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JEE PHYSICS MCQ: MOTION IN A STRAIGHT LINE

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Application +4 | -1
A particle moves along a straight line such that its displacement at any time tt given by

s=(t42−12t2)ms=\left(\frac{t^4}{2}-12 t^2\right) m

The velocity when the acceleration becomes zero is
View answer and explanation
Correct option: D
–32 m/sec
Option D (–32 m/sec) is correct because it's the velocity calculated when the acceleration is set to zero.

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