reason are true and Reason is the correct explanation of Assertion
Option A (Both Assertion and Reason are true and Reason is the correct explanation of Assertion) is correct because a wavefront is defined as a surface of constant phase, reached at the same time by light from the source.
187 Medium
187 of 418
Application +4 | -1
A light wave is incident normally over a slit of width 24×10−5  cm24 \times {10^{ - 5}}\;cm. The angular position of second dark fringe from the central maxima is 30∘30^\circ. What is the wavelength of light
View answer and explanation
Correct option: A
6000A∘6000\mathop \mathrm{A}\limits^ \circ
Option A (6000A∘6000\mathop \mathrm{A}\limits^ \circ) is correct because it is the wavelength calculated using the formula for the angular position of the second dark fringe in single-slit diffraction.
188 Medium
188 of 418
Remembering +4 | -1
The wavefront of a distant source of light is of shape
View answer and explanation
Correct option: D
plane
The correct answer is D (plane) because at a large distance from the source, the wavefront appears as a plane wave.
189 Medium
189 of 418
Understanding +4 | -1
For light diverging from a point source
View answer and explanation
Correct option: A
The wavefront is spherical
Option A (The wavefront is spherical) is correct because light diverging from a point source creates spherical wavefronts.
190 Medium
190 of 418
Understanding +4 | -1
The total angular width of central maxima in diffraction at a single slit is
View answer and explanation
Correct option: B
2λa\frac{2 \lambda}{a}
Option B is correct because the angular width of the central maxima in single-slit diffraction is given by 2λa\frac{2 \lambda}{a}, where λ\lambda is the wavelength and a is the slit width.
191 Medium
191 of 418
Understanding +4 | -1
Suppose you are using a microscope to view two closely spaced cells. For a given lens diameter, which color of light would you use to achieve the best possible resolving power?
View answer and explanation
Correct option: D
Blue
Option D (Blue) is correct because resolving power is inversely proportional to the wavelength of light, and blue light has the shortest wavelength.
192 Easy
192 of 418
Understanding +4 | -1
A thin air film is formed by putting the convex surface of a plane-convex lens over a plane glass plate. With monochromatic light, this film gives an interference pattern due to light reflected from the top (convex) surface and the bottom (glass plate) surface of the film.

Statement I : When light reflects from the air-glass plate interface, the reflected wave suffers a phase change of π\pi.

Statement II : The centre of the interference pattern is dark.
View answer and explanation
Correct option: B
Statement I is true, Statement II is true; Statement II is not the correct explanation for Statement I
Option B (Statement I is true, Statement II is true; Statement II is not the correct explanation for Statement I) is correct because both statements are true, but the dark center is due to a phase change upon reflection and the small air gap at the center.
193 Medium
193 of 418
Application +4 | -1
A slit of width ' aa ' is illuminated by light of wavelength 6000A06000 A^0 For What value of 'a will the :- 
(i) First maximum fall at an angle of diffraction of 30∘30^{\circ} ? 
(ii) First minimum fall at an angle of diffraction 30∘30^{\circ} ?
View answer and explanation
Correct option: A
1.8μm1.8 \mu \mathrm{m} , 1.2μm1.2 \mu \mathrm{m}
Option A (1.8μm1.8 \mu \mathrm{m} , 1.2μm1.2 \mu \mathrm{m}) is correct because it correctly applies the conditions for the first maximum and first minimum in single-slit diffraction.
194 Medium
194 of 418
Understanding +4 | -1
What should be refractive index of a transparent medium to be invisible in vacuum?
View answer and explanation
Correct option: A
1
Option A (1) is correct because the refractive index of vacuum is 1, and for a medium to be invisible, its refractive index must match that of the surrounding medium.
195 Medium
195 of 418
Analyzing +4 | -1
Yellow light is used in single slit diffraction experiment with slit width 0.6  mm\mathrm{0}\mathrm{.6}\;\mathrm{mm}. If yellow light is replaced by X\mathrm{X}-rays, then the pattern will reveal that
View answer and explanation
Correct option: A
No diffraction pattern
Option A (No diffraction pattern) is correct because the wavelength of X-rays is much smaller than the slit width, resulting in negligible diffraction.
196 Medium
196 of 418
Understanding +4 | -1
If a star is moving towards the earth, then the lines are shifted towards
View answer and explanation
Correct option: C
Blue
Option C (Blue) is correct because when a star moves towards the Earth, the light waves are compressed, resulting in a blueshift (shorter wavelength).
197 Medium
197 of 418
Understanding +4 | -1
In Fresnel diffraction, if the distance between the disc and the screen is decreased, the intensity of central bright spot will
View answer and explanation
Correct option: B
Decrease
Option A (Increase) is incorrect. In Fresnel diffraction, decreasing the distance between the disc and the screen increases the number of blocked half-period zones, thus decreasing the intensity of the central bright spot.
198 Medium
198 of 418
Understanding +4 | -1
The resolving power of an astronomical telescope is 0.2  seconds\mathrm{0}.\mathrm{2}\,\,\mathrm{seconds}. If the central half portion of the objective lens is covered, the resolving power will be
View answer and explanation
Correct option: A
0.1  sec⁡0.1\,\,\sec
The correct answer is B (0.2 sec) because the resolving power of a telescope depends on the diameter of the objective lens, not the area. Covering the central portion doesn't change the effective diameter.
199 Medium
199 of 418
Application +4 | -1
A single slit Fraunhoffer diffraction pattern is formed with white light. For what wavelength of light the third secondary maximum in the diffraction pattern coincides with the second secondary maximum in the pattern for red light of wavelength 6500 A∘6500\,\mathop \mathrm{A}\limits^ \circ
View answer and explanation
Correct option: C
4642.8 A∘4642.8\,\mathop \mathrm{A}\limits^ \circ
Option C (4642.8A∘4642.8\mathop \mathrm{A}\limits^ \circ) is correct because the position of the maxima in a single-slit diffraction pattern depends on the wavelength.
200 Medium
200 of 418
Understanding +4 | -1
Two coherent sources of light can be obtained by
View answer and explanation
Correct option: D
None of the above
Option D (None of the above) is correct because coherent sources require a single original source split into two to maintain a constant phase relationship, which cannot be achieved with two different lamps.
201 Medium
201 of 418
Understanding +4 | -1
Statement A: Sharp edge of a fine needle doesn't cast clear shadow.

Statement B: Sharp edge of needle capable to diffract radio wave.
View answer and explanation
Correct option: C
A is correct and B is wrong
Option C (A is correct and B is wrong) is correct because sharp edges of fine needles do not cast clear shadows due to diffraction, but needles are not capable of diffracting radio waves because radio waves have much larger wavelengths.
202 Medium
202 of 418
Application +4 | -1
In Young’s double slit experiment we get 60 fringes in the field of view of monochromatic light of wavelength 4000  A∘{4000\;\mathop \mathrm{A}\limits^ \circ }. If we use monochromatic light of wavelength 6000  A∘{6000\;\mathop \mathrm{A}\limits^ \circ }, then the number of fringes obtained in the same field of view are
View answer and explanation
Correct option: C
40
Option C (40) is correct because the number of fringes is inversely proportional to the wavelength of light used.
203 Medium
203 of 418
Understanding +4 | -1
The way the fringe pattern changes when the screen is moved away from the slits is
View answer and explanation
Correct option: A
Width of fringe increases
Option A (Width of fringe increases) is correct because the fringe width is directly proportional to the distance between the slits and the screen.
204 Medium
204 of 418
Understanding +4 | -1
Through quantum theory of light we can explain a number of phenomena observed with light, it is necessary to retain the wave nature of light to explain the phenomenon of
View answer and explanation
Correct option: B
Diffraction
Option B (Diffraction) is correct because diffraction is a phenomenon that can only be explained by the wave nature of light.
205 Medium
205 of 418
Understanding +4 | -1
As a result of interference of two coherent sources of light, energy is
View answer and explanation
Correct option: B
Redistributed and the distribution does not vary with time
Option B is correct because interference redistributes energy, creating regions of constructive and destructive interference without changing the total energy.
206 Medium
206 of 418
Understanding +4 | -1
In the following four statements are regarding well defined observable interference pattern.

A) Condition for sustained interference : The two waves should be coherent.

B) Condition for good observation : The separation between light sources should be as small as possible.

C) Condition for good contrast: The amplitudes of interfering waves should be equal (or) at least very nearly equal.

D) Condition for good contrast : Slit width must be very narrow considerably less than the fringe width.
View answer and explanation
Correct option: A
All the above are correct
Option A (All the above are correct) is correct because all the listed conditions (coherence, small separation, equal amplitudes, narrow slit width) are necessary for observing a well-defined interference pattern.
207 Medium
207 of 418
Understanding +4 | -1
In a diffraction pattern by a wire, on increasing diameter of wire, fringe width
View answer and explanation
Correct option: A
Decreases
Option C is correct because the dimensional formula for entropy is derived from the formula S=QTS = \frac{Q}{T}, where Q is heat (energy) and T is temperature.
208 Medium
208 of 418
Understanding +4 | -1
From Brewster's law, except for polished metallic surface, the polarising angle
View answer and explanation
Correct option: A
Depends on wave length and is different for different colours
Option A is correct because Brewster's angle, which is the polarizing angle, depends on the refractive index of the material, which in turn depends on the wavelength of light, making it different for different colors.
209 Medium
209 of 418
Application +4 | -1
The maximum number of possible interference maxima for slit separation equal to 2.5 times the wavelength in young's double slit experiment is
View answer and explanation
Correct option: B
Five
Option B (Five) is correct because the maximum number of interference maxima is determined by the condition dsin⁡θ=nλd \sin \theta = n \lambda, and with d=2.5λd = 2.5\lambda, the possible integer values for n are -2, -1, 0, 1, and 2.
210 Medium
210 of 418
Understanding +4 | -1
What should be refractive index of a transparent medium to be invisible in vacuum?
View answer and explanation
Correct option: A
1
Option A (1) is correct because for a medium to be invisible in vacuum, its refractive index must match that of vacuum, which is 1.
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