A uniform disc of mass 2 kg and radius 15 cm is revolving around the central axis by 4 ${\rm{rad}}{{\rm{s}}^{ - 1}}$. The linear momentum of disc will be

$1.2\;{\rm{kg}} - {\rm{m}}{{\rm{s}}^{ - 1}}\;$

$1.0\;{\rm{kg}} - {\rm{m}}{{\rm{s}}^{ - 1}}\;$

$0.6\;{\rm{kg}} - {\rm{m}}{{\rm{s}}^{ - 1}}\;$

JEE PHYSICS MCQ: SYSTEM OF PARTICLES

1 Medium

1 of 1

Understanding +4 | -1

A uniform disc of mass 2 kg and radius 15 cm is revolving around the central axis by 4

\mathrm{rad}{\mathrm{s}^{ - 1}}

. The linear momentum of disc will be

View answer and explanation

Correct option: D

None of these

Option D (None of these) is correct because the linear momentum of a rotating disc about its center of mass is zero.

Practice All Chapter MCQs →

\mathrm{AB}

\mathrm{L}

\mu(x)=a+\frac{b x}{L}

x

\mathrm{A}

\mathrm{CM}

\left(\frac{7}{12}\right) \mathrm{L}

\mathrm{A}

\mathrm{b}

1.0 \mathrm{~g}

8 \mathrm{~cm}

\omega = {t^4} + 2{t^3}

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)