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JEE PHYSICS MCQ: MOTION IN A STRAIGHT LINE

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An object moving with a speed of 6.25 m/s, is decelerated at a rate given by dvdt=2.5  v\frac{{dv}}{{dt}} = 2.5\;\sqrt v where v is the instantaneous speed. The time taken by the object, to come to rest would be
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Correct option: B
2s
Option B (2s) is correct because it is the time calculated by integrating the given deceleration equation.

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