Back to SYSTEM OF PARTICLES

JEE PHYSICS MCQ: SYSTEM OF PARTICLES

1 Medium

1 of 1

Analyzing +4 | -1

S-I: A wheel moving down a perfectly frictionless inclined plane will undergo slipping (not rolling motion).
S-II: For perfect rolling motion, work done against the friction is zero.

View answer and explanation

Correct option: A

Both S-I and S-II are correct

Option A (Both S-I and S-II are correct) is correct because a frictionless inclined plane results in slipping, and perfect rolling implies zero work done against friction.

More Questions from SYSTEM OF PARTICLES

Practice All Chapter MCQs →

It is easier for a swimmer jumping into water from a height to describe a loop in the air by A uniform thin rod

\mathrm{AB}

\mathrm{L}

has linear mass density

\mu(x)=a+\frac{b x}{L}

x

is measured from

\mathrm{A}

\mathrm{CM}

of the rod lies at a distance of

\left(\frac{7}{12}\right) \mathrm{L}

\mathrm{A}

\mathrm{b}

are related as : A solid metal ring and a disc of same radius and mass are rotating about their diameters with same angular frequency. The ratio of their respective rotational kinetic energy values is When a torque acting upon a system is zero, then which of the following will be constant A point particle of mass

1.0 \mathrm{~g}

is rotating in a circle of diameter

8 \mathrm{~cm}

. Its moment of inertia will be The angular velocity of a particle is given by

\omega = {t^4} + 2{t^3}

then its angular acceleration of the particle at

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)