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JEE • PHYSICS • UNITS & MEASUREMENTS

Units & measurements practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 541-570 of 616 questions

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541 Medium
541 of 616
Analyzing +4 | -1
Statement I: The dimensional method cannot be used to obtain the dependence of the work done by a force FF on the angle θ\theta between force FF and displacement xx.

Statement II: Angle can be measured in radians but it has no dimensions.
View answer and explanation
Correct option: A
Statement I is true, Statement II is true; Statement II is the correct explanation for Statement I
Option A is correct because Statement I is true, Statement II is true, and Statement II is the correct explanation for Statement I. Dimensional analysis cannot determine the dependence on dimensionless quantities like angles.
542 Medium
542 of 616
Remembering +4 | -1
The dimension of torque is
View answer and explanation
Correct option: A
[ML2T−2]\left[M L^2 T^{-2}\right]
Option A ([M L² T⁻²]) is correct because torque is force times distance, and the dimensions of force are [M L T⁻²] and distance is [L], so torque is [M L² T⁻²].
543 Medium
543 of 616
Understanding +4 | -1
Which of the following pairs has the dimensions of length?
View answer and explanation
Correct option: A
Radius of gyration and light year
Option A (Radius of gyration and light year) is correct because both radius of gyration and light year have the dimension of length.
544 Medium
544 of 616
Understanding +4 | -1
Dimensions of coefficient of viscosity are
View answer and explanation
Correct option: C
ML−1T−1M{L^{ - 1}}{T^{ - 1}}
The correct answer is C (ML−1T−1M{L^{ - 1}}{T^{ - 1}}) because the coefficient of viscosity is defined by the formula F = -ηA(dv/dx), and solving for η gives the stated dimensions.
545 Medium
545 of 616
Understanding +4 | -1
The dimensions [ML2T−2A−1]\left[\mathrm{ML}^2 \mathrm{T}^{-2} \mathrm{A}^{-1}\right] belong to the:
View answer and explanation
Correct option: D
Magnetic flux
The correct answer is Magnetic flux because its dimensions are equivalent to inductance multiplied by current, which matches the given dimensions.
546 Medium
546 of 616
Application +4 | -1
The ratio of S.I unit of universal gravitational constant to C.G.S unit is
View answer and explanation
Correct option: A
103{10^3}
Option A (103{10^3}) is correct because the ratio of the SI unit to the CGS unit of the universal gravitational constant is calculated using dimensional analysis.
547 Medium
547 of 616
Analyzing +4 | -1
Farad is not equivalent to
View answer and explanation
Correct option: B
qv2q{v^2}
Option B (qv2q{v^2}) is correct because Farad is the unit of capacitance, which is equivalent to qV\frac{q}{V}, q2J\frac{{{q^2}}}{J}, and JV2\frac{J}{{{V^2}}}, but not qv2q{v^2}.
548 Medium
548 of 616
Application +4 | -1
The potential energy of a particle that varies with distance x{x} is V(x)=−αx+βsin⁡xγ{V}(x)=-\alpha x+\beta \sin \frac{x}{\gamma}. A dimensionless combination of constants α,β,γ\alpha, \beta, \gamma is
View answer and explanation
Correct option: D
αγβ\frac{\alpha \gamma}{\beta}
The correct answer is αγβ\frac{\alpha \gamma}{\beta} because the dimensions of each term in the potential energy equation must be the same, allowing us to find a dimensionless combination.
549 Easy
549 of 616
Analyzing +4 | -1
Statement-I: If error in measurement of mass is 2%2 \% and that in measurement of velocity is 5%5 \% than error in measurement of kinetic energy is 6%6 \%.
Statement-II: Error in kinetic energy is ΔKK=(Δmm+2Δvv)\frac{\Delta K}{K}=\left(\frac{\Delta m}{m}+2 \frac{\Delta v}{v}\right)
View answer and explanation
Correct option: C
Statement-I is false and statement-II is true
Option C is correct because Statement-I is false and Statement-II is true. The error in kinetic energy calculation is incorrect, but the formula for error propagation is correct.
550 Easy
550 of 616
Understanding +4 | -1
Statement-I: Plane angle is dimensionless quantity.
Statement-II : All unitless quantities are dimensionless
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option B is correct because plane angle is defined as the ratio of arc length to radius (both lengths), making it unitless and dimensionless, and all unitless quantities are dimensionless.
551 Medium
551 of 616
Remembering +4 | -1
Dimensional formula of heat energy is
View answer and explanation
Correct option: A
ML2T−2M{L^2}{T^{ - 2}}
Option A (ML2T−2M{L^2}{T^{ - 2}}) is correct because heat energy, like all forms of energy, has the dimensions of mass times length squared divided by time squared.
552 Medium
552 of 616
Understanding +4 | -1
A physicist performs an experiment and takes 200 readings. He repeats the same experiment and now takes 800 readings. By doing so the probable error
View answer and explanation
Correct option: D
Is reduced by a factor of 1/4
Option D (Is reduced by a factor of 1/4) is correct because the error is inversely proportional to the square root of the number of readings. Since the number of readings is multiplied by 4, the error is divided by the square root of 4, which is 2. The variance is reduced by a factor of 4.
553 Medium
553 of 616
Understanding +4 | -1
State the number of significant figures in the
following:
(i) 2.000 m (ii) 5100 kg (iii) 0.050 cm.
View answer and explanation
Correct option: A
(i) - 4; (ii) - 4; (iii) - 2
Option A is correct because it accurately counts the significant figures in each given measurement based on the rules of significant figures.
554 Medium
554 of 616
Remembering +4 | -1
The dimensions of Wien’s constant are
View answer and explanation
Correct option: B
[M0LT0K]\left[ {{M^0}L{T^0}K} \right]
Option B ([M0LT0K{M^0}L{T^0}K]) is correct because Wien's constant has dimensions of length times temperature.
555 Medium
555 of 616
Application +4 | -1
To determine the Young’s modulus of a wire, the formula is Y=FA×LΔLY = \frac{F}{A} \times \frac{L}{{\Delta L}}; where L= length, A= area of cross-section of the wire, ΔL{\Delta L}= change in length of the wire when stretched with a force F. The conversion factor to change it from CGS to MKS system is
View answer and explanation
Correct option: C
0.1
Option C (0.1) is correct because the conversion factor from CGS to MKS for Young's modulus (dyne/cm²) to N/m² is 0.1.
556 Medium
556 of 616
Analyzing +4 | -1
The physical quantity that does not have the dimensional formula [ML−1 T−2]\left[\mathrm{ML}^{-1} \mathrm{~T}^{-2}\right] is
View answer and explanation
Correct option: A
force
Option A is correct because force has the dimensional formula [MLT⁻²], while pressure, stress, and modulus of elasticity have [ML⁻¹T⁻²].
557 Medium
557 of 616
Understanding +4 | -1
The unit of Young's modulus is

[Y=StressStrain=force/areaΔℓ/L]\left[\mathrm{Y}=\frac{\text {Stress}}{\text {Strain}}=\frac{\text {force} / \text {area}}{\Delta \ell / \mathrm{L}}\right]
View answer and explanation
Correct option: C
Newton/metre2{ }^2
Option C (Newton/metre2{ }^2) is correct because Young's modulus is defined as stress/strain, where stress has units of force/area (N/m²) and strain is dimensionless.
558 Medium
558 of 616
Understanding +4 | -1
Young’s modulus of a material has the same units as
View answer and explanation
Correct option: A
Pressure
Option A (Pressure) is correct because Young's modulus is defined as stress/strain, and stress has the same units as pressure.
559 Easy
559 of 616
Understanding +4 | -1
A physical quantity is measured and its value is found to be nu where where n= numerical value and u= unit. Then which of the following relations is true
View answer and explanation
Correct option: D
n∝1un \propto \frac{1}{u}
Option D (n∝1un \propto \frac{1}{u}) is correct because the physical quantity is constant, implying an inverse relationship between numerical value and unit.
560 Medium
560 of 616
Remembering +4 | -1
Unit of magnetic flux is:
View answer and explanation
Correct option: C
Weber
Option C (Weber) is correct because the Weber is the SI unit of magnetic flux.
561 Hard
561 of 616
Application +4 | -1
A wire has mass (0.3 ± 0.003) gm,(0.3\, \pm \,0.003)\,gm, radius (0.5± 0.005) cm (0.5 \pm \,0.005)\,cm\, and length (6± 0.06) cm (6 \pm \,0.06)\,cm\,. The maximum percentage error in the measurement of its density is:-
View answer and explanation
Correct option: D
0.04
Option D (4%) is correct because the maximum percentage error in density is the sum of the percentage errors in mass, length, and twice the percentage error in radius.
562 Medium
562 of 616
Understanding +4 | -1
The dimensional formula of intensity of magnetisation is
View answer and explanation
Correct option: D
[L−1 A]\left[{L}^{-1} {~A}\right]
Option D ([L−1 A{L}^{-1} {~A}]) is correct because the intensity of magnetization is defined as the magnetic moment per unit volume, which has the dimensions of current per unit length.
563 Medium
563 of 616
Application +4 | -1
If the acceleration due to gravity is 10  ms−2\;\mathrm{m}{\mathrm{s}^{ - 2}} and the units of length and time are changed in kilometer and hour respectively, the numerical value of acceleration is
View answer and explanation
Correct option: D
129600
Option D (129600) is correct because the acceleration is transformed using the conversion factors for length and time to the new system of units.
564 Medium
564 of 616
Analyzing +4 | -1
The velocity of a particle as a function of time is given as v(t)=at2+bt+ct2+dv(t)=a t^2+b t+\frac{c}{t^2+d}, where a,b,ca, b, c and dd are constants, The dimensions of [abcd]\left[\frac{a b}{c d}\right] is
View answer and explanation
Correct option: B
[LT−8]\left[L T^{-8}\right]
Option A is correct because by equating dimensions of each term in the given equation, we can find the dimensions of a, b, c, and d, and then calculate the dimensions of ab/cd.
565 Medium
565 of 616
Understanding +4 | -1
The SI unit of universal gas constant (R) is
View answer and explanation
Correct option: C
Joule  K−1mol−1Joule\;{K^{ - 1}}mo{l^{ - 1}}
Option C (Joule;K−1mol−1Joule \\;{K^{ - 1}}mo{l^{ - 1}}) is correct because the universal gas constant (R) is expressed in terms of energy per mole per Kelvin.
566 Medium
566 of 616
Analyzing +4 | -1
Assertion A: If in five complete rotations of the circular scale, the distance travelled on main scale of the screw gauge in 5 mm and there are 50 total divisions on circular scale, then least count of screw gauge is 0.002 cm.
Reason R: Least count = Pitch  Total divisions on circular scale =\frac{\text { Pitch }}{\text { Total divisions on circular scale }}
View answer and explanation
Correct option: C
Both A and R are true and R is the correct explanation of A
Option C is correct because both the assertion and reason are true, and the reason correctly explains how the least count of a screw gauge is calculated.
567 Medium
567 of 616
Analyzing +4 | -1
If the speed of light (c), acceleration due to gravity (g) and pressure (p) are taken as the fundamental quantities, then the dimension of gravitational constant is
View answer and explanation
Correct option: B
c0g2p−1{c^0}{g^2}{p^{ - 1}}
Option B (c0g2p−1{c^0}{g^2}{p^{ - 1}}) is correct because it is derived by equating the dimensions of the gravitational constant with the given fundamental quantities.
568 Medium
568 of 616
Analyzing +4 | -1
The dimension of a×ba \times b in the relation E=b−x2at, E = \frac{{b - {x^2}}}{{at}},\, where EE is the energy, xx is the displacement and tt is time are
View answer and explanation
Correct option: B
M−1L2T{M^{ - 1}}{L^2}T
Option B (M−1L2T{M^{ - 1}}{L^2}T) is correct because by equating dimensions, we find the dimension of 'a' and 'b' and then multiply them to get the dimension of a x b.
569 Medium
569 of 616
Remembering +4 | -1
The circular head of screw gauge is divided into 200 division and move 1 mm a head in one revolution. Find the pitch of screw gauge:
View answer and explanation
Correct option: A
1 mm
Option A (1 mm) is correct because the pitch of a screw gauge is the distance it moves forward in one complete revolution, which is given as 1 mm.
570 Easy
570 of 616
Remembering +4 | -1
SI unit of electric intensity is
View answer and explanation
Correct option: D
Newton/ coulomb
Option D (Newton/ coulomb) is correct because electric intensity (electric field) is defined as force per unit charge.
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