JEE PHYSICS MCQ: UNITS & MEASUREMENTS

1 Easy

1 of 1

Application +4 | -1

Using mass

(M)

, length

(L)

, time

(T)

and current

(A)

as fundamental quantities, the dimensions of permeability are

View answer and explanation

Correct option: C

\left[\mathrm{MLT}^{-2} \mathrm{A}^{-2}\right]

Option C ([

\mathrm{MLT}^{-2} \mathrm{A}^{-2}

]) is correct because it represents the correct dimensional formula for permeability using the given fundamental quantities.

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{\varepsilon _0}L\frac{{\Delta V}}{{\Delta t}},\;

{\varepsilon _0}

{\Delta V}

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