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JEE • PHYSICS • MOTION IN A STRAIGHT LINE

Motion in a straight line practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 1-30 of 285 questions
1 Medium
1 of 285
Analyzing +4 | -1
Assertion: In a free fall, the initial velocity of a body may not be zero.
Reason: Free fall means the vertical acceleration of the body is equal to g\mathrm{g}.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because free fall is defined by the vertical acceleration being equal to g, and this allows for an initial non-zero velocity.
2 Medium
2 of 285
Remembering +4 | -1
Which of the following is not a derived quantites?
View answer and explanation
Correct option: D
Time
Option D (Time) is correct because time is a base quantity, while the others are derived quantities.
3 Medium
3 of 285
Analyzing +4 | -1
Assertion: If a body is dropped from the top of a tower of height h\mathrm{h} and another body is thrown up simultaneously with velocity u\mathrm{u} from the foot of the tower, then both of them would meet after a time hu\frac{\mathrm{h}}{\mathrm{u}}.
Reason: For a body projected upwards, the distance covered by the body in the last second of its upward journey is always 4.9 m4.9 \mathrm{~m} irrespective of velocity of projection. (g=9.8 m/s2)(\mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^2)
View answer and explanation
Correct option: B
If both Assertion & reason are True but Reason is not a correct explanation of the Assertion
Option B (If both Assertion & reason are True but Reason is not a correct explanation of the Assertion) is correct because both statements are true, but the reason doesn't explain the assertion.
4 Medium
4 of 285
Application +4 | -1
A particle is having uniform acceleration. If its displacement from tt to (t+1)(t+1) second is 120 m120 \mathrm{~m} and change in velocity is 50 m/s50 \mathrm{~m} / \mathrm{s}. Find its displacement (in m\mathrm{m}) in (t+2)(t+2) second.
View answer and explanation
Correct option: A
170
Option A (170) is correct because it calculates the displacement in the (t+2)th second using the given acceleration and change in velocity.
5 Medium
5 of 285
Application +4 | -1
An aeroplane flies 400m north and 300m south and then flies 1200m upwards, then net displacement is
View answer and explanation
Correct option: D
1200m
Option D (1200m) is correct because the net displacement is found by vector addition of the north-south and upward displacements.
6 Medium
6 of 285
Application +4 | -1
A ball thrown up is caught by the thrower after 4 s4 \mathrm{~s}. How high did it go and with what velocity was it thrown?
View answer and explanation
Correct option: A
(i) 19.6 m;19.6 \mathrm{~m}; (ii) 19.6 ms−119.6 \mathrm{~ms}^{-1}
Option A ((i) 19.6 m;19.6 \mathrm{~m}; (ii) 19.6 ms−119.6 \mathrm{~ms}^{-1}) is correct because it calculates the maximum height and initial velocity using kinematic equations.
7 Medium
7 of 285
Understanding +4 | -1
Check up the only correct statement in the following
View answer and explanation
Correct option: B
A body has a constant speed but it can have a varying velocity
Option B is correct because a body can have constant speed while its velocity changes due to a change in direction, implying acceleration.
8 Medium
8 of 285
Application +4 | -1
The distance travelled by a particle starting from rest and moving with an acceleration 43 m/s2\frac{4}{3}\,m/{s^2}, in the third second is
View answer and explanation
Correct option: A
10/3 m
Option A (10/3 m) is correct because it uses the formula for distance traveled in the nth second, substituting the given acceleration and n=3.
9 Medium
9 of 285
Analyzing +4 | -1
In one dimensional motion, instantaneous speed vv satisfies 0≤v<v00 \leq v < v_0.
View answer and explanation
Correct option: B
The displacement xx in time TT satisfies
−v0T<x<v0T-v_0 T < x < v_0 T
Option B is correct. The displacement x in time T satisfies −v0T<x<v0T-v_0 T < x < v_0 T because the maximum distance covered is v0Tv_0T in either direction.
10 Medium
10 of 285
Application +4 | -1
A body movies with an initial velocity 10  ms−110\,\,m{s^{ - 1}}. . If it covers a distance of 20 m in 2S, then acceleration of the body is
View answer and explanation
Correct option: A
Zero
Option A (Zero) is correct because the acceleration is zero, implying constant velocity, when the distance covered is consistent with the initial velocity and time.
11 Medium
11 of 285
Application +4 | -1
Position of a particle moving along xx-axis is given by x=6t−3t2x=6 t-3 t^2, where xx is in m\mathrm{m} and tt is in s. Time (t)(t) at which particle will momentarily come to rest is
View answer and explanation
Correct option: C
1 s1 \mathrm{~s}
Option C (1 s1 \mathrm{~s}) is correct because it is the time when the velocity, calculated as the derivative of the position function, equals zero.
12 Medium
12 of 285
Understanding +4 | -1
Assertion: Distance is the actual length of the path but magnitude of displacement is the shortest distance between initial and final positions.
Reason: Distance is a scalar quantity and it is always positive or zero but displacement is a vector quantity. It may be positive, negative or zero.
View answer and explanation
Correct option: B
If both Assertion & reason are True but Reason is not a correct explanation of the Assertion
Option B (If both Assertion & reason are True but Reason is not a correct explanation of the Assertion) is correct because while both statements are true, the scalar/vector nature doesn't directly explain the path length difference.
13 Medium
13 of 285
Application +4 | -1
An object moving with a speed of 6.25 m/s, is decelerated at a rate given by dvdt=2.5  v\frac{{dv}}{{dt}} = 2.5\;\sqrt v where v is the instantaneous speed. The time taken by the object, to come to rest would be
View answer and explanation
Correct option: B
2s
Option B (2s) is correct because it is the time calculated by integrating the given deceleration equation.
14 Medium
14 of 285
Understanding +4 | -1
Area under velocity-time curve over a given interval of time represents
View answer and explanation
Correct option: D
Displacement
Option D is correct because the area under a velocity-time curve represents the displacement of the object.
15 Medium
15 of 285
Understanding +4 | -1
Curved lines in velocity-time graph for a particle in a given interval of time implies
View answer and explanation
Correct option: D
Non-uniform acceleration
Option D (Non-uniform acceleration) is correct because a curved line on a velocity-time graph indicates that the velocity is changing at a non-constant rate, which means the acceleration is not uniform.

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16 Medium
16 of 285
Understanding +4 | -1
Consider the motion of the tip of the minutes hand of a clock. In one hour
I. The displacement is zero
II. The distance covered is zero
III. The average speed is zero
IV. The average velocity is zero
View answer and explanation
Correct option: C
A and D are correct
Option C is correct because in one hour, the minute hand completes a full circle, resulting in zero displacement and zero average velocity, but non-zero distance and average speed.
17 Medium
17 of 285
Analyzing +4 | -1
A particle moves as such whose acceleration is given by a=3sin⁡4ta=3 \sin 4 t, then
View answer and explanation
Correct option: B
the acceleration of the particle becomes zero after each interval of π4\frac{\pi}{4} second.
Option B is correct because the acceleration becomes zero when sin⁡4t=0\sin 4t = 0, which occurs at intervals of π4\frac{\pi}{4} seconds.
18 Medium
18 of 285
Understanding +4 | -1
A particle moves along a straight line path. Its speed decreases continuously and after some time it comes to rest. The motion is with constant acceleration whose direction with respect to the direction of velocity is
View answer and explanation
Correct option: B
Negative throughout motion
Option B (Negative throughout motion) is correct because if the speed is decreasing, the acceleration must be in the opposite direction to the velocity.
19 Medium
19 of 285
Understanding +4 | -1
A ball thrown vertically upwards after reaching a maximum height h, returns to the starting point after a time of l0 s. Its displacement is
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because displacement is the change in position, and since the ball returns to the starting point, the displacement is zero.
20 Medium
20 of 285
Application +4 | -1
A bullet moving with a velocity of 200 cm/s penetrates a wooden block and comes to rest after traversing 4cm inside it. What velocity is needed for travelling distance of 9cm in same block
View answer and explanation
Correct option: C
300 cm/s
Option C (300 cm/s) is correct because the velocity required for the bullet to travel 9cm is calculated using the relationship between initial velocity and distance traveled before coming to rest.
21 Medium
21 of 285
Application +4 | -1
An object is moving along +ve xx-axis with a uniform acceleration of 4 ms−24 \mathrm{~ms}^{-2}. At time t=0,x=5 mt=0, x=5 \mathrm{~m} and v=3 ms−1.v=3 \mathrm{~ms}^{-1}. What will be the position of the object when it has a velocity of 5 ms−1?5 \mathrm{~ms}^{-1}?
View answer and explanation
Correct option: A
7 m7 \mathrm{~m}
Option A (7 m7 \mathrm{~m}) is correct because it is calculated using the kinematic equation relating displacement, initial velocity, final velocity, and acceleration.
22 Medium
22 of 285
Application +4 | -1
A body of mass 500 g is thrown upward with a velocity 20 ms and reaches back to the surface of a planet after 20 sec then the weight of the body on that planet is
View answer and explanation
Correct option: A
2 N
Option A (2 N) is correct because it is the weight of the body calculated using the acceleration due to gravity on that planet.
23 Medium
23 of 285
Application +4 | -1
A cricket ball is thrown up with a speed of 19.6  ms−119.6\;m{s^{ - 1}}. The maximum height it can reach is
View answer and explanation
Correct option: B
19.6 m
Option B (19.6 m) is correct because the maximum height is calculated using the kinematic equation Hmax=u22g{H_{\mathrm{max}}} = \frac{{{u^2}}}{{2g}}.
24 Medium
24 of 285
Understanding +4 | -1
Assertion: The average and instantaneous velocity in a uniform motion are always equal.
Reason: In a uniform motion, velocity remains constant.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion.
Option A (If both assertion and reason are true and reason is the correct explanation of the assertion) is correct because in uniform motion, velocity is constant, which means the average and instantaneous velocities are always equal.
25 Medium
25 of 285
Understanding +4 | -1
Assertion: The displacement of an object in a given time interval is always positive.

Reason: Displacement is a vector quantity and a vector is always positive.
View answer and explanation
Correct option: D
If both assertion and reason are false.
Option D is correct. Displacement can be positive, negative, or zero depending on the direction of motion, and vectors can also be negative depending on the coordinate system.
26 Medium
26 of 285
Analyzing +4 | -1
Assertion: A bus moving due north takes a turn and starts moving towards east with same speed. There will be no change in the velocity of bus.

Reason: Velocity is a vector-quantity.
View answer and explanation
Correct option: D
If assertion is false but reason is true
Option D (If assertion is false but reason is true) is correct because velocity is a vector quantity, and a change in direction implies a change in velocity.
27 Medium
27 of 285
Analyzing +4 | -1
In a race for 100m dash, the first and the second runners have a gap of one metre at the mid way stage. Assuming the first runner goes steady, by what percentage should the second runner increases his speed just to win the race.
View answer and explanation
Correct option: C
More than 4%4\%
Option C (More than 4%) is correct because the second runner needs to increase his speed by approximately 4.1% to win, which is more than 4%.
28 Medium
28 of 285
Understanding +4 | -1
Speed is in general _____ in magnitude than that of the velocity.
View answer and explanation
Correct option: B
Greater or equal
Option B (Greater or equal) is correct because speed is the magnitude of velocity, and it can be equal to or greater than the magnitude of the velocity.
29 Medium
29 of 285
Application +4 | -1
A body starts from rest, the ratio of distances travelled by the body during 3rd 3^{\text {rd }} and 4th 4^{\text {th }} second is:
View answer and explanation
Correct option: D
5/75 / 7
Option D (5/75 / 7) is correct because the ratio of distances travelled during the 3rd and 4th seconds is calculated using the formula Sn=u+12a(2n−1)S_n = u + \frac{1}{2}a(2n-1).
30 Medium
30 of 285
Analyzing +4 | -1
Assertion: A negative acceleration of a body can be associated with a ‘speeding up’ of the body.

Reason: Increase in speed of a moving body is independent of its direction of motion.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not the correct explanation of the assertion.
Option B is correct because both the assertion and reason are true, but the reason does not correctly explain the assertion. A negative acceleration can indeed be associated with speeding up, but the reason provided is not the direct cause.
Revision notes and key takeaways

Review MOTION IN A STRAIGHT LINE in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

  • ✓ This set contains 285 single-correct-answer MCQs on MOTION IN A STRAIGHT LINE.
  • ✓ Try each question before opening its answer. Read the explanation where one is available.
  • ✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.
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