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JEE • PHYSICS • UNITS & MEASUREMENTS

Units & measurements practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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571 Medium
571 of 616
Application +4 | -1
Given, Force =αdensity+  β3= \frac{\alpha }{{\mathrm{density} + \mathrm{\;}{\mathrm{\beta }^3}}} What are the dimensions of α,β?\mathrm{\alpha },\mathrm{\beta }?
View answer and explanation
Correct option: D
[M2L−2T2],  [ML−3]\left[ {{\mathrm{M}^2}{\mathrm{L}^{ - 2}}{\mathrm{T}_2}} \right],\mathrm{\;}\left[ {\mathrm{M}{\mathrm{L}^{ - 3}}} \right]
Option C ([M2 L-2 T-2], [M1/3 L-1]) is correct because it is derived from equating dimensions of force and density with the given expression.
572 Medium
572 of 616
Analyzing +4 | -1
The physical quantity which does not have the same dimensions as the other three is
View answer and explanation
Correct option: D
acceleration due to gravity
Option D is correct because acceleration due to gravity has dimensions [LT⁻²], while spring constant, surface tension, and surface energy have dimensions [MT⁻²].
573 Medium
573 of 616
Understanding +4 | -1
In a slide calliper, nn divisions of vernier scale coincides with (n−1)(n-1) divisions of main scale. The least count of the instrument is
View answer and explanation
Correct option: A
1nMSD\frac{1}{n} \mathrm{MSD}
Option A (1nMSD\frac{1}{n} \mathrm{MSD}) is correct because the least count of a slide caliper is calculated as the difference between one main scale division and one vernier scale division.
574 Easy
574 of 616
Understanding +4 | -1
Dimensions of strain are
View answer and explanation
Correct option: D
M0L0T0{M^0}{L^0}{T^0}
Option D is correct because strain is defined as the ratio of change in dimension to the original dimension, making it a dimensionless quantity.
575 Medium
575 of 616
Analyzing +4 | -1
The fundamental unit, which has the same power in the dimensional formulae of surface tension and viscosity is
View answer and explanation
Correct option: A
Mass
Option A is correct because both surface tension and viscosity have mass to the power of 1 in their dimensional formulas.
576 Medium
576 of 616
Analyzing +4 | -1
Assertion: The number of significant figures in 0.100 is 1 .

Reason: The zeros at the end of a number are always meaningless.
View answer and explanation
Correct option: D
If both assertion and reason are false.
Option D (If both assertion and reason are false) is correct because 0.100 has three significant figures, and zeros at the end of a number after the decimal point are significant.
577 Medium
577 of 616
Analyzing +4 | -1
Given that the amplitude A of scattered light is :

(i) Directly proportional to the amplitude (Ao)\left(A_o\right) of incident light.

(ii) Directly proportional to the volume (V)(V) of the scattering particle

(iii) Inversely proportional to the distance (r) from the scattered particle

(iv) Depend upon the wavelength (λ)(\lambda) of the scattered light. then:
View answer and explanation
Correct option: B
A∝1λ2A \propto \frac{1}{\lambda^2}
Option B is correct because the amplitude of scattered light is inversely proportional to the square of the wavelength, A∝1λ2A \propto \frac{1}{\lambda^2}.
578 Medium
578 of 616
Understanding +4 | -1
Which of the following is not a unit of energy
View answer and explanation
Correct option: B
kg–m/sec
Option B is correct because kg-m/sec is the unit of momentum, not energy.
579 Medium
579 of 616
Application +4 | -1
Rounding off the value 324.13821 upto four significant digits is
View answer and explanation
Correct option: A
324.1
Option A (324.1) is correct because when rounding to four significant digits, the digit after the fourth significant digit is less than 5, so the fourth digit remains unchanged.
580 Medium
580 of 616
Analyzing +4 | -1
Dimensional formula for h2v2/mc21+hvmc2\frac{h^2 v^2 / m c^2}{1+\frac{h v}{m c^2}} is (where hh is planck's constant, vv is frequency of light, mm is mass and cc is speed of light).
View answer and explanation
Correct option: C
[ML2 T−2]\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right]
Option C ([ML2 T−2]\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right]) is correct because after simplifying the expression using dimensional analysis, the result matches the dimensions of energy.
581 Medium
581 of 616
Application +4 | -1
The physical quantity which has the dimensional formula [M1T−3]\left[ {{\mathrm{M}^1}{\mathrm{T}^{ - 3}}} \right] is
View answer and explanation
Correct option: C
Solar constant
Option C (Solar constant) is correct because its dimensions are energy per unit area per unit time, which matches [M1T-3].
582 Easy
582 of 616
Understanding +4 | -1
Which of the following physical quantities has neither dimensions nor unit?
View answer and explanation
Correct option: C
Coefficient of friction
Option C (Coefficient of friction) is correct because it is a ratio of two forces, making it dimensionless and unitless.
583 Medium
583 of 616
Understanding +4 | -1
Statement-I: Positive zero error is added in measurement.
Statement-II: Defect may occurs during manufacturing of measuring instruments.
View answer and explanation
Correct option: B
Statement-I is wrong while statement-II is correct
Option B (Statement-I is wrong while statement-II is correct) is correct because positive zero error is subtracted, not added, and manufacturing defects can occur.
584 Medium
584 of 616
Application +4 | -1
Resistance of a given wire is obtained by measuring the current flowing in it and the voltage difference applied across it. If the percentage errors in the measurement of the current and the voltage difference are 3% each, then error in the value of resistance of the wire is
View answer and explanation
Correct option: A
6%6\%
Option A (6%6\%) is correct because the percentage error in resistance is the sum of the percentage errors in voltage and current.
585 Medium
585 of 616
Understanding +4 | -1
Which of the following measurement is most precise?
View answer and explanation
Correct option: D
3.00 mm
Option D is correct because the measurement with the smallest unit (3.00 mm) provides the highest precision.
586 Medium
586 of 616
Understanding +4 | -1
Assertion: Mass of a body and the velocity, with which it is moving, cannot be multiplied.

Reason: It is because, mass is a scalar and velocity is a vector quantity. In addition to this, the dimensions of mass and velocity are different.
View answer and explanation
Correct option: D
If both assertion and reason are false.
Option D (If both Assertion & Reason are false) is correct because mass and velocity can be multiplied to give momentum, and dimensions can be different for quantities that are multiplied.
587 Medium
587 of 616
Application +4 | -1
A screw gauge with a pitch of 0.5 mm and a circular scale with 50 divisions is used to measure the thickness of a thin sheet of aluminium. Before starting the measurement, it is found that when the two jaws of the screw gauge are brought in contact, the 45th division coincides with the main scale line and that the zero of the main scale is barely visible. What is the thickness of the sheet, if the main scale reading is 0.5 mm and the 25th division coincides with the main scale line?
View answer and explanation
Correct option: A
0.75 mm
Option A (0.75 mm) is correct because it accurately calculates the thickness by considering the main scale reading, circular scale reading, and zero error of the screw gauge.
588 Easy
588 of 616
Analyzing +4 | -1
Which of the following pair of quantities do not have the same dimensions :
View answer and explanation
Correct option: C
Light year, time period
Option D (Train PP exerts greater force on track) is correct because train P experiences a greater effective weight due to the Coriolis effect.
589 Hard
589 of 616
Analyzing +4 | -1
The liquid drop of density ρ,\rho , radius rr and surface tension σ\sigma oscillates with time period T. Which of the following expression for T2{T^2} is correct
View answer and explanation
Correct option: A
ρr3σ\frac{{\rho {r^3}}}{\sigma }
Option A (ρr3σ\frac{{\rho {r^3}}}{\sigma }) is correct because dimensional analysis confirms this relationship between the variables.
590 Medium
590 of 616
Analyzing +4 | -1
Assertion: The dimensional formula for product of resistance and conductance is same as for dielectric constant.

Reason: Both have dimensions of time constant.
View answer and explanation
Correct option: C
If assertion is true, but reason is false.
Option C (If assertion is true, but reason is false) is correct because both resistance times conductance and the dielectric constant are dimensionless, but they don't represent time constants.
591 Medium
591 of 616
Application +4 | -1
Age of the universe is about 1010yr10^{10} \mathrm{yr}, whereas the mankind has existed for 106yr10^6 \mathrm{yr}. For how many seconds would the man have existed, if age of universe were 1 day?
View answer and explanation
Correct option: C
8.6 s8.6 \mathrm{~s}
Option C (8.6 s8.6 \mathrm{~s}) is correct because the apparent age of mankind is calculated by scaling the age of the universe to one day.
592 Medium
592 of 616
Understanding +4 | -1
In the expression for Boyle's law, the product 'PVP V' has dimensions of
View answer and explanation
Correct option: C
Energy
Option C is correct because the product of pressure and volume (PV) has the dimensions of energy.
593 Medium
593 of 616
Understanding +4 | -1
Dimension of R is
View answer and explanation
Correct option: B
ML2T−3A−2M{L^2}{T^{ - 3}}{A^{ - 2}}
Option B (ML2T−3A−2M{L^2}{T^{ - 3}}{A^{ - 2}}) is correct because resistance is voltage divided by current, and substituting the dimensions of voltage and current gives the result.
594 Medium
594 of 616
Application +4 | -1
The volume of a cube in m3{m}^3 is equal to the surface area of the cube in m2{m}^2. The volume of the cube is
View answer and explanation
Correct option: B
216 m3216{~m}^3
Option B (216 m3216{~m}^3) is correct because the volume of the cube equals its surface area only when the side length is 6, resulting in a volume of 216.
595 Medium
595 of 616
Understanding +4 | -1
Assertion: One radian is the angle subtended at the centre of circle by an arc equal in length to the radius fo the circle.
Reason: Radian is the unit of distance
View answer and explanation
Correct option: C
If assertion is true reason is false
The correct answer is If assertion is true reason is false because radian is a unit of angle, not distance.
596 Easy
596 of 616
Application +4 | -1
If ε0\varepsilon_0 is the permittivity of free space and EE is the electric field, then ε0E2\varepsilon_0 E^2 has the dimensions:
View answer and explanation
Correct option: B
[ML−1T−2]\left[{M} {L}^{-1}{T}^{-2}\right]
Option B ([M][L]-1[T]-2) is correct because it represents the dimensions of energy density, which is equivalent to \ε0E2\varepsilon_0 E^2.
597 Medium
597 of 616
Analyzing +4 | -1
Assertion: Force can be subtracted from momentum.
Reason : Physical quantities with different nature and dimensions can be subtracted.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D (If both Assertion & Reason are false) is correct because force and momentum have different dimensions and cannot be subtracted, and physical quantities with different dimensions cannot be subtracted.
598 Medium
598 of 616
Analyzing +4 | -1
The position of a particle at time t is given by the relation x(t)=(v0α)(1−c−αt)x\left( t \right) = \left( {\frac{{{v_0}}}{\alpha }} \right)\left( {1 - {c^{ - \alpha t}}} \right), where v0{v_0} is a constant and α>0\alpha > 0. The diemensions of v0{v_0} and α\alpha are respectively
View answer and explanation
Correct option: A
M0L1T−1 and T−1{M^0}{L^1}{T^{ - 1}}\,{\text{and}}\,{T^{ - 1}}
Option A (M0L1T−1 and T−1{M^0}{L^1}{T^{ - 1}}\,{\text{and}}\,{T^{ - 1}}) is correct because it correctly identifies the dimensions of velocity and inverse time respectively.
599 Medium
599 of 616
Understanding +4 | -1
The expression [ML−1T−1]\left[ {\mathrm{M}{\mathrm{L}^{ - 1}}{\mathrm{T}^{ - 1}}} \right] represents
View answer and explanation
Correct option: D
Coefficient of viscosity
Option D (Coefficient of viscosity) is correct because the dimensional formula for the coefficient of viscosity is [ML⁻¹T⁻¹].
600 Easy
600 of 616
Understanding +4 | -1
Statement-I: The equation y=x+ty=x+t cannot be true where x,yx, y are the distances and tt is time
Statement-II: quantities with different dimensions can not be added
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option A (Statement-I is true and statement-II is true) is correct because the equation y=x+ty=x+t is dimensionally incorrect, and quantities with different dimensions cannot be added.
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