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JEE • PHYSICS • SYSTEM OF PARTICLES

System of particles practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 361-390 of 451 questions

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361 Medium
361 of 451
Understanding +4 | -1
Moment of inertia of an object does not depend upon
View answer and explanation
Correct option: C
Angular velocity
Option C (Angular velocity) is correct because the moment of inertia depends on the mass, mass distribution, and axis of rotation, but not on the angular velocity of the object.
362 Medium
362 of 451
Application +4 | -1
A particle is under uniform circular motion with angular momentum L. If its kinetic energy is tripled and frequency of motion is halved then new angular momentum becomes
View answer and explanation
Correct option: D
6 L
Option D (6 L) is correct because the new angular momentum is 6 times the original angular momentum, derived from the relationship between kinetic energy, angular momentum, and frequency.
363 Medium
363 of 451
Analyzing +4 | -1
For a hollow cylinder and a solid cylinder rolling without slipping on an inclined plane, then which of these reaches earlier
View answer and explanation
Correct option: A
solid cylinder
Option A (solid cylinder) is correct because the solid cylinder has a lower moment of inertia, resulting in a higher acceleration down the inclined plane.
364 Medium
364 of 451
Understanding +4 | -1
Statements:
a) Position of C.m depends on acceleration due to gravity where as position of C.g independent on acceleration due to gravity.
b) Centre of gravity of a body is defined to know the amount of stability of the body and the center of mass of the body is defined to describe the nature of motion of the body.
View answer and explanation
Correct option: B
a is false, b is true
Option B is correct because the position of the center of mass is independent of gravity, while the center of gravity depends on gravity. The second statement correctly describes the purpose of each concept.
365 Medium
365 of 451
Application +4 | -1
A ballet dancer spins about a vertical axis at 120 rpm with arms out stretched with her arms folded, moment of inertial about the axis of rotation decreases by 40%.40\%. Calculate the new rate of rotation is [in rpm]
View answer and explanation
Correct option: B
200
Option B (200) is correct because the new rate of rotation is calculated using the conservation of angular momentum.
366 Medium
366 of 451
Understanding +4 | -1
A horizontal disc rotates freely with angular velocity ω\omega about a vertical axes through its centre. A ring, having the same mass and radius as the disc, is now gently placed coaxially on the disc. After some time, the two rotate with a common angular velocity. Then
View answer and explanation
Correct option: B
The angular momentum of the system is conserved
Option B (The angular momentum of the system is conserved) is correct because there are no external torques acting on the disc-ring system.
367 Medium
367 of 451
Remembering +4 | -1
If the body is moving in a circle of radius r with a constant speed v, its angular velocity is
View answer and explanation
Correct option: C
v/r
Option C (v/r) is correct because angular velocity is defined as linear velocity divided by the radius of the circular path.
368 Medium
368 of 451
Understanding +4 | -1
For a particle of a purely rotating body, v=rωv=r \omega, so correct relation will be
View answer and explanation
Correct option: D
ω\omega is independent of rr
Option D is correct because for a purely rotating body, angular velocity is the same for all particles regardless of their distance from the axis of rotation.
369 Medium
369 of 451
Understanding +4 | -1
A point mass of 10 kg10 \mathrm{~kg} is placed at the centre of earth. The weight of the point mass is
View answer and explanation
Correct option: A
Zero
Option A (Zero) is correct because the gravitational acceleration at the center of the Earth is zero, resulting in zero weight.
370 Medium
370 of 451
Understanding +4 | -1
Assefion: Radius of gyration of body is a constant quantity.

Reason: The radius of gyration of a body about an axis of rotation may be defined as the root mean square distance of the particle from the axis of rotation.
View answer and explanation
Correct option: D
If both the Assertion and Reason are incorrect.
Option D (If both the Assertion and Reason are incorrect) is correct because the radius of gyration is not a constant quantity and depends on the axis of rotation and mass distribution.
371 Medium
371 of 451
Understanding +4 | -1
In pure rolling motion of a ring
a) It rotates about Instantaneous point of contact of ring and ground
b) Its centre of mass moves in translatory motion only
c) Its centre of mass will have translatory as well as rotatory motion
View answer and explanation
Correct option: C
a and b are correct
Option C (a and b are correct) is correct because in pure rolling, the ring rotates about the instantaneous point of contact, and its center of mass undergoes translational motion only.
372 Medium
372 of 451
Analyzing +4 | -1
Assertion: A judo fighter in order to throw his opponent on to the mat tries to initially bend his opponent and then rotate him around his hip.
Reason: As the mass of the opponent is brought closer to the fighter's hip, the force required to throw the opponent is reduced.
View answer and explanation
Correct option: A
If both assertion and reason are true and the reason is the correct explanation of the assertion.
Option A is correct because the judo fighter reduces the force required by bringing the opponent's mass closer to their hip, making the torque zero.
373 Medium
373 of 451
Analyzing +4 | -1
There are some passengers inside a stationary railway compartment. The centre of mass of the compartment itself (without the passengers) is C1,C_1, while the centre of mass of the 'compartment plus passengers' system is C2.C_2. If the passengers move about inside the compartment then
View answer and explanation
Correct option: C
C1C_1 Will move but C2C_2 will be stationary with respect to the ground
Option C is correct because the center of mass of the compartment plus passengers system remains stationary as there is no external force, while the compartment itself moves to compensate for the passengers' movement.
374 Medium
374 of 451
Understanding +4 | -1
Two particles move towards each other from rest under a mutual force of attraction. At the instant, when the speed of A is V, the speed of B is V/2. The speed of centre of mass of the system is
View answer and explanation
Correct option: D
zero
Option D (zero) is correct because, in the absence of external forces, the velocity of the center of mass remains constant. Since the particles start from rest, the initial velocity of the center of mass is zero, and it remains zero.
375 Medium
375 of 451
Application +4 | -1
If the earth is a point mass of 6×10246 \times {10^{24}}kg revolving around the sun at distance of 1.5×1081.5 \times {10^8}km and in time T = 3.14×1073.14 \times {10^7} seconds, then the angular momentum of the earth around the sun is [in kg−m2kg - {m^2} / s]
View answer and explanation
Correct option: D
2.7×10402.7 \times {10^{40}}
Option D (2.7×10402.7 \times {10^{40}}) is correct because it is the angular momentum calculated using the formula L = mvr = mωr².
376 Medium
376 of 451
Analyzing +4 | -1
Assertion: The centre of mass of a body may lie where there is no mass.
Reason: The centre of mass does not depend upon the mass of the body.
View answer and explanation
Correct option: C
If assertion is true but reason is false
The correct answer is C because the assertion is true (center of mass can be in empty space), but the reason is false (center of mass depends on mass distribution).
377 Medium
377 of 451
Understanding +4 | -1
(A): The spin angular velcoity of a star is greatly enhanced when it collapse under gravitational pull and become a neutron star.
(R): According to law of conservation of angular momentum there is increase in angular velocity of collapsing star.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
Option A is correct because both the assertion and the reason are true, and the reason correctly explains the assertion. The conservation of angular momentum causes the increase in angular velocity.
378 Medium
378 of 451
Understanding +4 | -1
Mass is non-uniformly distributed on the circumference of a ring of radius aa and centre at origin. Let bb be the distance of the centre of mass of the ring from origin. Then
View answer and explanation
Correct option: B
0≤b≤a0 \leq b \leq a
Option B is correct because the center of mass of a non-uniformly distributed mass on a ring can lie anywhere from the origin to the circumference.
379 Medium
379 of 451
Application +4 | -1
A disc rotates about its axis with a constant angular acceleration of 4 rad/s2.4 \mathrm{~rad} / \mathrm{s}^2. Find the radial and tangential accelerations of a particle at a distance of 1 cm1 \mathrm{~cm} from the axis at the end of the first second after the disc starts rotating.
View answer and explanation
Correct option: A
16 cm/s2,4 cm/s216 \mathrm{~cm} / \mathrm{s}^2, 4 \mathrm{~cm} / \mathrm{s}^2
Option A (16 cm/s2,4 cm/s216 \mathrm{~cm} / \mathrm{s}^2, 4 \mathrm{~cm} / \mathrm{s}^2) is correct because it correctly calculates the radial and tangential accelerations using the given angular acceleration and radius.
380 Medium
380 of 451
Application +4 | -1
A ring of mass 10 kg and diameter 0.4 m is rotated about its axis. If it makes 2100 revolutions per minute, then its angular momentum will be
View answer and explanation
Correct option: B
88  kg  ×m2/s88\;kg\; \times {m^2}/s
Option B (88  kg  ×m2/s88\;kg\; \times {m^2}/s) is correct because it is the result of calculating the angular momentum using the formula L=IωL = I\omega with the given parameters.
381 Medium
381 of 451
Understanding +4 | -1
If torque is zero, then
View answer and explanation
Correct option: A
Angular momentum is conserved
Option A is correct because if the net torque is zero, the angular momentum is conserved, according to the relation τ = dL/dt.
382 Medium
382 of 451
Application +4 | -1
The angular displacement of a particle is given by θ=4t3+3t2+2t+1\theta = 4{t^3} + 3{t^2} + 2t + 1 where ‘t’ is time in seconds. Its angular velocity at t=2 sec⁡t = 2\,\sec is [in rad/sec]
View answer and explanation
Correct option: C
62
The correct answer is C (62) because the angular velocity is the derivative of the angular displacement with respect to time, and evaluating this derivative at t=2s gives 62 rad/sec.
383 Medium
383 of 451
Understanding +4 | -1
One solid sphere A and another hallow sphere B are of same mass and same outer radii. Their moment of inertia about their diameters are respectively IA{I_A} and IB{I_B} such that
View answer and explanation
Correct option: C
IA<IB{I_A} < {I_B}
Option C (IA<IB{I_A} < {I_B}) is correct because for the same mass and radius, a hollow sphere has a larger moment of inertia than a solid sphere.
384 Medium
384 of 451
Understanding +4 | -1
A solid sphere is rotating freely about its symmetry axis in free space, The radius of the sphere is increased keeping
its mass same Which of the following physical quantities would remain constant for the sphere ?
View answer and explanation
Correct option: A
Angular momentum
Option B is correct because when the elevator moves downward with constant acceleration, the apparent weight is reduced, leading to a feeling of weight loss.
385 Medium
385 of 451
Application +4 | -1
The ratio of moments of inertia of a solid sphere about axes passing through its centre and tangent respectively is
View answer and explanation
Correct option: B
2:72:7
Option B (2:7) is correct because the moment of inertia about the center is 25MR2\frac{2}{5}MR^2 and about a tangent is 75MR2\frac{7}{5}MR^2, and the ratio is 2:7.
386 Medium
386 of 451
Understanding +4 | -1
The moment of inertia of semicircular ring about an axis which is perpendicular to the plane of the ring and passes through the centre
View answer and explanation
Correct option: A
MR2M{R^2}
Option A is correct because the moment of inertia of a semicircular ring about an axis perpendicular to the plane and passing through the center is MR².
387 Medium
387 of 451
Understanding +4 | -1
A square plate is kept in yz-plane. Then according to perpendicular axis theorem
View answer and explanation
Correct option: B
Ix=ly+IzI_x=l_y+I_z
Option B (Ix=ly+IzI_x=l_y+I_z) is correct because, according to the perpendicular axis theorem, for a planar lamina in the yz-plane, the moment of inertia about the x-axis is the sum of the moments of inertia about the y and z axes.
388 Medium
388 of 451
Analyzing +4 | -1
Assertion (A): A body rolling without slipping has only rotational kinetic energy.
Reason (R): The centre of mass of a rolling body docs not move forward.
View answer and explanation
Correct option: D
Both (A) and (R) are false
Option D (Both (A) and (R) are false) is correct because a rolling body has both translational and rotational kinetic energy, and the center of mass does move forward.
389 Medium
389 of 451
Application +4 | -1
The radius of gyration of a uniform rod of length L about on axis passing through its centre of mass and perpendicular to its length is
View answer and explanation
Correct option: A
L/12L/\sqrt {12}
Option A (L/12L/\sqrt {12}) is correct because it is the radius of gyration for a uniform rod about an axis through its center.
390 Medium
390 of 451
Understanding +4 | -1
Two particles of masses m1 and m2{m_1}\,and\,{m_2} initially at rest start moving towards each other under their mutual force of attraction. The speed of the centre of mass at any time tt, when they are at a distance rr apart, is
View answer and explanation
Correct option: A
Zero
Option A (Zero) is correct because there is no external force acting on the system, and the center of mass was initially at rest.
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