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JEE PHYSICS MCQ: OSCILLATIONS

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A particle executes simple harmonic motion with an amplitude of 5 cm. When the particle is at 4 cm from the mean position, the magnitude of its velocity in SI units is equal to that of its acceleration. Then, its periodic time (in seconds) is
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Correct option: B
8π3\frac{{8\pi }}{3}
Option B (8π3\frac{{8\pi }}{{3}}) is correct because the periodic time is calculated using the relationship between velocity, acceleration, amplitude, and angular frequency in SHM.

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