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JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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One quarter of the disc of mass m is removed. If rr be the radius of the disc, the new moment of inertia is
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Correct option: C
38mr2\frac{3}{8}m{r^2}
Option C (38mr2\frac{3}{8}m{r^2}) is correct because the moment of inertia is proportional to the mass, and removing one-quarter of the disc reduces the mass to three-quarters.

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