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JEE • PHYSICS • SYSTEM OF PARTICLES

System of particles practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 151-180 of 483 questions

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151 Medium
151 of 483
Understanding +4 | -1
A nonzero external force acts on a system of particles. The velocity and the acceleration of the centre of mass are found to be v0v_0 and a0a_0 at an instant tt. It is possible that
View answer and explanation
Correct option: B
v0=0,a0≠0v_0=0, a_0 \neq 0
Option B (v0=0,a0≠0v_0=0, a_0 \neq 0) is correct because a non-zero external force implies a non-zero acceleration of the center of mass, while the velocity can be instantaneously zero.
152 Medium
152 of 483
Understanding +4 | -1
S-I: Ratio of the distances of the centre of mass of a two particle system are in the inverse ration of their masses
S-II: The location of the centre of mass is independent of the reference frame used locate it.
View answer and explanation
Correct option: A
Both S-I and S-II are correct
Option A (Both S-I and S-II are correct) is correct because the center of mass divides the distance between two particles in the inverse ratio of their masses, and its location is independent of the reference frame.
153 Medium
153 of 483
Remembering +4 | -1
When a body does not rotate or rotates with a constant angular velocity (ω).(\omega). It is said to be in:
View answer and explanation
Correct option: A
Rotational Equilibrium
Option A (Rotational Equilibrium) is correct because rotational equilibrium occurs when there is no net torque, resulting in either no rotation or constant angular velocity.
154 Medium
154 of 483
Application +4 | -1
A solid cylinder of mass MM and radius RR rolls without slipping down an inclined plane of length LL and height hh. What is the speed of its centre of mass when the cylinder reaches its bottom
View answer and explanation
Correct option: B
43gh\sqrt {\frac{4}{3}gh}
Option B (43gh\sqrt {\frac{4}{3}gh}) is correct because it is the final speed calculated using conservation of energy for rolling without slipping.
155 Medium
155 of 483
Application +4 | -1
Let M\mathrm{M} and L\mathrm{L} be the mass and length of thin uniform rod respectively. In 1st 1^{\text {st }} case, axis of rotation is passing through centre and perpendicular to its length. In 2nd 2^{\text {nd }} case, axis of rotation is passing through one end and perpendicular to its length. The ratio of radius of gyration in first case to second case is
View answer and explanation
Correct option: A
1:21: 2
Option A (1:2) is correct because the ratio of the radius of gyration is calculated based on the moment of inertia for each case.
156 Medium
156 of 483
Understanding +4 | -1
The centre of mass of a body is defined as the point at which the whole of its mass is supposed to be concentrated, while centre of gravity of a body is defined as the point at which whole of its weight is supposed to be concentrated then,
View answer and explanation
Correct option: B
the centre of gravity may lie slightly below the centre of mass
Option B (the centre of gravity may lie slightly below the centre of mass) is correct because the gravitational field is not perfectly uniform, and the lower parts of an object experience slightly stronger gravity.
157 Medium
157 of 483
Analyzing +4 | -1
An equilateral triangle ABCA B C formed from a uniform wire has two small identical beads initially located at AA. The triangle is set rotating about the vertical axis AOA O. Then the beads are released from rest simultaneously and allowed to slide down, one along ABA B and the other along ACA C as shown. Neglecting frictional effects, the quantities that are conserved as the beads slide down, are
View answer and explanation
Correct option: B
total angular momentum and total energy
Option B (total angular momentum and total energy) is correct because no external torque acts on the system and energy is conserved due to the absence of friction.
158 Medium
158 of 483
Application +4 | -1
The unit mass has r=8i^−4j^{r}=8 \hat{{i}}-4 \hat{{j}} and v=8i^+4j^{v}=8 \hat{{i}}+4 \hat{{j}}. Its angular momentum is
View answer and explanation
Correct option: B
64 units in +k^+\hat{{k}} direction
Option B (64 units in +k^+\hat{{k}} direction) is correct because the angular momentum is calculated as the cross product of the position vector and the velocity vector, L=r×vL = r \times v.
159 Medium
159 of 483
Analyzing +4 | -1
Two uniform solid spheres having unequal masses and unequal radii are released from rest from the same height on a rough incline. If the spheres roll without slipping,
View answer and explanation
Correct option: C
the two spheres reach the bottom together
Option C (the two spheres reach the bottom together) is correct because the acceleration of a rolling sphere on an incline is independent of its mass and radius.
160 Medium
160 of 483
Understanding +4 | -1
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R

Assertion A : An electric fan continues to rotate for some time after the current is switched off.

Reason R: Fan continues to rotate due to inertia of motion.

In the light of above statements, choose the most appropriate answer from the options given below.
View answer and explanation
Correct option: C
Both A and R are correct and R is the correct explanation of A
Option C is correct because the fan's continued rotation is due to its inertia of motion, which opposes changes in its state of motion.
161 Medium
161 of 483
Analyzing +4 | -1
Assertion: A solid sphere and a hollow sphere are rolling on ground with same total kinetic energies. If translational kinetic energy of solid sphere is KK, then translational kinetic energy of hollow sphere should be greater than KK.


Reason: In case of hollow sphere rotational kinetic energy is less than its translational kinetic energy.
View answer and explanation
Correct option: D
If Assertion is false but the Reason is true
Option D (If Assertion is false but the Reason is true) is correct because the assertion is false, and the reason is true. The hollow sphere's translational kinetic energy is less than K.
162 Medium
162 of 483
Remembering +4 | -1
What remains constant in the field of central force
View answer and explanation
Correct option: C
Angular momentum
Option C (Angular momentum) is correct because in a central force field, the torque acting on the particle is zero, leading to the conservation of angular momentum.
163 Medium
163 of 483
Understanding +4 | -1
A particle covers equal distances around a circular path in equal intervals of time. It has uniform nonzero rate of change of
View answer and explanation
Correct option: B
angular displacement.
Option B (angular displacement) is correct because the particle covers equal distances in equal times, implying a constant angular speed and thus a uniform non-zero rate of change of angular displacement.
164 Medium
164 of 483
Understanding +4 | -1
A particle performing uniform circular motion has
View answer and explanation
Correct option: C
Transverse velocity and radial acceleration
Option C (Transverse velocity and radial acceleration) is correct because in uniform circular motion, the velocity is tangential (transverse) and the acceleration is directed towards the center (radial).
165 Medium
165 of 483
Analyzing +4 | -1
A solid homogeneous sphere is moving on a rough horizontal surface, partly rolling and partly sliding. During this kind of motion of this sphere
View answer and explanation
Correct option: D
Angular momentum about the centre of mass is conserved.
Option D (Angular momentum about the centre of mass is conserved) is correct because the net torque about the center of mass is zero when only friction acts.
166 Medium
166 of 483
Application +4 | -1
A fly wheel is accelerated uniformly from rest and rotates through 5 rad in the first second. The angle rotated by the fly wheel in the next second, will be:
View answer and explanation
Correct option: B
15 rad
Option A (15 rad) is correct because the angle rotated in the next second is calculated using the angular acceleration and the time interval.
167 Medium
167 of 483
Application +4 | -1
A circular disc is rotating about its natural axis with
angular velocity of 20 rad/s. A second disc of same
mass gently placed on it co-axially. If the radius of
disc is half of the radius of the first, then they will
start rotating with angular velocity of
View answer and explanation
Correct option: D
16 rad/s
The correct answer is D (16 rad/s) because angular momentum is conserved when the second disc is placed on the first.
168 Medium
168 of 483
Understanding +4 | -1
If the net external forces acting on the system of particles is zero, then which of the following may vary?
View answer and explanation
Correct option: C
Position of centre of mass
Option C (Position of centre of mass) is correct because if the net external force is zero, the velocity of the center of mass remains constant, but its position can still change with time.
169 Medium
169 of 483
Analyzing +4 | -1
A sphere is rotating about a diameter with constant angular acceleration α.\alpha.
Assertion (A): All the particles on the surface have same linear acceleration.
Reason (R): All the particles on the surface have same linear speed.
View answer and explanation
Correct option: D
Both (A) and (R) are false
Option D (Both (A) and (R) are false) is correct because the linear acceleration and linear speed vary depending on the position of the particle on the sphere's surface.
170 Medium
170 of 483
Remembering +4 | -1
Angular momentum is
View answer and explanation
Correct option: A
Moment of momentum
The correct answer is A (Moment of momentum) because angular momentum is defined as the cross product of the position vector and the linear momentum.
171 Hard
171 of 483
Understanding +4 | -1
Moment of inertia of a uniform annular disc of internal radius rr and external radis RR and mass MM about an axis through its centre and perpendicular to its plane is
View answer and explanation
Correct option: B
12M(R2+r2)\frac{1}{2} M\left(R^2+r^2\right)
Option B (12M(R2+r2)\frac{1}{2} M(R^2+r^2)) is correct because it represents the moment of inertia of an annular disc about an axis through its center and perpendicular to its plane.
172 Easy
172 of 483
Application +4 | -1
Three masses are placed on the x – axis, 200 g at origin, 400 g at x = 20 cm and 600 g at x = 60 cm. The distance of the centre of mass from the origin is
View answer and explanation
Correct option: D
1103 cm\frac{{110}}{3}\,cm
Option D (1103 cm\frac{{110}}{3}\,cm) is correct because it is calculated using the center of mass formula for a system of particles.
173 Medium
173 of 483
Application +4 | -1
The moment of inertia of a circular ring of radius 15 cm15 \mathrm{~cm} and mass 150 g150 \mathrm{~g} is _____
View answer and explanation
Correct option: D
0.003 kg⋅m20.003 \mathrm{~kg} \cdot \mathrm{m}^2
Option D (0.003 kg⋅m20.003 \mathrm{~kg} \cdot \mathrm{m}^2) is correct because it is calculated using the formula for the moment of inertia of a circular ring, I=mr2I = mr^2.
174 Medium
174 of 483
Application +4 | -1
A binary star consists of two stars A (mass 2.2 Ms{M_s}) and B (mass 11 Ms{M_s}), where Ms{M_s} is the mass of the sun. They are separated by distance d and are rotating about their centre of mass, which is stationary. The ratio of the total angular momentum of the binary star to the angular momentum of star B about the centre of mass is
View answer and explanation
Correct option: B
6
Option B (6) is correct because the ratio of total angular momentum to the angular momentum of star B is calculated using the moment of inertia and angular velocity relationship, considering the inverse proportionality between radius and mass.
175 Medium
175 of 483
Application +4 | -1
The moment of inertia of a body about a given axis is 2.4 kg−m22.4\,kg - {m^2}. To produce a rotational kinetic energy of 750 J, an angular acceleration of 5 rad/s2{s^2} must be applied about the axis for
View answer and explanation
Correct option: B
5 sec
Option B (5 sec) is correct because it is calculated using the rotational kinetic energy formula and angular acceleration formula.
176 Medium
176 of 483
Application +4 | -1
If the equation for the displacement of a particle moving on a circular path is given by (θ)=2t3+0.5\left( \theta \right) = 2{t^3} + 0.5, where θ\theta is in radians and t in seconds, then the angular velocity of the particle after 2 sec from its start is
View answer and explanation
Correct option: C
24 rad/sec
Option C (24 rad/sec) is correct because the angular velocity is the derivative of the angular displacement with respect to time, evaluated at t=2s.
177 Medium
177 of 483
Application +4 | -1
For a body rolling along a level surface, the translational and rotational K.E are equal. The body is
View answer and explanation
Correct option: C
Disc
Option C (Disc) is correct because for a disc, the moment of inertia is I=12mr2I = \frac{1}{2}mr^2, making the translational and rotational kinetic energies equal when rolling.
178 Medium
178 of 483
Understanding +4 | -1
Which of the following statements are correct?

1) Centre of mass of body always coincides with the centre of gravity of the body.

2) Central mass of a body is the point at which the total gravitational torque on the body is zero.

3) A couple on a body produce both translational and rotational motion in a body.

4) Mechanical advantage greater than one means that small effort can be used to lift a large load.
View answer and explanation
Correct option: B
(b) and (d)
Option B ((b) and (d)) is correct because the center of gravity is where the total gravitational torque is zero, and a mechanical advantage greater than one means a small effort can lift a large load.
179 Medium
179 of 483
Application +4 | -1
Two rods each having length ll and mass m\mathrm{m} joined together at point B\mathrm{B} as shown in figure. Then find out moment of inertia about axis passing through A\mathrm{A} and perpendicular to the plane of page as shown in figure.
View answer and explanation
Correct option: D
5ml23\frac{5 m l^2}{3}
Option D (5ml23\frac{5 m l^2}{3}) is correct because it is the sum of the moments of inertia of both rods about the specified axis.
180 Medium
180 of 483
Application +4 | -1
A solid sphere of radius RR has its outer half removed, so that its radius becomes (R/2)(R / 2). Then its moment of inertia about the diameter is
View answer and explanation
Correct option: D
becomes 132\frac{1}{32} of initial volume
Option D (becomes 132\frac{1}{32} of initial volume) is correct because the moment of inertia depends on both mass and radius, and both are reduced when the outer half is removed.
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