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JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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A solid cylinder of mass 4 kg and radius 8 cm is rotating about its axis at the rate of 6 rpm. The torque required to stop after 4π4 \pi revolutions is:
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Correct option: D
3.2×10−5 N m3.2 \times 10^{-5} \mathrm{~N} \mathrm{~m}
Option D (3.2×10−5 N m3.2 \times 10^{-5} \mathrm{~N} \mathrm{~m}) is correct because it is calculated by finding the angular deceleration and then using τ=Iα\tau = I\alpha.

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