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JEE • PHYSICS • MOTION IN A STRAIGHT LINE

Motion in a straight line practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 241-270 of 333 questions

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241 Medium
241 of 333
Application +4 | -1
A car travels along a straight line for the first half time with speed 50 kmh−150 \mathrm{~kmh}^{-1} and the second half time with speed 60 kmh−1.60 \mathrm{~kmh}^{-1}. Find the average speed of the car.
View answer and explanation
Correct option: A
55 kmh−155 \mathrm{~kmh}^{-1}
Option A (55 kmh−155 \mathrm{~kmh}^{-1}) is correct because the average speed is calculated by dividing the total distance by the total time, considering the different speeds for each half of the time.
242 Medium
242 of 333
Application +4 | -1
The driver of an express train moving with a velocity v1{v_1} finds that a goods train is moving with a velocity v2{v_2} in the same direction on the same track. He applies the brakes and produces a retardation a. The minimum time required to avoid collision is
View answer and explanation
Correct option: A
v1−v2a\frac{{{v_1} - {v_2}}}{a}
Option A (v1−v2a\frac{{{v_1} - {v_2}}}{a}) is correct because it represents the time required for the express train to decelerate to the speed of the goods train.
243 Medium
243 of 333
Application +4 | -1
If a body having initial velocity zero is moving with uniform acceleration 8 m/sec28 \mathrm{~m} / \mathrm{sec}^2, the distance travelled by it in fifth second will be
View answer and explanation
Correct option: A
36 metres
Option A (36 metres) is correct because it is calculated using the formula for distance travelled in the nth second with uniform acceleration.
244 Medium
244 of 333
Analyzing +4 | -1
The relation between acceleration and velocity for a body moving in straight line is a∝v3a \propto v^3. Choose incorrect option. (xx is position and tt is time)
View answer and explanation
Correct option: D
x∝1v2x \propto \frac{1}{v^2}
The incorrect option is D (x∝1v2x \propto \frac{{1}}{{v^2}}) because the correct relation derived from a∝v3a \propto v^3 is x∝tx \propto \sqrt{{t}} and v∝1tv \propto \frac{{1}}{{\sqrt{{t}}}} which implies x∝v−2x \propto v^{-2} is incorrect.
245 Medium
245 of 333
Analyzing +4 | -1
Assertion: If two particles, moving with constant velocities are to meet, the relative velocity must be along the line joining the two particles.
Reason: Relative velocity means motion of one particle as viewed by the other.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because the relative velocity must be along the line joining the two particles for them to meet, and relative velocity is indeed the motion of one particle as viewed by the other.
246 Medium
246 of 333
Application +4 | -1
Two balls AA and BB are placed at the top of 180 m180 \mathrm{~m} tall tower. Ball AA is released from the top at t=0 st=0 \mathrm{~s}. Ball BB is thrown vertically down with an initial velocity uu at t=2 st=2 \mathrm{~s}. After a certain time, both balls meet 100 m100 \mathrm{~m} above the ground. Find the value of uu in ms−1\mathrm{ms}^{-1} [use g=10 ms−2g=10 \mathrm{~ms}^{-2} ]
View answer and explanation
Correct option: D
30
Option D (30) is correct because it is calculated by equating the distances traveled by both balls and solving for the initial velocity uu of ball B.
247 Medium
247 of 333
Application +4 | -1
A train 175 m175 \mathrm{~m} long crosses a bridge which is 225 m225 \mathrm{~m} long in 80 seconds. What is the speed of the train?
View answer and explanation
Correct option: A
5 m/sec5 \mathrm{~m} / \mathrm{sec}
Option A (5 m/sec5 \mathrm{~m} / \mathrm{sec}) is correct because the speed is calculated by dividing the total distance (train length + bridge length) by the time taken.
248 Medium
248 of 333
Analyzing +4 | -1
The motion of a particle moving along yy-axis is represented as y=3(t−2)+5(t−2)2.y=3(t-2)+5(t-2)^2. Identify the correct statement.
View answer and explanation
Correct option: C
The particle is at the origin at t=2 st=2 \mathrm{~s}
Option C is correct. The particle is at the origin at t=2s because substituting t=2 into the equation gives y=0.
249 Medium
249 of 333
Understanding +4 | -1
A graph is drawn between velocity and time for the motion of a particle. The area under the curve between the time intervals t1 and  t2{t_1}\,and\,\,{t_2} gives
View answer and explanation
Correct option: B
Displacement of the particle
Option B (Displacement of the particle) is correct because the area under a velocity-time graph represents the displacement of the particle.
250 Medium
250 of 333
Analyzing +4 | -1
Assertion (A) : A body is dropped from height hh and another body is thrown vertically upwards with a speed gh\sqrt{g h}. They meet at height h/2h / 2.

Reason (R) : The time taken by both the blocks in reaching the height h/2h / 2 is same.
View answer and explanation
Correct option: A
If both Assertion and Reason are true and the Reason is correct explanation of the Assertion.
The correct answer is A because both the Assertion and Reason are true, and the Reason is the correct explanation of the Assertion. Both objects reach h/2 in the same time.
251 Medium
251 of 333
Application +4 | -1
The displacement of a particle starting from rest (at t=0) is given by s=6t2−t3.s = 6{t^2} - {t^3}.. The time in seconds at which the particle will attain zero velocity again, is
View answer and explanation
Correct option: B
4
Option B (4) is correct because the velocity is zero when the derivative of the displacement function equals zero, which occurs at t=4 seconds.
252 Medium
252 of 333
Analyzing +4 | -1
A body starts from rest and travels a distance S with uniform acceleration, then moves uniformly a distance 2 S uniformly, and finally comes to gest after moving further 5 S under uniform retardation. The ratio of average velocity to maximum velocity is
View answer and explanation
Correct option: C
47\frac{4}{7}
Option C (47\frac{4}{7}) is correct because it represents the ratio of average velocity to maximum velocity, calculated using the distances and velocities during different phases of motion.
253 Medium
253 of 333
Application +4 | -1
Two trains 121 m121 \mathrm{~m} and 99 m99 \mathrm{~m} in lengths are running in opposite directions with velocities 40 km/h40 \mathrm{~km} / \mathrm{h} and 32 km/h32 \mathrm{~km} / \mathrm{h}. In what time they will completely cross each other?
View answer and explanation
Correct option: B
11 sec
Option B (11 sec) is correct because it correctly calculates the relative velocity and the total distance to find the time taken to cross each other.
254 Easy
254 of 333
Application +4 | -1
The displacement of particle is given by y=2+3t+8t2−6t4  my = 2 + 3t + 8{t^2} - 6{t^4}\,\,{\text{m}} then initial velocity is given by (m/s)
View answer and explanation
Correct option: C
3
Option C (3) is correct because the initial velocity is the derivative of the displacement equation evaluated at t=0.
255 Medium
255 of 333
Application +4 | -1
A person travels along a straight road for the first half time with a velocity v1v_1 and the second half time with a velocity v2v_2. Then the mean velocity vˉ\bar{v} is given by
View answer and explanation
Correct option: A
vˉ=v1+v22\bar{v}=\frac{v_1+v_2}{2}
Option A (vˉ=v1+v22\bar{v}=\frac{v_1+v_2}{2}) is correct because the average velocity is calculated as the arithmetic mean of the two velocities when the time intervals are equal.
256 Medium
256 of 333
Application +4 | -1
A bus starts from rest and moves along a straight road with constant acceleration ff until its speed is vv. The bus then continues with constant speed vv. When the bus starts, a car is at a distance bb behind the bus and is moving with constant speed uu in same direction as that of bus. Find the distance between the car and the bus at time tt after the bus started.

(Given 0<t<vf0 < t < \frac{v}{f} and u2<2fbu^2 < 2 f b).
View answer and explanation
Correct option: A
b−ut+ft22b-u t+\frac{f t^2}{2}
Option A (b−ut+ft22b-u t+\frac{f t^2}{2}) is correct because it represents the difference between the initial distance, the distance covered by the car, and the distance covered by the bus with constant acceleration.
257 Medium
257 of 333
Application +4 | -1
A body is moving with uniform velocity of 8 ms−18 \mathrm{~ms}^{-1}. When the body just crossed another body, the second one starts and moves with uniform acceleration of 4 ms−24 \mathrm{~ms}^{-2}. The time after which two bodies meet, will be
View answer and explanation
Correct option: B
4 s4 \mathrm{~s}
Option B (4 s4 \mathrm{~s}) is correct because the time is calculated by equating the displacements of both bodies.
258 Medium
258 of 333
Application +4 | -1
A train is moving with a velocity of 30 ms−130 \mathrm{~ms}^{-1}. When brakes are applied, it is found that the velocity reduced to 10 ms−110 \mathrm{~ms}^{-1} in 240 m240 \mathrm{~m}. When the velocity of the train is zero, the distance travelled is
View answer and explanation
Correct option: D
270 m270 \mathrm{~m}
Option D (270 m270 \mathrm{~m}) is correct because it is calculated by first finding the deceleration and then using it to find the total distance traveled.
259 Medium
259 of 333
Application +4 | -1
A train started from rest from a station and accelerated at 2 ms−22\,m{s^{ - 2}} for 10sec. Then it travels at constant speed for 30 sec and there after it decelerated at 4 ms−24\,m{s^{ - 2}} until it stopped at the next station. The distance between two stations is
View answer and explanation
Correct option: C
750 m
Option C (750 m) is correct because it is the total distance calculated by summing the distances traveled during acceleration, constant speed, and deceleration.
260 Medium
260 of 333
Application +4 | -1
A ball which is at rest is dropped from a height h metre. As it bounces off the floor its speed is 80% of what it was just before touching the ground. The ball then rise to nearly a height
View answer and explanation
Correct option: D
0.64 h
Option D (0.64 h) is correct because the height reached after bouncing is proportional to the square of the velocity, which is 80% of the initial velocity.
261 Medium
261 of 333
Understanding +4 | -1
Two stones of equal masses are dropped from a rooftop of height h one after another. Their separation distance against time will
View answer and explanation
Correct option: B
Increase
Option B is correct because the separation distance increases with time due to the constant acceleration of gravity.
262 Medium
262 of 333
Analyzing +4 | -1
Assertion(A): Average velocity can't be zero in case of uniform acceleration.

Reason (R): For average velocity to be zero, a non zero velocity should not remain constant.
View answer and explanation
Correct option: D
If Assertion is false but the Reason is true.
Option D (If Assertion is false but the Reason is true) is correct because average velocity can be zero even with uniform acceleration (e.g., projectile motion), and the reason correctly states the condition for zero average velocity.
263 Medium
263 of 333
Analyzing +4 | -1
Assertion: In one-dimensional motion of an object, path length comes out to be equal to displacement.
Reason: Direction of object is changed two times.
View answer and explanation
Correct option: C
If assertion is true but reason is false
Option C (If assertion is true but reason is false) is correct because in one-dimensional motion, path length equals displacement only if the direction doesn't change.
264 Easy
264 of 333
Understanding +4 | -1
A body is thrown vertically upwards with a velocity u. Find the true statement from the following
View answer and explanation
Correct option: D
Velocity is zero at the highest point and maximum height reached is u2/2g{u^2}/2g
Option D is correct because at the highest point, the velocity is momentarily zero, and the maximum height is given by u2/2g{u^2}/2g based on kinematic equations.
265 Hard
265 of 333
Analyzing +4 | -1
The distance x covered by a particle in one-dimensional motion varies with time t as x2=at2+2bt+c{x^2} = a{t^2} + 2bt + c. The accelerating of the particle varies as
View answer and explanation
Correct option: A
x−3{x^{ - 3}}
Option A (x−3{x^{ - 3}}) is correct. By differentiating the given equation twice with respect to time, the acceleration is found to be inversely proportional to x cubed.
266 Medium
266 of 333
Analyzing +4 | -1
Assertion: An object may have varying speed without having varying velocity.
Reason: If the velocity is zero at an instant, the acceleration may not be zero at that instant.
View answer and explanation
Correct option: D
If Assertion is false but Reason is true.
Option D (If Assertion is false but Reason is true) is correct because the assertion is false, while the reason is true.
267 Medium
267 of 333
Understanding +4 | -1
Assertion: For a moving object the instantaneous velocity is calculated by the limiting value of its average velocity as the time interval approaches to zero.
Reason: The direction of the average velocity is same as the direction of displacement.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not the correct explanation of assertion
Option B is correct because both the assertion and reason are true, but the reason doesn't explain why the instantaneous velocity is the limit of the average velocity.
268 Medium
268 of 333
Understanding +4 | -1
Assertion: For an object in uniform motion, the position-time graph is a straight line inclined to the time-axis.

Reason: In a uniform motion, the acceleration is zero.
View answer and explanation
Correct option: B
If both assertion and reason are true, but reason is not correct explanation of the assertion.
Option B is correct because both the assertion and the reason are true, but the reason (zero acceleration) doesn't directly explain why the position-time graph is a straight line; the constant velocity is the direct cause.
269 Medium
269 of 333
Application +4 | -1
A particle starts from the origin of coordinates at time t=0 and moves in the x-y plane with a constant acceleration&nbsp;α\alpha in the y-diretion. Its equation of motion is y=βx2y = \mathrm{\beta }{x^2}. Its velocity component in the x-direction is
View answer and explanation
Correct option: D
α2β\sqrt {\frac{\mathrm{\alpha }}{{2\mathrm{\beta }}}}
Option D (α2β\sqrt {\frac{{\alpha }}{{2\mathrm{\beta }}}}) is correct because the velocity component in the x-direction is constant and can be derived from the given equations of motion.
270 Medium
270 of 333
Analyzing +4 | -1
A particle moves in a straight line, so that after tt second the distance xx from a fixed point OO on the line is given by x=(t−2)2(t−5)x=(t-2)^2(t-5). Then
View answer and explanation
Correct option: C
the acceleration is negative when t<3 st<3 \mathrm{~s}.
Option C (the acceleration is negative when t<3 s) is correct because the second derivative of the position function is negative for t<3.
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