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JEE • PHYSICS • MOTION IN A STRAIGHT LINE

Motion in a straight line practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 271-285 of 285 questions
271 Medium
271 of 285
Analyzing +4 | -1
Car AA is moving with a speed of 36 kmh−136 \mathrm{~kmh}^{-1} on a two lane road. Two cars BB and CC, each moving with a speed of 54 kmh−154 \mathrm{~kmh}^{-1} in opposite directions on the other lane are approaching car A. At certain instant of time, when the distance AB=AC=1 kmA B=A C=1 \mathrm{~km}, the driver of car BB decides to overtake AA before CC does. What must be the minimum acceleration of car BB, so as to avoid an accident ?
View answer and explanation
Correct option: A
1 ms−21 \mathrm{~ms}^{-2}
Option A (1 ms−21 \mathrm{~ms}^{-2}) is correct because it is the minimum acceleration required for car B to overtake car A before car C reaches car A.
272 Medium
272 of 285
Analyzing +4 | -1
A particle moves along a straight line such that its position x at any time t is x=6t2−t3.x = 6{t^2} - {t^3}.. Where x in metre and t is in second, then
View answer and explanation
Correct option: D
Both (1) and (2) are correct
Option D (Both (1) and (2) are correct) is correct because at t=0, the acceleration is 12 m/s², and the x-t curve has a maximum at t=4 s.
273 Medium
273 of 285
Understanding +4 | -1
Two bodies one held 100 cm100 \mathrm{~cm} directly above the other are released simultaneously from the large height and both fall freely under the gravity. The separation between the bodies just after 2 s2 \mathrm{~s} will be
View answer and explanation
Correct option: B
100 cm100 \mathrm{~cm}
Option B is correct because the separation between the two bodies remains constant at 100 cm as they fall under gravity.
274 Medium
274 of 285
Application +4 | -1
Two trains travelling on the same track are approaching each other with equal speeds of 40ms−140\mathrm{m}{\mathrm{s}^{ - 1}}. The drivers of the trains begin to decelerate simultaneously when they are just 2 km apart. If the decelerations are both uniform and equal, then the value of deceleration to barely avoid collision should be
View answer and explanation
Correct option: A
0.8ms−20.8\mathrm{m}{\mathrm{s}^{ - 2}}
Option A (0.8ms−20.8\mathrm{m}{\mathrm{s}^{ - 2}}) is correct because it is the deceleration required to avoid collision, calculated using kinematics.
275 Medium
275 of 285
Analyzing +4 | -1
Which of the following 4 statements is false
View answer and explanation
Correct option: B
A body can have a constant velocity and still have a varying speed
Option B is correct. A body cannot have a constant velocity and still have a varying speed because constant velocity implies both constant speed and constant direction.
276 Medium
276 of 285
Application +4 | -1
A cyclist moving on a circular track of radius 40 m completes half a revolution in 40 s. Its average velocity is
View answer and explanation
Correct option: C
2 m/s2\,{\text{m/s}}
Option C (2 m/s) is correct because average velocity is calculated by dividing the displacement by the time taken, and in half a revolution, displacement is 2R.
277 Medium
277 of 285
Application +4 | -1
An object is moving with uniform acceleration. Its velocity after 5 seconds is 25 ms−125 \mathrm{~ms}^{-1} and after 8 seconds, it is 34 ms−1.34 \mathrm{~ms}^{-1}. Find the distance travelled by the object in 12th second.
View answer and explanation
Correct option: A
44.5 m44.5 \mathrm{~m}
Option A (44.5 m) is correct because the distance travelled in the 12th second is calculated using the kinematic equations of motion with uniform acceleration.
278 Medium
278 of 285
Application +4 | -1
A body is dropped from the top of a tower clears (7/16)th{\left( {7/16} \right)^{\mathrm{th}}} of total height of the tower in its last second of flight. The height of the tower is
View answer and explanation
Correct option: C
78.4 m
Option C (78.4 m) is correct because it is calculated by using the kinematic equation of motion and solving for the height of the tower.
279 Medium
279 of 285
Analyzing +4 | -1
Assertion: For a particle, acceleration-time graph gives the velocity.
Reason: Rate of change of velocity is acceleration.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not the correct explanation of assertion
Option B (If both assertion and reason are true but reason is not the correct explanation of assertion) is correct because while both statements are true, the reason doesn't explain why the area under the acceleration-time graph gives the change in velocity.
280 Medium
280 of 285
Application +4 | -1
Two cars A and B at rest at same point initially. If A starts with uniform velocity of 40 m/sec and B starts in the same direction with constant acceleration of 4m/s24m/{s^2}, then B will catch A after how much time
View answer and explanation
Correct option: B
20 sec
Option B (20 sec) is correct because the time is calculated by equating the distances traveled by both cars when B catches A.
281 Medium
281 of 285
Analyzing +4 | -1
I. Particle-1 is dropped from a tower and particle-2 is projected horizontal from the same tower, then both the particles reach the ground simultaneously.

II. Both the particles strike the ground with different speeds.

Which of the following statement(s) is/are correct?
View answer and explanation
Correct option: C
Both I and II
Option C is correct. Both particles reach the ground simultaneously because vertical motion is independent of horizontal motion, and they strike with different speeds due to the horizontal velocity component of particle-2.
282 Medium
282 of 285
Application +4 | -1
A particle moves along a straight line such that its displacement at any time t is given by S=t3−6t2+3t+4S = {t^3} - 6{t^2} + 3t + 4 metres. The velocity when the acceleration is zero is
View answer and explanation
Correct option: B
−9ms−1- 9m{s^{ - 1}}
Option B (-9 m/s⁻¹) is correct because it's the velocity calculated at the time when the acceleration is zero, found by differentiating the displacement function twice.
283 Medium
283 of 285
Application +4 | -1
A moving car possesses average velocities of 5 m/s, 10 m/s and 15 m/s. In the first, second and third seconds respectively. Then the total distance covered by the car in these 3 seconds is
View answer and explanation
Correct option: B
30 m
Option B (30 m) is correct because it's the sum of the distances covered in each second, calculated using the average velocities.
284 Medium
284 of 285
Application +4 | -1
A particle is thrown vertically up with an initial velocity 9 m/s9 \mathrm{~m} / \mathrm{s} from the surface of Earth (take g=10 m/s2g=10 \mathrm{~m} / \mathrm{s}^2). The time (in seconds) taken by the particle to reach a height of 4 m4 \mathrm{~m} from the surface second time (in seconds) is
View answer and explanation
Correct option: D
1.01.0
Option D (1.01.0) is correct because it is one of the two possible times when the particle reaches the specified height, and it is the second time.
285 Medium
285 of 285
Understanding +4 | -1
A particle is constrained to move on a straight line path. It returns to the starting point after 10 s10 \mathrm{~s}. The total distance covered by the particle during this time is 30 m30 \mathrm{~m}. Which of the following statements about the motion of the particle is true?
View answer and explanation
Correct option: D
Both (1) and (2)
Option D (Both (1) and (2)) is correct because the displacement is zero as the particle returns to the starting point, and the average speed is calculated as total distance/total time, which is 3 m/s.
Revision notes and key takeaways

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