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JEE PHYSICS MCQ: OSCILLATIONS

1 Medium

1 of 1

Application +4 | -1

A particle moving on

x

-axis has potential energy

U=2-20 x+5 x^2

joule along

x

-axis. The particle is released at

x=-3

. The maximum value of

x

will be (

x

is in metre)

View answer and explanation

Correct option: C

7 \mathrm{~m}

Option C (

7 \mathrm{~m}

) is correct because the maximum value of x is found by determining the equilibrium position and using the amplitude of the oscillation.

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{y_1}

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{U_1}

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{y_2}

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{U_2}

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