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JEE PHYSICS MCQ: OSCILLATIONS

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Application +4 | -1
If the maximum acceleration of a SHMSHM is α\alpha and the maximum velocity is β\beta, then the amplitude of vibration is
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Correct option: C
β2α\frac{{{\beta ^2}}}{\alpha }
Option C (β2α\frac{{{\beta ^2}}}{\alpha }) is correct because it is derived from the relationship between maximum acceleration, maximum velocity, angular frequency, and amplitude in SHM.

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