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JEE • PHYSICS • OSCILLATIONS
Oscillations practice · Mixed difficulty
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 211-240 of 483 questions
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211
Medium
211 of 483
Application
+4 | -1
In SHM, potential energy of a particle at mean position is and kinetic energy is , then
View answer and explanation
Correct option: B
total potential energy at is
The correct answer is that the total potential energy at is because it correctly applies the potential energy formula for SHM.
212
Medium
212 of 483
Application
+4 | -1
A simple pendulum of length and having a bob of mass is suspended in a car. moving on a circular track of radius with uniform speed If the pendulum makes small oscillation in a radial direction about its equilibrium position, then its time period can be given by The value of is
[Take ]
[Take ]
View answer and explanation
Correct option: C
101
Option C (101) is correct because the time period of the pendulum is affected by the centripetal acceleration of the car, and the effective acceleration is used to calculate the time period.
213
Medium
213 of 483
Analyzing
+4 | -1
Consider one dimensional motion of a particle of mass . It has potential energy , where ' ' and ' ' are positive constants. At origin it has initial velocity . It performs simple harmonic oscillations. The frequency of the simple harmonic motion depends on
View answer and explanation
Correct option: A
and alone
Option A ( and alone) is correct because the frequency of SHM is derived from the potential energy function and depends only on the constant and the mass .
214
Medium
214 of 483
Understanding
+4 | -1
How does the time period of pendulum vary with length
View answer and explanation
Correct option: A
Option A () is correct because the time period of a simple pendulum is directly proportional to the square root of its length.
215
Medium
215 of 483
Application
+4 | -1
The maximum height of a simple pendulum with respect to the equilibrium position is and the maximum velocity of the bob of pendulum is . Then
View answer and explanation
Correct option: C
Option C () is correct because it is derived from the conservation of energy, equating the change in kinetic energy to the change in potential energy.
216
Medium
216 of 483
Application
+4 | -1
In a SHM, when the displacement is one half
the amplitude, what fraction of the total energy
is kinetic?
the amplitude, what fraction of the total energy
is kinetic?
View answer and explanation
Correct option: D
Option D () is correct because the kinetic energy is 3/4 of the total energy when the displacement is half the amplitude in SHM.
217
Medium
217 of 483
Application
+4 | -1
A simple harmonic oscillation is represented by the equation where and are in metre and second respectively. The value of time period is
View answer and explanation
Correct option: A
Option A () is correct because the time period is calculated from the angular frequency in the given equation.
218
Medium
218 of 483
Application
+4 | -1
The kinetic energy of a particle executing S.H.M. is 16 J when it is in its mean position. If the amplitude of oscillations is 25 and the mass of the particle is 5.12 kg, the time period of its oscillation is
View answer and explanation
Correct option: A
Option A () is correct because it's calculated using the maximum kinetic energy, amplitude, and mass to find the angular frequency and then the time period.
219
Medium
219 of 483
Understanding
+4 | -1
For a simple pendulum, the graph between and (where is the time period and is the length) is
View answer and explanation
Correct option: A
straight line passing through origin
Option A (straight line passing through origin) is correct because the square of the time period () is directly proportional to the length () of the pendulum, resulting in a linear relationship that passes through the origin.
220
Medium
220 of 483
Understanding
+4 | -1
If and denote the average kinetic and the average potential energies respectively of mass describing a simple harmonic motion, over one period, then the correct relation is
View answer and explanation
Correct option: A
Option A is correct because in Simple Harmonic Motion (SHM), the average kinetic energy and average potential energy over one period are equal.
221
Easy
221 of 483
Analyzing
+4 | -1
Molten-wax of mass drops on a block of mass , which is oscillating on a frictionless table. Select the correct option.
View answer and explanation
Correct option: D
time period increases
Option D (time period increases) is correct because the time period of a simple harmonic oscillator is proportional to the square root of the mass, and the mass increases when wax drops on the block.
222
Medium
222 of 483
Application
+4 | -1
The displacement of an elastic wave is given by the function where ‘y’ is in cm and ‘t’ is in second. Then the resultant amplitude in
View answer and explanation
Correct option: D
5
Option D (5) is correct because the resultant amplitude is found using the formula for the superposition of two waves with a phase difference of 90 degrees.
223
Medium
223 of 483
Application
+4 | -1
A linear oscillator of unit mass of force constant and amplitude has a total mechanical energy of
View answer and explanation
Correct option: A
Option B (6 m) is correct because the length of the rod is calculated from the radius of gyration formula.
224
Medium
224 of 483
Application
+4 | -1
A particle hanging from a spring stretches it by at earth's surface. Radius of earth is . At a place 800 above the earth's surface, the same particle will stretch the spring by:
View answer and explanation
Correct option: D
0.79 cm
Option D (0.79 cm) is correct because it is calculated by considering the variation of gravitational force with distance from the Earth's center.
225
Medium
225 of 483
Understanding
+4 | -1
Motion of a ball bearing inside a smooth curved bowl, when released from a point slightly above the lower point is
View answer and explanation
Correct option: A
Simple harmonic motion
Option A (Simple harmonic motion) is correct because the ball bearing's motion approximates SHM when released slightly above the lowest point in a smooth curved bowl.
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226
Medium
226 of 483
Understanding
+4 | -1
The total energy of particle performing SHM depend on
View answer and explanation
Correct option: A
Option A () is correct because the total energy of a particle in SHM depends on the spring constant (), amplitude (), and mass ().
227
Easy
227 of 483
Understanding
+4 | -1
Two particles are executing simple harmonic motion. At an instant of time , their displacements are and
Then, the phase difference between and is
Then, the phase difference between and is
View answer and explanation
Correct option: B
Option B () is correct because the phase difference between cosine and sine functions with the same argument is 90 degrees.
228
Medium
228 of 483
Application
+4 | -1
A particle is executing S.H.M with time period and amplitude . The graphical plot of velocity versus displacement of the particle
View answer and explanation
Correct option: C
May be a circle
Option C (May be a circle) is correct because the v-x plot for SHM can be an ellipse, and a circle is a special case of an ellipse when the angular frequency is 1.
229
Medium
229 of 483
Application
+4 | -1
A particle is executing simple harmonic motion. Its displacement to amplitude ratio when its kinetic energy is of total energy is
View answer and explanation
Correct option: B
Option B () is correct because the ratio is found by equating the kinetic energy to 84% of the total energy and solving for the displacement to amplitude ratio.
230
Medium
230 of 483
Application
+4 | -1
A body is executing SHM, if the force acting on the body is 6 N. When the displacement is 2 cm, then the force acting on the body at a displacement of 3 cm is
View answer and explanation
Correct option: B
9N
Option B (9N) is correct because the force in SHM is directly proportional to the displacement.
231
Medium
231 of 483
Application
+4 | -1
Three springs are connected to a mass . When mass oscillates, what is the effective spring constant and time period of vibration? Given and .
View answer and explanation
Correct option: A
The correct answer is A () because the effective spring constant is the sum of individual spring constants and the time period is calculated using this effective constant.
232
Easy
232 of 483
Application
+4 | -1
To make the frequency of an oscillator double, one has to
View answer and explanation
Correct option: D
reduce the mass to one-fourth
Option D (reduce the mass to one-fourth) is correct because the frequency of an oscillator is inversely proportional to the square root of the mass.
233
Medium
233 of 483
Application
+4 | -1
If a spring of mass has spring constant of , then its time period, is
View answer and explanation
Correct option: D
seconds
Option D ( seconds) is correct because the time period of a spring is calculated using the formula .
234
Medium
234 of 483
Understanding
+4 | -1
Statement-I: If Amplitude of SHM is doubled, the periodicity wall remain same.
Statement-II: Amlitude and periodicity are two independent characteristics of SHM.
Statement-II: Amlitude and periodicity are two independent characteristics of SHM.
View answer and explanation
Correct option: A
If both Statement- I and Statement- II are true, and Statement - II is the correct explanation of Statement-I.
Option A (If both Statement- I and Statement- II are true, and Statement - II is the correct explanation of Statement-I) is correct because the period of SHM is independent of the amplitude.
235
Medium
235 of 483
Analyzing
+4 | -1
A pendulum made of a uniform wire of cross – sectional area A has time period T. When an additional mass M is added to its bob, the time period changes If the Young’s modulus of the material of the wire is Y, then is equal to ( = gravitational acceleration)
View answer and explanation
Correct option: A
Option A () is correct because it correctly relates the change in time period to Young's modulus and the added mass.
236
Medium
236 of 483
Application
+4 | -1
A particle is executing SHM of period 24 and of amplitude 41 cm with O as equilibrium position. The minimum time in seconds taken by the particle to go from P to Q. where OP = -9 cm and OQ =40 cm is
View answer and explanation
Correct option: B
6
Option B (6) is correct because the minimum time taken to go from P to Q is calculated using the SHM equation and the given displacements.
237
Medium
237 of 483
Application
+4 | -1
The displacement of an elastic wave is given by the function where ‘y’ is in cm and ‘t’ is in second. Then the resultant amplitude in
View answer and explanation
Correct option: D
5
Option D (5) is correct because the resultant amplitude is found using the formula for the superposition of two waves with a phase difference of 90 degrees.
238
Medium
238 of 483
Understanding
+4 | -1
Which one of the following statements is
correct?
correct?
View answer and explanation
Correct option: C
The measurement of mass taken by a spring weighing balance is corrected at the place where the acceleration due to gravity is same with the place where the spring balance is calibrated for
The measurement of mass taken by a spring weighing balance is corrected at the place where the acceleration due to gravity is same with the place where the spring balance is calibrated for is correct because the reading depends on the local gravitational acceleration.
239
Medium
239 of 483
Application
+4 | -1
At a given instant of time the position vector of a particle moving in a circle with a velocity is . Its angular velocity at that time is
View answer and explanation
Correct option: B
Option D () is correct because it is calculated using the formula for angular velocity, which is the cross product of the position vector and velocity vector, divided by the square of the magnitude of the position vector.
240
Medium
240 of 483
Understanding
+4 | -1
When a simple pendulum is moved from the Earth's surface to deep mine, the period of oscillation
View answer and explanation
Correct option: C
Increases
Option C is correct because the acceleration due to gravity decreases as you go deeper into the mine, which increases the period of oscillation of a simple pendulum.
Revision notes and key takeaways
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Showing 211-240 of 483 questions
