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JEE • PHYSICS • THERMODYNAMICS
Thermodynamics practice · Mixed difficulty
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 151-180 of 384 questions
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151
Medium
151 of 384
Understanding
+4 | -1
Statement-I: Two vessels A and B are connected to each other by a stopcock. Vessel A contains a gas at and 1 atmosphere pressure and vessel B is evacuated. The two vessels are thermally insulated from the surroundings. If the stopcock is suddenly opened, the expanding gas does no work.
Statement-II: Since and as the gas expands freely so and from the first law of thermodynamics it follows that is also zero for the above process.
Statement-II: Since and as the gas expands freely so and from the first law of thermodynamics it follows that is also zero for the above process.
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option A (Statement-I is true and statement-II is true) is correct because in free expansion, no work is done, and since it's insulated, there's no heat exchange, leading to no change in internal energy.
152
Medium
152 of 384
Analyzing
+4 | -1
and are the moles of two ideal gases, whose thermodynamics constants, [ratio of ] are and respectively, are mixed. for the mixture is-
View answer and explanation
Correct option: D
Option D () is correct. It represents the correct formula for the adiabatic index of a mixture of ideal gases based on the number of moles and individual adiabatic indices.
153
Medium
153 of 384
Application
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A gas mixture consists of 4 moles of and 8 moles of Ar at temperature T. Neglecting all vibrational modes, the total internal energy of the system is:
View answer and explanation
Correct option: A
22 RT
Option A (22 RT) is correct because the total internal energy is the sum of the internal energies of each gas, considering their respective degrees of freedom.
154
Medium
154 of 384
Understanding
+4 | -1
If a gas is compressed adiabatically by doing work of , the change in intemal energy of the gas is:
View answer and explanation
Correct option: B
250 J
Option B (250 J) is correct because in an adiabatic process, the work done on the gas is equal to the increase in its internal energy.
155
Medium
155 of 384
Understanding
+4 | -1
When a body A is in thermal equilibrium with a body B, and also separately with a body C, then B and C will be in thermal equilibrium with each other.
View answer and explanation
Correct option: A
TRUE
Option A (TRUE) is correct because it describes the Zeroth Law of Thermodynamics, which states that if two systems are each in thermal equilibrium with a third system, then they are in thermal equilibrium with each other.
156
Medium
156 of 384
Application
+4 | -1
of water at and of ice at are mixed together in a calorimeter. Find the amount of ice that melts. (Specific heat of ice and latent heat of ice ).
View answer and explanation
Correct option: A
2.5 g
Option A (2.5 g) is correct because it is the amount of ice that melts when the heat lost by the water is used to first raise the temperature of the ice to 0°C and then melt it.
157
Medium
157 of 384
Understanding
+4 | -1
Which of the following processes is reversible
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Correct option: D
Isothermal compression
Option D (Isothermal compression) is correct because it is a quasi-static process that can be reversed by an infinitesimal change in conditions.
158
Medium
158 of 384
Analyzing
+4 | -1
Two identical containers and with friction less pistons contain the same ideal gas at the same temperature and the same volume . The mass of gas is and that of is . The gas in each cylinder is now allowed to expand isothermally to the same final volume . The change in the pressure in and are found to be and respectively. Then,
View answer and explanation
Correct option: C
Option C () is correct because the change in pressure is inversely proportional to the mass of the gas, leading to the relationship .
159
Medium
159 of 384
Application
+4 | -1
When an ideal gas is heated under constant pressure, then what percentage of given heat energy will be utilised in doing external work
View answer and explanation
Correct option: A
0.4
Option A (0.4) is correct because the fraction of heat used for external work in a constant pressure process is related to γ by the formula = 1 - .
160
Medium
160 of 384
Analyzing
+4 | -1
The work done during expansion of a gas is independent of pressure if the expansion takes place
View answer and explanation
Correct option: D
In none of the above cases
Option D (In none of the above cases) is correct because work done depends on pressure in both isothermal and adiabatic processes.
161
Medium
161 of 384
Application
+4 | -1
A Carnot engine has efficiency of . If the temperature of sink is reduced by , its efficiency increases by . The temperature of the source will be:
View answer and explanation
Correct option: C
Option C () is correct because it is the temperature of the source calculated from the given efficiency changes of the Carnot engine.
162
Medium
162 of 384
Analyzing
+4 | -1
Two Carnot engines A and B are operated in series. The engine receives heat from the source at temperature and rejects the heat to the sink at temperature . The second engine receives the heat at temperature and rejects to its sink at temperature . For what value of the efficiencies of the two engines are equal?
View answer and explanation
Correct option: D
Option D () is correct. Equating the efficiencies of the two Carnot engines and solving for T gives the geometric mean of T1 and T2.
163
Medium
163 of 384
Remembering
+4 | -1
First law of thermodynamics is based on
View answer and explanation
Correct option: B
Law of conservation of energy
Option B (Law of conservation of energy) is correct because the first law of thermodynamics states that energy is conserved, meaning it cannot be created or destroyed, only transformed.
164
Medium
164 of 384
Application
+4 | -1
The efficiency of the Carnot engine is and the temperature of the sink is . If the temperature of the source is kept constant and its efficiency raised to , then the required temperature of the sink will be
View answer and explanation
Correct option: C
Option C (400 K) is correct because it is calculated by first finding the source temperature using the initial efficiency and sink temperature, and then finding the new sink temperature for the increased efficiency.
165
Medium
165 of 384
Understanding
+4 | -1
(A): heat is given to melt ice cube and magnitude of work done by ice on surrounding is then
(R): First law of thermodynamics is applicable in this situation.
(R): First law of thermodynamics is applicable in this situation.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
Option A (Both (A) and (R) are true and (R) is the correct explanation of (A)) is correct because the first law of thermodynamics explains the relationship between heat, work, and internal energy change.
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166
Easy
166 of 384
Understanding
+4 | -1
Assertion: The internal energy of a real gas is function of both, temperature and volume.
Reason: At constant pressure, some heat is spent in expansion of the gas.
Reason: At constant pressure, some heat is spent in expansion of the gas.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion
Option A (If both assertion and reason are true and reason is the correct explanation of the assertion) is correct because the internal energy of a real gas depends on both temperature and volume due to intermolecular forces, and energy is used for expansion at constant pressure.
167
Medium
167 of 384
Analyzing
+4 | -1
Assertion(A): In adiabatic expansion process, the product of and always decreases.
Reason(R): In adiabatic expansion process, work is done by the gas at the cost of internal energy of gas.
Reason(R): In adiabatic expansion process, work is done by the gas at the cost of internal energy of gas.
View answer and explanation
Correct option: A
Both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
Option A is correct because in an adiabatic expansion, the gas does work at the expense of its internal energy, leading to a decrease in both temperature and the product of pressure and volume.
168
Medium
168 of 384
Application
+4 | -1
During an adiabatic compression, 830 J of work is done on 2 moles of a diatomic ideal gas to reduce its volume by 50%. The change in its temperature is nearly: ()
View answer and explanation
Correct option: C
20 K
Option C (20 K) is correct because it is calculated using the formula for work done during an adiabatic process.
169
Medium
169 of 384
Understanding
+4 | -1
A process is said to be reversible if
View answer and explanation
Correct option: B
Both the system as well as the surroundings
return to their original states
return to their original states
Option B (Both the system as well as the surroundings return to their original states) is correct because a reversible process is defined as one where both the system and surroundings can be returned to their initial states without any net change.
170
Medium
170 of 384
Understanding
+4 | -1
Assertion: The efficiency of a reversible engine is maximum
Reason: In such a device no dissipation of energy takes place.
Reason: In such a device no dissipation of energy takes place.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct
explanation of assertion
explanation of assertion
Option A (If both assertion and reason are true and reason is the correct explanation of assertion) is correct because a reversible engine has maximum efficiency due to no energy dissipation.
171
Easy
171 of 384
Understanding
+4 | -1
The work done in an isothermal expansion of a gas depends upon
View answer and explanation
Correct option: C
Both temperature and expansion ratio
Option C (Both temperature and expansion ratio) is correct because the work done in an isothermal expansion depends on both the temperature and the ratio of final to initial volume.
172
Medium
172 of 384
Application
+4 | -1
Work done by 0.1 mole of a gas at to double its volume at constant pressure is
View answer and explanation
Correct option: C
Option C () is correct because the maximum range is achieved at an angle of 45 degrees, and the range is twice the maximum height when the angle for maximum height is considered.
173
Medium
173 of 384
Analyzing
+4 | -1
Assertion: Sum of two path functions is always a path function.
Reason: Every state function can be produced by path functions.
Reason: Every state function can be produced by path functions.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D is correct because the sum of two path functions is not always a path function, and state functions cannot be produced by path functions.
174
Medium
174 of 384
Application
+4 | -1
A mass of lead shot is placed at the bottom of a vertical cardboard cylinder that is long and closed at both ends. The cylinder is suddenly inverted so that the shot falls . If this process is repeated quickly 100 times, assuming no heat is dissipated or lost, the temperature of the shot will increase by (specific heat of lead )
View answer and explanation
Correct option: D
Option D () is correct because the potential energy lost by the lead shot is converted into thermal energy, increasing its temperature.
175
Medium
175 of 384
Application
+4 | -1
An ideal heat engine works between temperatures . If the engine absorbs 600 J of heat from the source, then the amount of heat released to the sink is
View answer and explanation
Correct option: A
450 J
Option A (450 J) is correct because it is the amount of heat released to the sink, calculated using the efficiency formula for a heat engine.
176
Medium
176 of 384
Understanding
+4 | -1
In an isothermal process the volume of an ideal gas is halved. One can say that
View answer and explanation
Correct option: C
Work done by the gas is negative
Option C (Work done by the gas is negative) is correct because in an isothermal compression, work is done on the gas, hence negative work done by the gas.
177
Medium
177 of 384
Application
+4 | -1
An ideal gas is expanding such that = constant. The coefficient of volume expansion of the gas is
View answer and explanation
Correct option: C
Option C () is correct because it's derived from the ideal gas equation and the given relation = constant, leading to the coefficient of volume expansion.
178
Medium
178 of 384
Application
+4 | -1
A hammer of mass '' having speed of , hit a iron nail of mass . If specific heat of
iron is and half the energy is converted into heat, the raise be temperature of nail is
iron is and half the energy is converted into heat, the raise be temperature of nail is
View answer and explanation
Correct option: A
Option A () is correct because it represents the temperature rise calculated by equating half of the hammer's kinetic energy to the heat gained by the nail.
179
Medium
179 of 384
Understanding
+4 | -1
Assertion: For an isothermal process in an ideal gas, the heat obsorbed by the gas is entirely used in the work done by the gas.
Reason: During a process taking place in a system, the temperature remains constant then the process is isothermal.
Reason: During a process taking place in a system, the temperature remains constant then the process is isothermal.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not correct explanation of the assertion
Option B is correct. Both the assertion and the reason are true, but the reason doesn't explain the assertion. The assertion is true because in an isothermal process, , so . The reason is a definition of an isothermal process.
180
Medium
180 of 384
Understanding
+4 | -1
In a diagram for an ideal gas (where is along -axis and is along -axis), the value of the ratio "slope of adiabatic curve/slope of the isothermal curve" at any point will be (where symbols have their usual meanings).
View answer and explanation
Correct option: C
Option C () is correct because the ratio of the slope of the adiabatic curve to the slope of the isothermal curve is equal to gamma, which is .
Revision notes and key takeaways
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Showing 151-180 of 384 questions
