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JEE • PHYSICS • THERMODYNAMICS

Thermodynamics practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 121-150 of 363 questions

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121 Medium
121 of 363
Understanding +4 | -1
Which of the following is true with regards to the energy of an isolated system?
View answer and explanation
Correct option: C
E=E= constant
The correct answer is C (E=E= constant) because, for an isolated system, energy cannot enter or leave, so the total energy remains constant.
122 Medium
122 of 363
Understanding +4 | -1
Which of the following parameters does not characterise the thermodynamic state of matter?
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Correct option: C
Work
Option C (Work) is correct because work is a path function, not a state function, and therefore does not characterize the thermodynamic state of matter.
123 Medium
123 of 363
Analyzing +4 | -1
(A): In isobaric process, during an expansion of a gas both volume and temperature of the gas increase.
(R): Heat added to a gas partly gets converted into internal energy and remaining to do external work.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
Option A is correct because in an isobaric process, as heat is added to the gas, both volume and temperature increase, with the added heat partly converting into internal energy and the rest doing external work.
124 Medium
124 of 363
Understanding +4 | -1
Heat is not being exchanged in a body. If its internal energy is increased, then
View answer and explanation
Correct option: A
Its temperature will increase
Option A is correct because an increase in internal energy without heat exchange directly leads to a rise in temperature.
125 Medium
125 of 363
Understanding +4 | -1
(A): During a free expansion of an ideal gas work done is zero.
(R): Work done against vacuum is zero.
View answer and explanation
Correct option: B
Both (A) and (R) are true and (R) is not the correct explanation of (A)
Option B is correct because both the assertion and the reason are true, but the reason is not the correct explanation of the assertion. Free expansion occurs against zero external pressure, and work done against a vacuum is indeed zero, but the reason for zero work in free expansion is not *only* because it's a vacuum.
126 Medium
126 of 363
Understanding +4 | -1
Conversion of water to steam is accompanied by which process?
View answer and explanation
Correct option: B
Isothermal
The correct answer is B because the conversion of water to steam occurs at a constant temperature (the boiling point), making it an isothermal process.
127 Medium
127 of 363
Understanding +4 | -1
A gas is heated at constant pressure. The fraction of heat energy used to increase the internal energy of the gas molecules is
View answer and explanation
Correct option: B
1/γ1 / \gamma
Option B (1/γ1 / \gamma) is correct because the fraction of heat energy used to increase internal energy at constant pressure is 1/γ1/\gamma, where γ=Cp/Cv\gamma = C_p/C_v.
128 Medium
128 of 363
Understanding +4 | -1
Boyle’s law holds for an ideal gas during
View answer and explanation
Correct option: B
Isothermal changes
Option B (Isothermal changes) is correct because Boyle's law states that for a fixed mass of gas at constant temperature, the pressure and volume are inversely proportional.
129 Medium
129 of 363
Understanding +4 | -1
The molar specific heat of a gas as given from the kinetic theory is 52R\frac{5}{2} R. If it is not specified whether it is CpC_p or CVC_V, one could conclude that the molecules of the gas
View answer and explanation
Correct option: D
can be monoatomic or rigid diatomic
Option D (can be monoatomic or rigid diatomic) is correct because both monoatomic and rigid diatomic gases can have a molar specific heat of (5/2)R at constant volume.
130 Medium
130 of 363
Remembering +4 | -1
The ratio of the specific heats CpCV=γ\frac{C_p}{C_V}=\gamma in terms of degrees of freedom (n)(n) is given by
View answer and explanation
Correct option: C
(1+2n)\left(1+\frac{2}{n}\right)
Option C ((1+2n)\left(1+\frac{2}{n}\right)) is correct because the ratio of specific heats is related to the degrees of freedom by this formula.
131 Medium
131 of 363
Application +4 | -1
The change in internal energy of a thermodynamic system which has absorbed 2kcal2 \mathrm{kcal} of heat and done 400 J400 \mathrm{~J} of work is (Take, 1cal=4.2 J1 \mathrm{cal}=4.2 \mathrm{~J} )
View answer and explanation
Correct option: B
8 kJ8 \mathrm{~kJ}
Option B (8 kJ8 \mathrm{~kJ}) is correct because it represents the change in internal energy calculated using the first law of thermodynamics.
132 Medium
132 of 363
Application +4 | -1
An ideal gas has molar heat capacity cvc_v at constant volume. The gas undergoes a process as T=T0(1+αV2)T=T_0\left(1+\alpha V^2\right) where TT and VV are temperature and volume respectively, T0T_0 and α\alpha are positive constants. The molar heat capacity CC of the gas is given as C=CV+Rf(V)C=C_V+R f(V), where f(V)f(V) is a function of volume. The expression for f(V)f(V) is
View answer and explanation
Correct option: B
1+αV22αV2\frac{1+\alpha V^2}{2 \alpha V^2}
Option A (αV21+αV2\frac{{\alpha V^2}}{{1+\alpha V^2}}) is incorrect. The correct answer is B (1+αV22αV2\frac{{1+\alpha V^2}}{{2 \alpha V^2}}) because it is derived from the first law of thermodynamics and the given temperature-volume relationship.
133 Medium
133 of 363
Application +4 | -1
Efficiency of a heat engine is η=0.4\eta=0.4 and the temperature of the source is 227∘C227^{\circ} \mathrm{C}. If the temperature of source and sink increased by 100∘C100^{\circ} \mathrm{C}, then the efficiency of a modified heat engine is
View answer and explanation
Correct option: B
1/31 / 3
Option B (1/31/3) is correct because the efficiency of the modified heat engine is calculated using the new source and sink temperatures after the increase.
134 Medium
134 of 363
Remembering +4 | -1
How much heat (in joules) is required to raise the temperature of 1 g1 \mathrm{~g} of water from 14.5∘C14.5^{\circ} \mathrm{C} to 15.5∘C15.5^{\circ} \mathrm{C} at 1 atmospheric pressure?
View answer and explanation
Correct option: B
4.186 J4.186 \mathrm{~J}
Option B (4.186 J4.186 \mathrm{~J}) is correct because this is the definition of a calorie in terms of joules.
135 Medium
135 of 363
Understanding +4 | -1
In Which Process the PV indicator diagram is a straight line parallel to volume axis
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Correct option: B
Isobaric
Option B (Isobaric) is correct because an isobaric process is defined as a process occurring at constant pressure, resulting in a horizontal line on a PV diagram.
136 Medium
136 of 363
Application +4 | -1
During an adiabatic process, the cube of the pressure is found to be inversely proportional to the fourth power of the volume. Then the ratio of specific heats is
View answer and explanation
Correct option: B
1.33
Option B (1.33) is correct because the ratio of specific heats (γ) is determined by the relationship between pressure and volume in an adiabatic process, which in this case is found to be 4/3 or 1.33.
137 Medium
137 of 363
Understanding +4 | -1
A system undergoes a cyclic process in which it absorbs Q1Q_1 heat and gives out Q2Q_2 heat. The efficiency of the process is η\eta and work done is WW. Select the correct statement.
View answer and explanation
Correct option: B
η=WQ1\eta=\frac{W}{Q_1}
η=WQ1\eta=\frac{W}{Q_1} is the correct statement because efficiency is defined as the ratio of work done to the heat absorbed.
138 Medium
138 of 363
Understanding +4 | -1
The molar heat capacity of a gas at constant volume is CVC_V. If nn moles of the gas undergo ΔT\Delta T change in temperature, its internal energy will change by nCVΔTn C_V \Delta T
View answer and explanation
Correct option: A
Only if the change of temperature occurs at constant volume
The correct answer is D (In any process) because the change in internal energy of an ideal gas depends only on the change in temperature and is given by ΔU=nCVΔT\Delta U = nC_V \Delta T, regardless of the process.
139 Medium
139 of 363
Analyzing +4 | -1
Assertion: The specific heat of a gas in an adiabatic process is zero and in an isothermal process is infinite.
Reason: Specific heat of a gas is directly proportional to change of heat in system and inversely proportional to change in temperature.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion
Option A is correct because both the assertion and the reason are true, and the reason correctly explains why specific heat is zero in an adiabatic process and infinite in an isothermal process.
140 Medium
140 of 363
Application +4 | -1
When the amount of work done is 333cal333cal and change in internal energy is 167cal167cal, then the heat supplied is
View answer and explanation
Correct option: C
500cal500cal
Option C (500cal500cal) is correct because, according to the first law of thermodynamics, the heat supplied is the sum of the change in internal energy and the work done.
141 Medium
141 of 363
Application +4 | -1
A piece of ice (heat capacity=2100JKg−10C−12100JK{g^{ - 1}}^0{C^{ - 1}} and latent heat=3.36×105Jkg−13.36 \times {10^5}\mathrm{Jk}{\mathrm{g}^{ - 1}}) of mass m gram is at −50C- {5^0}C at atmospheric pressure. It is given 420 J of heat so that the ice starts melting. Finally when the ice-water mixture is in equilibrium, it is found that 1 g of ice has melted. Assuming there is no other heat exchange in the process, the value of m is
View answer and explanation
Correct option: A
8
Option A (8) is correct because solving the heat exchange equation, considering the heat required to raise the ice temperature and melt part of it, yields m=8g.
142 Medium
142 of 363
Understanding +4 | -1
An ideal gas goes through two different non cyclic quasistatic processes.

Process 1 →\rightarrow In this process change in internal energy is zero.

Process 2 →\rightarrow In this process work done by gas is zero.
View answer and explanation
Correct option: B
Process 1 may be isothermal, process 2 may
be isochoric
Option D is correct because a process with zero change in internal energy may be isothermal, and a process with zero work done must be isochoric.
143 Medium
143 of 363
Understanding +4 | -1
Which is/are path dependent?
View answer and explanation
Correct option: D
Both (2) and (3)
Option D is correct because work done and heat are path-dependent quantities, while internal energy is a state function.
144 Medium
144 of 363
Understanding +4 | -1
A system performs work ∆W when an amount of heat is ΔQ\Delta Q added to the system, the corresponding change in the internal energy is ΔU\Delta U. A unique function of the initial and final states (irrespective of the mode of change) is
View answer and explanation
Correct option: D
ΔU\Delta U
Option D is correct because the change in internal energy is a state function, depending only on the initial and final states, while heat and work are path-dependent.
145 Medium
145 of 363
Application +4 | -1
When 20 K cal of heat is supplied to the system and the increase in the internal energy is 8400 J, then the work done by the system is
View answer and explanation
Correct option: B
18 K cal
The correct answer is 18 K cal because it is calculated by applying the first law of thermodynamics: ΔW=ΔQ−ΔU\Delta W = \Delta Q - \Delta U.
146 Medium
146 of 363
Understanding +4 | -1
Statement-I: Two vessels A and B are connected to each other by a stopcock. Vessel A contains a gas at 300 K300 \mathrm{~K} and 1 atmosphere pressure and vessel B is evacuated. The two vessels are thermally insulated from the surroundings. If the stopcock is suddenly opened, the expanding gas does no work.
Statement-II: Since ΔQ=0\Delta Q=0 and as the gas expands freely so ΔW=0\Delta W=0 and from the first law of thermodynamics it follows that ΔU\Delta U is also zero for the above process.
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option A (Statement-I is true and statement-II is true) is correct because in free expansion, no work is done, and since it's insulated, there's no heat exchange, leading to no change in internal energy.
147 Medium
147 of 363
Analyzing +4 | -1
n1n_1 and n2n_2 are the moles of two ideal gases, whose thermodynamics constants, [ratio of (CpCv)\left(\frac{C_p}{C_v}\right) ] are γ1\gamma_1 and γ2\gamma_2 respectively, are mixed. (CpCv)\left(\frac{C_p}{C_v}\right) for the mixture is-
View answer and explanation
Correct option: D
n1γ1(γ2−1)+n2γ2(γ1−1)n1(γ2−1)+n2(γ1−1)\frac{n_1 \gamma_1\left(\gamma_2-1\right)+n_2 \gamma_2\left(\gamma_1-1\right)}{n_1\left(\gamma_2-1\right)+n_2\left(\gamma_1-1\right)}
Option D (n1γ1(γ2−1)+n2γ2(γ1−1)n1(γ2−1)+n2(γ1−1)\frac{n_1 \gamma_1(\gamma_2-1)+n_2 \gamma_2(\gamma_1-1)}{n_1(\gamma_2-1)+n_2(\gamma_1-1)}) is correct. It represents the correct formula for the adiabatic index of a mixture of ideal gases based on the number of moles and individual adiabatic indices.
148 Medium
148 of 363
Application +4 | -1
A gas mixture consists of 4 moles of O2\mathrm{O}_2 and 8 moles of Ar at temperature T. Neglecting all vibrational modes, the total internal energy of the system is:
View answer and explanation
Correct option: A
22 RT
Option A (22 RT) is correct because the total internal energy is the sum of the internal energies of each gas, considering their respective degrees of freedom.
149 Medium
149 of 363
Understanding +4 | -1
If a gas is compressed adiabatically by doing work of 250 J250 \mathrm{~J}, the change in intemal energy of the gas is:
View answer and explanation
Correct option: B
250 J
Option B (250 J) is correct because in an adiabatic process, the work done on the gas is equal to the increase in its internal energy.
150 Medium
150 of 363
Understanding +4 | -1
When a body A is in thermal equilibrium with a body B, and also separately with a body C, then B and C will be in thermal equilibrium with each other.
View answer and explanation
Correct option: A
TRUE
Option A (TRUE) is correct because it describes the Zeroth Law of Thermodynamics, which states that if two systems are each in thermal equilibrium with a third system, then they are in thermal equilibrium with each other.
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